String split based on condition - sql-server

Question

I have few string with numbers like this; and its around 3000 records.
Column
------------
Cell 233567-3455
Cell123-4567
Cell#123-7449
Local 456-0987
1 616 468-7796
1234567-5x2345
234/625-1234
(C)755-7442
5732878-2
5721899-23
6712909-3
7894200-234
2144-57238
5673893/588218
437-4737-5772
How can i find the records like below:
Column
-------------
5732878-2
5721899-23
6712909-3
7894200-234
Once I find this, I need to split those into two parts
1st Column. | 2nd column
------------- |
5732878 | 5732872
5721899 | 5721823
6712909 | 6712903
7894200 | 7894234
I tried to fix This using PARINDEX and CHARINDEX
But somehow its not working.Please help.

Answer 1

I don't know your filtering logic to get to your intermediate set, but this should get your expected final result set. I assumed you only want records where the length of the string to the left of the hyphen is greater than the length on the right and also exclude records with more than 1 hyphen.
SELECT LEFT(telephone, CHARINDEX('-', telephone)-1) AS [1stTelephone],
STUFF(
--get the string before the hyphen
LEFT(telephone, CHARINDEX('-', telephone)-1),
--get the starting location of chars we are going to replace
LEN(LEFT(telephone, CHARINDEX('-', telephone)))-LEN(RIGHT(telephone, CHARINDEX('-', REVERSE(telephone))-1)),
--get the length of the section we are replacing
LEN(RIGHT(telephone, CHARINDEX('-', REVERSE(telephone))-1)),
--replace that section with the string after the hyphen
RIGHT(telephone, CHARINDEX('-', REVERSE(telephone))-1)
) AS [2nd telephone]
FROM your_table
WHERE LEN(LEFT(telephone, CHARINDEX('-', telephone))) > LEN(RIGHT(telephone, CHARINDEX('-', REVERSE(telephone))))
AND len(telephone) - len(REPLACE(telephone, '-', '')) = 1

Answer 2

Somewhat dirty method (looks specifically for 7 digits followed by hyphen followed by any number of digits):
SELECT BasePhone AS Phone1, LEFT(BasePhone, 7-LEN(OtherPhoneEnd)) + OtherPhoneEnd AS Phone2
FROM (
SELECT LEFT(Telephone, 7) AS BasePhone, SUBSTRING(Telephone,9,7) AS OtherPhoneEnd
FROM Telephones
WHERE Telephone LIKE '[0-9][0-9][0-9][0-9][0-9][0-9][0-9]-%'
)

Answer 3

I assumed based on information you given, that you want numbers with hyphen (-) at 8th position. Try this:
create table #TelNo (
Tel varchar(30)
)
insert #TelNo(Tel)
values ('5732878-2'),
('5721899-23'),
('6712909-3'),
('7894200-234'),
('2144-57238'),
('5673893/588218'),
('437-4737-5772')
select Tel, LEFT(Tel, Len(tel) - len(suffix)) + suffix [SecondTel] from (
select substring(Tel, 1, 7) [Tel], substring(Tel, 9, 10) [suffix] from #TelNo
where CHARINDEX('-', Tel) = 8
)a

Answer 4

You could use something like this:
DDL
use tempdb
create table TelNo (
Tel varchar(30)
)
insert TelNo(Tel)
values ('5732878-2'),
('5721899-23'),
('6712909-3'),
('7894200-234'),
('2144-57238'),
('5673893/588218'),
('437-4737-5772')
Code
select Tel,
case
when Tel like '%_-[0-9]' then left(Tel, len(Tel)-2)
when Tel like '%__-[0-9][0-9]' then left(Tel, len(Tel)-3)
when Tel like '%___-[0-9][0-9][0-9]' then left(Tel, len(Tel)-4)
else Tel
end Tel1,
case
when Tel like '%_-[0-9]' then left(Tel, len(Tel)-3) + right(Tel, 1)
when Tel like '%__-[0-9][0-9]' then left(Tel, len(Tel)-5) + right(Tel, 2)
when Tel like '%___-[0-9][0-9][0-9]' then left(Tel, len(Tel)-7) + right(Tel, 3)
else NULL
end Tel2
from TelNo