Calculate salary base on total Hours in SQL Server - sql-server

Question

How can I calculate salary base on total Hours? I have two tables and a query that will compute the total hours per day.
Table officer_timelogs
employee_id record_time Day type
--------------------------------------------------------
125 2018-02-27 18:03:31.000 Tuesday 1
125 2018-02-27 07:54:03.000 Tuesday 0
Table officer_rate
employee_id designation salary
125 programmer 100 (hour)
SQL Query:
select
employee_id,
[Date], DATENAME(WEEKDAY, date)as [Day],
[Hours] = right(concat('00', diff / 3600), 2) + ' : ' + right(concat('00', diff % 3600 / 60), 2) + ' : ' + right(concat('00', diff % 60), 2)
from (
select
employee_id,
[date] = cast(record_time as date),
diff = datediff(ss, min(iif(type = 0, record_time, null)), max(iif(type = 1, record_time, null)))
from
officer_timelogs
where employee_id = '125'
group by employee_id, cast(record_time as date)
) t
order by date desc
Output:
employee_id Date Day Hours
125 2018-03-02 Friday 09 : 00 : 00
125 2018-03-01 Thursday 10 : 10 : 49
125 2018-02-28 Wednesday 10 : 14 : 11
125 2018-02-27 Tuesday 10 : 09 : 28
125 2018-02-26 Monday 10 : 13 : 34
Desired output (I want to retrieve data like this)
employee_id Date Day Hours Salary
125 2018-03-02 Friday 09 : 00 : 00 900

Answer 1

I think you've done the most complex part.
Since you already have the worked time, you just need to multiply by the salary, like this:
select
t.employee_id,
[Date], DATENAME(WEEKDAY, date)as [Day],
[Hours] = right(concat('00', diff / 3600), 2) + ' : ' + right(concat('00', diff % 3600 / 60), 2) + ' : ' + right(concat('00', diff % 60), 2),
diff * r.salary / 3600 AS Salary
from (
select
employee_id,
[date] = cast(record_time as date),
diff = datediff(ss, min(iif(type = 0, record_time, null)), max(iif(type = 1, record_time, null)))
from
officer_timelogs
where employee_id = '125'
group by employee_id, cast(record_time as date)
) t
INNER JOIN officer_rate r ON t.employee_id = r.employee_id
order by date desc
You can check it live on this SQL Fiddle.
Edit: Code and demo updated with OT rate:
In this case, you need to check if OT should be applied. If the person worked 8h or less, we consider the regular rate. The difference for the 8h is calculated by considering 20% of the hourly salary:
select
t.employee_id,
[Date], DATENAME(WEEKDAY, date)as [Day],
[Hours] = right(concat('00', diff / 3600), 2) + ' : ' + right(concat('00', diff % 3600 / 60), 2) + ' : ' + right(concat('00', diff % 60), 2),
CAST(
CASE WHEN diff <= 3600 * 8
THEN diff * r.salary / 3600
ELSE
(3600 * 8 * r.salary / 3600) -- salary x 8h / work
+ (diff - (3600 * 8)) * r.salary * 0.2 /3600 -- OT work
END AS decimal(10, 2)) AS Salary
from (
select
employee_id,
[date] = cast(record_time as date),
diff = datediff(ss, min(iif(type = 0, record_time, null)), max(iif(type = 1, record_time, null)))
from
officer_timelogs
where employee_id = '125'
group by employee_id, cast(record_time as date)
) t
INNER JOIN officer_rate r ON t.employee_id = r.employee_id
order by date desc;
Demo updated here

Answer 2

Maybe this. I bet you need to convert hours to decimal such that 1 hour and 30 minutes will make 1.5
select
employee_id,
[Date], DATENAME(WEEKDAY, date)as [Day],
[Hours] = right(concat('00', diff / 3600), 2) + ' : ' + right(concat('00', diff % 3600 / 60), 2) + ' : ' + right(concat('00', diff % 60), 2),
Salary = <However you need to get hour(s) as a decimal> * tl2.salary
from (
select
employee_id,
[date] = cast(record_time as date),
diff = datediff(ss, min(iif(type = 0, record_time, null)), max(iif(type = 1, record_time, null)))
from
officer_timelogs
where employee_id = '125'
group by employee_id, cast(record_time as date)
) t
INNER JOIN officer_rate tl2 ON tl2.employee_id=t.employee_id
order by date desc