Creating a process tree with 4 children - c

I am having trouble creating this process tree.
This is my code:
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>
int main ()
{
int i;
printf("\n [ID = %d] I am the root parent \n", getpid());
for(i=0;i<4;i++)
{
pid_t ret=fork();
if(ret <0) //eror occured
{
printf("Fork Failed \n");
return 1;
}
else if (ret == 0){
printf("\n [ID =%d] My parent is [%d]\n", getpid(), getppid());
}
else
{
wait(NULL);
exit(0);
}
}
return 0;
}
and this is my output
[ID = 4478] I am the root parent
[ID =4479] My parent is [4478]
[ID =4480] My parent is [4479]
[ID =4481] My parent is [4480]
[ID =4482] My parent is [4481]
When I sketch this out, it's just a chain process tree.
p
|
C1
|
C2
|
C3
|
C4
I tried other methods of writing this but this was as close to getting four children. I've been getting 6 on my other tries.

Your flaw is in the logic of the program itself. First you think of making a loop with 4 iterations, when in reality you only want 2 children on the parent process. But then, when fork is successful (ret > 0) you are calling wait(NULL); exit(0); which will stop the for loop and exit the process once wait stops hanging. When the children are forked, they will be inside the for loop themselfs as well. If the loop wasn't getting stuck in the wait(NULL); exit(0); statements you'd have an even bigger mess, with the parent process having 4 children, and the childrens having between 3 and 0 childrens, and the grandchildrens having between 2 and 0 childrens, and so on..
What you need is something like this:
for(i = 0; i < 2; ++i){
pid_t ret = fork();
if(ret < 0){
printf("Fork Failed!\n");
return 1;
} else if(ret == 0) { //Children process
pid_t children_ret = fork();
if(children_ret < 0){
printf("Fork Failed!\n");
return 1;
} else if(children_ret == 0) { //Grandchildren process
//... Do whatever you want on the grandchildren process
exit(0);
}
//... Do whatever you want on the children process
wait(NULL);
exit(0);
}
}
//... Do whatever you want on the parent process
wait(NULL);
exit(0);
Note that the exit calls on the children and grandchildren processes are very important. That's because all the processes share the same code, so if they don't exit on those points they will keep running whatever rest of code you have (i.e.: the grandchildren will run the children code and the parent code).

Related

Using fork() and execlp() to create process hierarchy in C

I MUST use fork() and execlp() to create and annotate the given process hierarchy:
I cannot wrap my head around when each process should be forked in order to reflect this hierarchy, add to that the non-negotiable use of execlp() which replaces the current process image.
Here is what I managed to come up with (please excuse the very non-DRY code, I'm new to these concepts):
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <errno.h>
#include <sys/types.h>
#include <sys/wait.h>
#define oops(m) {perror(m); exit(EXIT_FAILURE);}
int main() {
pid_t pid1_1, pid1_2, pid1_1_1, pid1_1_2, pid1_2_1, pid1_2_2;
pid1_1 = fork();
if (pid1_1 < 0) {
oops("Fork Failed!");
}
// child 1.1
if (pid1_1 == 0) {
printf("I am the child %d\n", getpid());
if (execlp("./iam", "iam", "1.1", NULL) < 0)
oops("Execlp Failed!");
} else {
// grandchild 1.1.1
pid1_1_1 = fork();
if (pid1_1_1 < 0) {
oops("Fork Failed!");
}
if (pid1_1_1 == 0) {
printf("I am the grandchild %d\n", getpid());
if (execlp("./iam", "iam", "1.1.1", NULL) < 0)
oops("Execlp Failed!");
}
//grandchild 1.1.2
pid1_1_2 = fork();
if (pid1_1_2 < 0) {
oops("Fork Failed!");
}
if (pid1_1_2 == 0) {
printf("I am the grandchild %d\n", getpid());
if (execlp("./iam", "iam", "1.1.2", NULL) < 0)
oops("Execlp Failed!");
}
}
pid1_2 = fork();
if (pid1_2 < 0) {
oops("Fork Failed!");
}
// child 1.2
if (pid1_2 == 0) {
printf("I am the child %d\n", getpid());
if (execlp("./iam", "iam", "1.2", NULL) < 0)
oops("Execlp Failed!");
} else {
// grandchild 1.2.1
pid1_2_1 = fork();
if (pid1_2_1 < 0) {
oops("Fork Failed!");
}
if (pid1_2_1 == 0) {
printf("I am the grandchild %d\n", getpid());
if (execlp("./iam", "iam", "1.2.1", NULL) < 0)
oops("Execlp Failed!");
}
// grandchild 1.2.2
pid1_2_2 = fork();
if (pid1_2_2 < 0) {
oops("Fork Failed!");
}
if (pid1_2_2 == 0) {
printf("I am the grandchild %d\n", getpid());
if (execlp("./iam", "iam", "1.2.2", NULL) < 0)
oops("Execlp Failed!");
}
}
// pid > 0 ==> must be parent
printf("I am the parent %d\n", getpid());
/* parent will wait for the child to complete */
if (waitpid(-1, NULL, 0) < 0)
printf("-1 from wait() with errno = %d\n", errno);
printf("Child terminated; parent exiting\n");
exit(EXIT_SUCCESS);
}
My output shows that this hierarchy is not set up correctly. For example, manually stepping through with gdb and finishing the PID for 1.2 terminates the entire process tree (when 1.1 sub-tree should be left in tact).
Any suggestions for where I'm going wrong with logically replicating this process hierarchy would be really appreciated. Thanks!
Any suggestions for where I'm going wrong with logically replicating this process hierarchy would be really appreciated.
Check this part of code at start of your program:
pid1_1 = fork();
this will fork a child process. After this you are doing:
if (pid1_1 == 0) {
printf("I am the child %d\n", getpid());
if (execlp("./iam", "iam", "1.1", NULL) < 0)
......
That means, now the child process image will be replaced by another process image.
As per picture you have shown, a process is supposed to fork 2 child process before calling execlp(), if it is a parent process in the given process tree. Similar kind of problems are there in below part of your code.
I cannot wrap my head around when each process should be forked in order to reflect this hierarchy, .....
Look at the process tree closely and you will find it as a perfect binary tree where every internal node has 2 child and all leaf nodes are at same level.
That said, every process should create 2 child process and then call execlp() and as soon as you reach to the given height (which is 2 in your case), no child process should fork further.
I will show you how to create the process hierarchy and you can add the execlp() call to replace the current process image with some other process image.
add to that the non-negotiable use of execlp() which replaces the current process image.
I believe, here, the current process means the process which is forking of child processes and this includes the top most process (equivalent to root in tree) as well.
To create the hierarchy of process as perfect binary tree, you can do:
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <sys/wait.h>
int main (int argc, char *argv[]) {
int height;
if (argc != 2) {
printf ("Invalid number of arguments, exiting..\n");
exit (0);
}
height = atoi (argv[1]);
if (height < 0) {
printf ("Invalid input.\n"); // error handling can be better
exit (0);
}
printf ("Parent process, my pid = %d, height = %d\n", getpid(), height);
for (int i = 0; i < height; ++i) {
printf ("\nMy pid : %d, current height of tree : %d, forking..\n", getpid(), i);
pid_t pid = fork();
if (pid == -1) {
printf ("Fork failed\n");
} else if (pid == 0) {
printf ("My pid = %d, [my parent : %d], I am child 1..\n", getpid(), getppid());
// this sleep is for sequenced output, otherwise it's not needed
// sleeping for 1 second
sleep (1);
continue;
}
pid = fork();
if (pid == -1) {
printf ("Fork failed\n");
} else if (pid == 0) {
printf ("My pid = %d, [my parent : %d], I am child 2..\n", getpid(), getppid());
// this sleep is for sequenced output, otherwise it's not needed
// sleeping for 1 second
sleep (1);
continue;
}
// break the loop as the current process is done with forking 2 child process
break;
}
// ADD execlp call here
// This part of code is to just show you the hierarchy.
// If you add execlp call above then part is not needed.
while (wait(NULL) > 0);
printf ("pid %d : I am EXITING\n", getpid());
// added sleep for sequenced output, otherwise it's not needed
sleep (1);
return 0;
}
Usage: ./a.out <height_of_process_tree>
Output:
# ./a.out 0
Parent process, my pid = 50807, height = 0
pid 50807 : I am EXITING
# ./a.out 1
Parent process, my pid = 50808, height = 1
My pid : 50808, current height of tree : 0, forking..
My pid = 50809, [my parent : 50808], I am child 1..
My pid = 50810, [my parent : 50808], I am child 2..
pid 50810 : I am EXITING
pid 50809 : I am EXITING
pid 50808 : I am EXITING
# ./a.out 2
Parent process, my pid = 50811, height = 2
My pid : 50811, current height of tree : 0, forking..
My pid = 50812, [my parent : 50811], I am child 1..
My pid = 50813, [my parent : 50811], I am child 2..
My pid : 50812, current height of tree : 1, forking..
My pid : 50813, current height of tree : 1, forking..
My pid = 50814, [my parent : 50812], I am child 1..
My pid = 50815, [my parent : 50813], I am child 1..
My pid = 50816, [my parent : 50812], I am child 2..
My pid = 50817, [my parent : 50813], I am child 2..
pid 50814 : I am EXITING
pid 50815 : I am EXITING
pid 50816 : I am EXITING
pid 50817 : I am EXITING
pid 50812 : I am EXITING
pid 50813 : I am EXITING
pid 50811 : I am EXITING

Amount of process

Do I understand correctly that 2 processes are created in the code below? Since one fork () call creates one thread. There are two such calls in the code, therefore, the process is created 2?
#include <stdio.h>
#include <stdlib.h>
int main() {
int x,y;
pid_t pidl, pid2;
x = 2;
y = 3;
printf ("Single process, x=$d\n",x);
pidl = fork();
if(pidl == 0) {
printf ("New, x=%d\n",x);
exit (0);
}
if(pid1 < 0){
printf("Cannot create");
exit (1);
}
pid2=fork();
if(pid2 == 0) {
printf ("New, y=%d\n",y);
exit (0);
}
if(pid2 < 0){
printf("Cannot create");
exit (1);
}
return 0;
}
Yes. This code create two child process.
However you do not make the relation between parent and child processes by using wait function.
Therefore result of code change variously.
Child process 1 can print result before / after parent process terminated.
Child process 2 can print result before / after parent process terminated.
Maybe this variable result confuse you.

I try to create a process using 'fork'

I'm start to studying the fork. while using the fork, I have some problems.
I'm trying to create a single parent process with two child
and two child trying to make each three grandchild.
When I run my code, unlike my expectations, so many child and grandchild come out.
Here my code:
int main()
{
int i, j, rev;
for(i=0;i<2;i++)
{
if((rev=fork())<0) { printf("fork() error\n"); exit(-1); }
else if(rev==0)
{
printf("child %d %d \n",getpid(),getppid());
for(j=0;j<3;j++)
{
if((rev=fork()) <0) { printf("fork() error\n"); exit(-1); }
else if(rev == 0)
{
printf("grandch %d %d \n",getppid(),getpid());
exit(0);
}
}
}
}
printf("parent %d %d \n",getpid(),getppid());
exit(0);
}
How can I correct this code?
One important example before using fork() statements :
//Calculate number of times hello is printed.
#include <stdio.h>
#include <sys/types.h>
int main()
{
fork();
fork();
fork();
printf("hello\n");
return 0;
}
Number of times hello printed is equal to number of process created. Total Number of Processes = 2^n where n is number of fork system calls. So here n = 3, 2^3 = 8.
fork (); // Line 1
fork (); // Line 2
fork (); // Line 3
L1 // There will be 1 child process
/ \ // created by line 1.
L2 L2 // There will be 2 child processes
/ \ / \ // created by line 2
L3 L3 L3 L3 // There will be 4 child processes
// created by line 3
So if you are trying to make two child process and then three grand
child follow something of this sort:
What you should do is something like this for two child processes
if(fork()) # parent
if(fork()) #parent
else # child2
else #child1
After you create process , you should check the return value. If you don't , the second fork() will be executed by both the parent process and the child process, so you have four processes.
If you want to create n child processes , just :
for (i = 0; i < n; ++i) {
pid = fork();
if (pid) { //means pid is non-zero value, i.e, pid>0
continue;
} else if (pid == 0) {
break;
} else {
printf("fork error\n");
exit(1);
}
}
The section of code that runs for the child processes doesn't exit. As a result, they continue on to run more iterations of the outer loop which only the parent process is supposed to run, so they spawn more children.
You need to call exit, or better yet _exit, so that the children don't do that:
int main()
{
int i, j, rev;
for(i=0;i<2;i++)
{
if((rev=fork())<0) { printf("fork() error\n"); exit(-1); }
else if(rev==0)
{
printf("child %d %d \n",getpid(),getppid());
for(j=0;j<3;j++)
{
if((rev=fork()) <0) { printf("fork() error\n"); exit(-1); }
else if(rev == 0)
{
printf("grandch %d %d \n",getpid(),getppid());
_exit(0);
}
}
sleep(1); // stick around so the grandchild can print the parent pid
_exit(0); // exit the child
}
}
printf("parent %d %d \n",getpid(),getppid());
sleep(1); // stick around so the child can print the parent pid
exit(0);
}

Interprocess Communication fork() - Timing wait() and/or sleep()

I've been asked to develop the consumer (client) side to a producer (server), where the producer creates processes, waits until the consumer has read shared memory and deleted processes, then passes control back to the producer for the killing of processes and the shutting down of the shared memory block.
I've researched the difference between sleep and wait, and realise that as soon as fork() is called, the child process begins running.
The below code is after the creation of processes and checks if they're parent processes. If they are, they wait(0). *Now for my question, how do I know where the code in the consumer starts to be executed, and how do I pass it back? *
else if(pid > 0)
{
wait(0);
}
Below can be seen the main loop the producer uses.
int noToCreate = atoi(argv[2]); // (user inputs on cmd line "./prod 20 10 5" - 20 size of shared mem, 10 process to be created, 5 processes to be deleted)
while(*memSig != 2)
{
while(*memSig == 1) // set memsignature to sleep while..
{
sleep(1);
}
for(B = 0; B < noToCreate; B++)
{
pid = fork();
if(pid == -1)
{
perror("Error forking");
exit(1);
}
else if(pid > 0)
{
wait(0);
}
else
{
srand(getpid());
while(x == 0)
{
if(*randNum == 101)
{
*randNum = rand() % (100 -
1) + 1;
*pidNum = getpid();
printf("priority: %d
Process ID: %d \n", *randNum, *pidNum);
x = 1;
}
else
{
*randNum++;
*pidNum++;
}
}
exit(0);
}
} /* Closes main for loop */
if(*memSig == 0)
{
*memSig = 1;
}
} /* Closes main while loop */
Thanks a bunch guys :)
wait make parent blocked until any child end .You can use waitpid let parent wait specific child.
When a child process end, it will set a signal SIG_CHILD.
The pid is zero for the child process after the fork, so you are in the child process at your call to the srand function.
The other pid is that for the child process which allows he original thread to wait for the child to finish. If you wish to pass data between the processes consider using a pipe. A popen call returns two file descriptors, one to write end and the other to the read end. Set this up before the fork and the two processes can communicate.
wait makes the parent wait for any child to terminate before going on (preferably use waitpid to wait for a certain child), whereas sleep puts the process to sleep and resumes it, as soon as the time passed as argument is over.
Both calls will make the process block.
And it is NOT said that the child will run immediately, this is indeterminate behavior!
If you want to pass data between producer and consumer, use pipes or *NIX sockets, or use the return-value of exit from the child if a single integer is sufficient.
See man wait, you can get the return value of the child with the macro WEXITSTATUS.
#include <sys/wait.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
int
main(int argc, char *argv[])
{
pid_t cpid, w;
int status;
cpid = fork();
if (cpid == -1) {
perror("fork");
exit(EXIT_FAILURE);
}
if (cpid == 0) { /* Code executed by child */
printf("Child PID is %ld\n", (long) getpid());
if (argc == 1)
pause(); /* Wait for signals */
_exit(atoi(argv[1]));
} else { /* Code executed by parent */
do {
w = waitpid(cpid, &status, WUNTRACED | WCONTINUED);
if (w == -1) {
perror("waitpid");
exit(EXIT_FAILURE);
}
if (WIFEXITED(status)) {
printf("exited, status=%d\n", WEXITSTATUS(status));
} else if (WIFSIGNALED(status)) {
printf("killed by signal %d\n", WTERMSIG(status));
} else if (WIFSTOPPED(status)) {
printf("stopped by signal %d\n", WSTOPSIG(status));
} else if (WIFCONTINUED(status)) {
printf("continued\n");
}
} while (!WIFEXITED(status) && !WIFSIGNALED(status));
exit(EXIT_SUCCESS);
}
}

how to create two processes from a single Parent

I know I'm going to need to use fork(), but this just creates a single child process. Do i simply call fork again from within the child process? Also, I need them to communicate through a signal or pipe, which is easier to implement and what do i need to know for doing that (functions, etc..)
To create a second process, call fork() again - either within the parent or the child (but not both!). Which you choose depends on whether you want this process to be a child of the original parent or a child of the first child process (it is usual for it to be a child of the original parent).
Communicating through a pipe is much simpler and more reliable than using signals. pipe(), close(), read(), write() and select() are the key functions here.
For example, to have the parent create two child processes, you would do something like:
pid_t child_a, child_b;
child_a = fork();
if (child_a == 0) {
/* Child A code */
} else {
child_b = fork();
if (child_b == 0) {
/* Child B code */
} else {
/* Parent Code */
}
}
Another fancy code using && operator:
pid_t c1_pid, c2_pid;
(c1_pid = fork()) && (c2_pid = fork()); // Creates two children
if (c1_pid == 0) {
/* Child 1 code goes here */
} else if (c2_pid == 0) {
/* Child 2 code goes here */
} else {
/* Parent code goes here */
}
#include <stdio.h>
#include <unistd.h>
void main(){
int pi_d ;
int pid ;
pi_d = fork();
if(pi_d == 0){
printf("Child Process B:\npid :%d\nppid:%d\n",getpid(),getppid());
}
if(pi_d > 0){
pid = fork();
if(pid > 0){
printf("\nParent Process:\npid:%d\nppid :%d\n",getpid(),getppid());
}
else if(pid == 0){
printf("Child Process A:\npid :%d\nppid:%d\n",getpid(),getppid());
}
}
}
output :
Parent Process:
pid:3648
ppid :2379
Child Process B:
pid :3649
ppid:3648
Child Process A:
pid :3650
ppid:3648
You can put the fork in a loop and generate as many child processes as you need.
I did that on a project recently.
for(nSon=0; nSon < nSonsAsked; nSon++) {
Log_Print("Setup son #%.2u ", nSon+1);
if((pid = fork()) == 0) {
/* Do child stuff init, like connect the pipes, close shared handles */
return iTMInChild(...); /* A specific function of the child work */
/* The life of the child should not go beyond that point, i.e. the loop is over
or else the child will spawn even more processes. */
}
else if(pid > 0) {
/* Father process stuff. Here I initialise an array with the pid of the forked */
/* processes, this way I can index with the number of processes.*/
pid[nSon] = pid;
}
else
return Err_Print(ERR_FORK_FAILED, "fork failed. errno=%d \"%s\"\n", errno, strerror(errno));
}
Log_Print() and Err_Print() are internal functions but quite obvious so I let them like they are.
There is one aspect with the variables that has to be explained. nSon and nSonAsked should be declared as globals not as stack variables. This way, their value persists in the forked process. This means that the nSon variable will have a different value in each of the children. This allows it to have a simpler numbering scheme than the ownpid() number.
To get it completely right, there are a lot of details to get right. You will have to set signal handlers in the father process to detect the death of a child, likewise the other way round (only possible on Linux, other Unix (at least Solaris) do not support parent death signals).
You have to be aware that open file descriptors in the father process will be also open in the child after fork and it will be the same one. This opens a lot of concurrency problems if you're not aware of it (the solution is using dup() and close() in the right places).
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
#include <sys/types.h>
int main()
{
system ("clear");
int i ;
pid_t childa,childb,childa1,childa2,childb1,childb2;
printf("\n \t \t I am the parent process with ID %d \n",getpid());
childa=fork();
if (childa == 0 )
{
printf("\nI am a child A with PID %d and my parent ID is %d\n",getpid(),getppid());
}
else
{
childb = fork();
if (childb == 0)
{
printf("\nI am Child B with ID %d and my parent ID is %d\n",getpid(),getppid());
}
else
{
sleep(1);
}
}
}
In this example they are just sleeping for a few random sec. It also has all the pid, so we can send SIGNAL to communicate... Most of the #includes are commented cause they were useless where I compiled.
#include <stdlib.h> // exit() ...
#include <stdio.h> // printf() ...
// Compile with -lrt -> cc file_name.c -lrt
//#include <fcntl.h>
//#include <sys/stat.h>
//#include <sys/types.h>
//#include <sys/wait.h> // may need this for wait()
//#include <time.h>
//#include <unistd.h> // and this one for fork()
// In the start function you can do whatever you want.
void start (const int azon) {
// For children processes
srand( time(NULL) );
unsigned t = rand()%5; // printf("%d\n", t);
sleep(t);
printf("%d. process reached the end.\n", azon);
exit(0);
}
int main() {
const int N = 5;
pid_t pids[N];
int i;
// The 'for' loop make 'N' process with 'fork()'.
// The children processes will call the start function.
// Since after fork() you will get 2 process. One Parent, and One Child
// The returning value from fork() is saved in "pids" which is an
// integer AND it is (<0) IF something went wrong.
// it is (>0) IF 'we are' in the Parent process,
// because this number is the Child process' ID (pid).
// and Last it is (==0) IF 'we are' in the Child process.
for (i = 0; i < N; i++) {
pids[i] = fork();
sleep(1);
if (pids[i] == 0) start(i+1); // ... OR you can make a switch(..)
}
// This 'for' loop in the wait(NULL) statement ONLY move on when a
// process ended, so it waits until 'N' proc ends.
for (i = 0; i < N; i++)
wait(NULL);
printf("Partent process reached the end\n");
return 0;
}
Just a little contribution, if you want to create 2 childs from the same parent you could use this code below. In which one father create 2 child processes (lazy and active).
#include <stdlib.h>
#include <stdio.h>
#include <unistd.h>
int main (){
pid_t lazy_child;
lazy_child = fork();
if(lazy_child == 0){ // This is the lazy child process.
printf("LAZY CHILD:%d\n", getpid());
}
else if(lazy_child > 0){ // This is the father process.
pid_t active_child = fork();
if(active_child == 0){ // This is the active child process.
printf("ACTIVE CHILD:%d\n", getpid());
}
else if(active_child > 0){ // This is the father process.
printf("FATHER:%d\n", getpid());
}
else{ // Fork doesnt work.
printf("fork error\n");
exit(1);
}
}
else{ // Fork doesnt work.
printf("fork error\n");
exit(1);
}
return 0;
}
If you run this code, you should get a similar output:
$ ./a.out
FATHER:14501
ACTIVE CHILD:14503
LAZY CHILD:14502
#include <sys/wait.h>
#include <stdio.h>
#include <unistd.h>
int main()
{
pid_t AliceID, BobID;
double n=0;
int i1 =0;
/* fork a child process */
AliceID = fork();
if (AliceID < 0) { /* error occurred */
fprintf(stderr, "Fork Failed");
return 1;
}
else if (AliceID == 0) { /* child Alice code */
for(int i=1; i<11; i++)
{n = n+i;
i1++; }
double avg1 = n/i1;
printf("From Alice: the average of 1,2, …, 10 is the-average-she-calculated");
printf(" sum = %.2f and avg = %.2f \n",n, avg1);
}
else {
BobID = fork();
if (BobID == 0) { /* Child Bob code */
printf("From Bob: I am born to print this and then die.\n");
} else { /* Parent Code */
/* parent will wait for the child to complete */
wait(NULL);
printf("From parent: AliceID is %d \n", AliceID);
printf("From parent: Bob is %d \n", BobID);
printf("Parent ID %d \n", getpid());
}
}
return 0;
}

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