I'm trying to transpose a dataset however i'm getting the attached result in my table. I'm creating thee extra repeated rows but I'm not sure how to summarize my data so that there are only unique "test" labels and no blank GLH values SASresult
array leaners{*} Learners1-Learners3;
do index = 1 to dim(leaners);
ind = index;
test = leaners{index};
output;
end;
array GLH{*} TotalGLHYear1-TotalGLHYear3;
do index = 1 to dim(GLH);
ind = index;
GLHall = GLH{index};
output;
end;
keep Region test GLHall;
Option 1: You can save the distinct rows to a new table using proc sql:
proc sql;
create table work.want as
select distinct(*) from work.have ;
quit;
Option 2: You can remove duplicates from your table using proc sort:
proc sort data=work.have noduprecs;
by _all_ ; Run;
Related
I am working with a table with more than 50 columns. I am trying to replace the value of multiple columns using a lookup table.
Table:
data have;
infile datalines delimiter=",";
input ID $1. SUB_ID :$2. COUNTRY :$2. A $1. B $1.;
datalines;
1,A,FR,A,B
2,B,CH,,B
3,C,DE,B,A
4,D,CZ,,B
5,E,GE,A,
6,F,EN,B,
7,G,US,,A
;
run;
Lookup table:
data lookup;
infile datalines delimiter=",";
input value_before $1. value_after :$2.;
datalines;
A,1
B,2
C,3
;
run;
Actual code:
data want;
if 0 then set lookup;
if _n_ = 1 then do;
declare hash lookup(dataset:'lookup');
lookup.defineKey('value_before');
lookup.defineData('value_after');
lookup.defineDone();
end;
set have;
if (lookup.find(key:A) = 0) then
A = value_after;
if (lookup.find(key:B) = 0) then
B = value_after;
/* ... */
/* if (lookup.find(key:Z) = 0) then
Z = value_after; */
drop value_before value_after;
run;
I guess this code would do the job if I would hardcode the 50 columns.
I wonder if there is a way to "apply" the hash.find() to all variables except the first three (ID, SUB_ID and Country) (maybe by indexing ?) without having to hardcode them or to use macros. For the sake of example I only computed 2 variables to replace the value (A and B) but there are more than 50 (with really different names and no pattern like var1,var2,...,varn).
In cases like this, I like to use proc sql and the dictionary table to fill in the column names for me to create an array. The below code will pull the variable names from dictionary.columns and save them as space-delimited into the macro variable varnames. We can feed this into an array and then use array logic to do the rest.
proc sql noprint;
select name
into :varnames separated by ' '
from dictionary.columns
where libname = 'WORK'
AND memname = 'HAVE'
AND name NOT IN('ID', 'SUB_ID', 'COUNTRY')
;
quit;
data want;
if 0 then set lookup;
if _n_ = 1 then do;
declare hash lookup(dataset:'lookup');
lookup.defineKey('value_before');
lookup.defineData('value_after');
lookup.defineDone();
end;
set have;
array vars[*] &varnames.;
do i = 1 to dim(vars);
if lookup.Find(key:vars[i])=0 then vars[i] = value_after;
end;
drop value_before value_after i;
run;
So I have a dataset with one primary key: unique_id and 1200 variables. This dataset is generated from a macro so the number of columns will not be fixed. I need to split this dataset into 4 or more datasets of 250 variables each, and each of these smaller datasets should contain the primary key so that I can merge them back later. Can somebody help me with either a sas function or a macro to solve this?
Thanks in advance.
A simple way to split a datasets in the way you request is to use a single data step with multiple output datasets where each one has a KEEP= dataset option listing the variables to keep. For example:
data split1(keep=Name Age Height) split2(keep=Name Sex Weight);
set sashelp.class;
run;
So you need to get the list of variables and group then into sets of 250 or less. Then you can use those groupings to generate code like above. Here is one method using PROC CONTENTS to get the list of variables and CALL EXECUTE() to generate the code.
I will use macro variables to hold the name of the input dataset, the key variable that needs to be kept on each dataset and maximum number of variables to keep in each dataset.
So for the example above those macro variable values would be:
%let ds=sashelp.class;
%let key=name;
%let nvars=2;
So use PROC CONTENTS to get the list of variable names:
proc contents data=&ds noprint out=contents; run;
Now run a data step to split them into groups and generate a member name to use for the new split dataset. Make sure not to include the KEY variable in the list of variables when counting.
data groups;
length group 8 memname $41 varnum 8 name $32 ;
group +1;
memname=cats('split',group);
do varnum=1 to &nvars while (not eof);
set contents(keep=name where=(upcase(name) ne %upcase("&key"))) end=eof;
output;
end;
run;
Now you can use that dataset to drive the generation of the code:
data _null_;
set groups end=eof;
by group;
if _n_=1 then call execute('data ');
if first.group then call execute(cats(memname,'(keep=&key'));
call execute(' '||trim(name));
if last.group then call execute(') ');
if eof then call execute(';set &ds;run;');
run;
Here are results from the SAS log:
NOTE: CALL EXECUTE generated line.
1 + data
2 + split1(keep=name
3 + Age
4 + Height
5 + )
6 + split2(keep=name
7 + Sex
8 + Weight
9 + )
10 + ;set sashelp.class;run;
NOTE: There were 19 observations read from the data set SASHELP.CLASS.
NOTE: The data set WORK.SPLIT1 has 19 observations and 3 variables.
NOTE: The data set WORK.SPLIT2 has 19 observations and 3 variables.
Just another way of doing it using macro variables:
/* Number of columns you want in each chunk */
%let vars_per_part = 250;
/* Get all the column names into a dataset */
proc contents data = have out=cols noprint;
run;
%macro split(part);
/* Split the columns into 250 chunks for each part and put it into a macro variable */
%let fobs = %eval((&part - 1)* &vars_per_part + 1);
%let obs = %eval(&part * &vars_per_part);
proc sql noprint;
select name into :cols separated by " " from cols (firstobs = &fobs obs = &obs) where name ~= "uniq_id";
quit;
/* Chunk up the data only keeping those varaibles and the uniq_id */
data want_part∂
set have (keep = &cols uniq_id);
run;
%mend;
/* Run this from 1 to whatever the increment required to cover all the columnns */
%split(1);
%split(2);
%split(3);
this is not a complete solution but some help to give you another insight into how to solve this. The previous solutions have relied much on proc contents and data step, but I would solve this using proc sql and dictionary.columns. And I would create a macro that would split the original file into as many parts as needed, 250 cols each. The steps roughly:
proc sql; create table as _colstemp as select * from dictionary.columns where library='your library' and memname = 'your table' and name ne 'your primary key'; quit;
Count the number of files needed somewhere along:
proc sql;
select ceil(count(*)/249) into :num_of_datasets from _colstemp;
select count(*) into :num_of_cols from _colstemp;
quit;
Then just loop over the original dataset like:
%do &_i = 1 %to &num_of_datasets
proc sql;
select name into :vars separated by ','
from _colstemp(firstobs=%eval((&_i. - 1)*249 + 1) obs = %eval(min(249,&num_of_cols. - &_i. * 249)) ;
quit;
proc sql;
create table split_&_i. as
select YOUR_PRIMARY_KEY, &vars from YOUR_ORIGINAL_TABLE;
quit;
%end;
Hopefully this gives you another idea. The solution is not tested, and may contain some pseudocode elements as it's written from my memory of doing things. Also this is void of macro declaration and much of parametrization one could do.. This would make the solution more general (parametrize your number of variables for each dataset, your primary key name, and your dataset names for example.
I'm trying to turn a correlation matrix into one long column vector such that I have the following structure
data want;
input _name1_$ _name2_$ _corr_;
datalines;
var1 var2 0.54
;
run;
I have the following code, which outputs name1 and corr; however, I'm struggling to get name2!
DATA TEMP_1
(DROP=I J);
ARRAY VAR[*] VAR1-VAR10;
DO I = 1 TO 10;
DO J = 1 TO 10;
VAR(J) = RANUNI(0);
END;
OUTPUT;
END;
RUN;
PROC CORR
DATA=TEMP_1
OUT=TEMP_CORR
(WHERE=(_NAME_ NE " ")
DROP=_TYPE_)
;
RUN;
PROC SORT DATA=TEMP_CORR; BY _NAME_; RUN;
PROC TRANSPOSE
DATA=TEMP_CORR
OUT=TEMP_CORR_T
;
BY _NAME_;
RUN;
Help is appreciated
You're close. You're running into a weird issue with the name variable because that becomes a variable out of PROC TRANSPOSE as well. If you rename it, you get what you want. I also list the variables explicitly and add some RENAME data set options to get what you likely want.
PROC TRANSPOSE
DATA=TEMP_CORR (rename=_name_ = Name1)
OUT=TEMP_CORR_T (rename = (_name_ = Name2 col1=corr))
;
by name1;
var var1-var10;
RUN;
Edit: If you don’t want duplicates you can add a WHERE to the OUT dataset.
PROC TRANSPOSE
DATA=TEMP_CORR (rename=_name_ = Name1)
OUT=TEMP_CORR_T (rename = (_name_ = Name2 col1=corr) where = name1 > name2)
;
by name1;
var var1-var10;
RUN;
Just an ARRAY with VNAME() function. To just output the upper triangle set lower bound of DO loop to _N_.
data want ;
length _name1_ _name2_ $32 _corr_ 8 ;
keep _name1_ _name2_ _corr_;
set corr;
where _type_ = 'CORR';
array x _numeric_;
_name1_=_name_;
do i=_n_ to dim(x);
_name2_ = vname(x(i));
_corr_ = x(i);
output;
end;
run;
I have a bunch of character variables which I need to sort out from a large dataset. The unwanted variables all have entries that are the same or are all missing (meaning I want to drop these from the dataset before processing the data further). The data sets are very large so this cannot be done manually, and I will be doing it a lot of times so I am trying to create a macro which will do just this. I have created a list macro variable with all character variables using the following code (The data for my part is different but I use the same sort of code):
data test;
input Obs ID Age;
datalines;
1 2 3
2 2 1
3 2 2
4 3 1
5 3 2
6 3 3
7 4 1
8 4 2
run;
proc contents
data = test
noprint
out = test_info(keep=name);
run;
proc sql noprint;
select name into : testvarlist separated by ' ' from test_info;
quit;
My idea is then to just use a data step to drop this list of variables from the original dataset. Now, the problem is that I need to loop over each variable, and determine if the observations for that variable are all the same or not. My idea is to create a macro that loops over all variables, and for each variable counts the occurrences of the entries. Since the length of this table is equal to the number of unique entries I know that the variable should be dropped if the table is of length 1. My attempt so far is the following code:
%macro ListScanner (org_list);
%local i next_name name_list;
%let name_list = &org_list;
%let i=1;
%do %while (%scan(&name_list, &i) ne );
%let next_name = %scan(&name_list, &i);
%put &next_name;
proc sql;
create table char_occurrences as
select &next_name, count(*) as numberofoccurrences
from &name_list group by &next_name;
select count(*) as countrec from char_occurrences;
quit;
%if countrec = 1 %then %do;
proc sql;
delete &next_name from &org_list;
quit;
%end;
%let i = %eval(&i + 1);
%end;
%mend;
%ListScanner(org_list = &testvarlist);
Though I get syntax errors, and with my real data I get other kinds of problems with not being able to read the data correctly but I am taking one step at a time. I am thinking that I might overcomplicate things so if anyone has an easier solution or can see what might be wrong to I would be very grateful.
There are many ways to do this posted around.
But let's just look at the issues you are having.
First for looping through your space delimited list of names it is easier to let the %do loop increment the index variable for you. Use the countw() function to find the upper bound.
%do i=1 %to %sysfunc(countw(&name_list,%str( )));
%let next_name = %scan(&name_list,&i,%str( ));
...
%end;
Second where is your input dataset in your SQL code? Add another parameter to your macro definition. Where to you want to write the dataset without the empty columns? So perhaps another parameter.
%macro ListScanner (dsname , out, name_list);
%local i next_name sep drop_list ;
Third you can use a single query to count all of variables at once. Just use count( distinct xxxx ) instead of group by.
proc sql noprint;
create table counts as
select
%let sep=;
%do i=1 %to %sysfunc(countw(&name_list,%str( )));
%let next_name = %scan(&name_list,&i,%str( ));
&sep. count(distinct &next_name) as &next_name
%let sep=,;
%end;
from &dsname
;
quit;
So this will get a dataset with one observation. You can use PROC TRANSPOSE to turn it into one observation per variable instead.
proc transpose data=counts out=counts_tall ;
var _all_;
run;
Now you can just query that table to find the names of the columns with 0 non-missing values.
proc sql noprint ;
select _name_ into :drop_list separated by ' '
from counts_tall
where col1=0
;
quit;
Now you can use the new DROP_LIST macro variable.
data &out ;
set &dsname ;
drop &drop_list;
run;
So now all that is left is to clean up after your self.
proc delete data=counts counts_tall ;
run;
%mend;
As far as your specific initial question, this is fairly straightforward. Assuming &testvarlist is your macro variable containing the variables you are interested in, and creating some test data in have:
%let testvarlist=x y z;
data have;
call streaminit(7);
do id = 1 to 1e6;
x = floor(rand('Uniform')*10);
y = floor(rand('Uniform')*10);
z = floor(rand('Uniform')*10);
if x=0 and y=4 and z=7 then call missing(of x y z);
output;
end;
run;
data want fordel;
set have;
if min(of &testvarlist.) = max(of &testvarlist.)
and (cmiss(of &testvarlist.)=0 or missing(min(of &testvarlist.)))
then output fordel;
else output want;
run;
This isn't particularly inefficient, but there are certainly better ways to do this, as referenced in comments.
Data set have has some columns with prefix Dex. But I don't know how many columns exactly with that prefix.
I want to create an array with values equal to those columns.
data want;
set have;
array Dex[100];
for i = 1 to 100;
[assign values]
end;
run;
Is there a way to do this without knowing those columns' names?
Yes, you could define your array such as:
array vars Dex:;
do i=1 to dim(vars);
[assign values]
end;
run;
Use dictionary.columns to find out the number of columns which has prefix - dex
/Sample dataset/
data have;
dex_random1=1;
dex_1=2;
dex_3=4;
dex_dex_random=2;
run;
proc sql;
select count(*) into: Number_of_vars from dictionary.columns where
upcase(libname)="WORK" and upcase(memname)="HAVE" and upcase(name) like "DEX%";
select name into: All_vars separated by " " from dictionary.columns where
upcase(libname)="WORK" and upcase(memname)="HAVE" and upcase(name) like "DEX%";
quit;
data want(drop=i);
set have;
array dex[&Number_of_vars.] &All_vars. ;
do i=1 to &Number_of_vars.;
dex[i]=1;
end;
run;