When String Contains Elements From Arrays In Order - arrays

Question

How do you make the console print true when the variable "message" contains an element from each array in order: "greetings" then "colour" then "names", but any words before "greetings" and after "colour" still prints true.
If the elements are out of order it should print false.
If there are words in-between the elements it should print false.
Check examples below current code.
Current Code:
var message = '';
var greetings = 'hi' || 'hello' || 'hey';
var colour = 'red' || 'green' || 'blue';
var names = 'john' || 'evan' || 'etienne';
if (message.includes(greetings + ' ' + colour + ' ' + names)) {
console.log(true);
} else {
console.log(false);
}
Examples of what it should print when message:
message = 'hi green evan' //true
message = 'lol hey blue john' //true
message = 'hello green etienne! xD' //true
message = 'evan green hi' //false because wrong element order
message = 'hi very green evan' //false because word in-between elements

Answer 1

You can use regex for this.
var message = "hello green etienne! xD";
var greetings = ["hi", "hello", "hey"].join("|");
var colors = ["red", "green", "blue"].join("|");
var names = ["john", "evan", "etienne"].join("|");
var reg = new RegExp("^.*(" + greetings + ")\\s+.*(" + colors + ")\\s+(" + names + ").*$");
console.log(reg.test(message));

Answer 2

var message = 'hi green evan';
var greetings = ["hi","hello","hey"];
var colour = ['red','green','blue'];
var names = ['john','evan','etienne'];
var contained = false;
greetings.some(x =>{
colour.some(z=>{
names.some(e=>{
if(message.includes(x + ' ' + z + ' ' + e)){
contained = true;
alert(true);
}
});
});
});
if(!contained)
alert(false);
You could do it like this. Probably not the best way to do it but the first thing that came to my mind