I'm trying to return a string array from a function to another array and i just cant seem to get it working. Any advice?
the call is :
labelTypes() = loadLabelCSV(runningPath)
the code :
Function loadLabelCSV(runpath As String) As String()
Dim arr(5, 0) As String
Dim x As Integer
Dim line As String
Dim lineArr() As String
Dim reader As New StreamReader(runpath & "\labelTypes.csv", Encoding.Default)
If System.IO.File.Exists(runpath & "\labelTypes.csv") = False Then
MsgBox("The label types file is missing please check.", vbCritical)
End If
Do
line = reader.ReadLine
If line = "" Then Exit Do
lineArr = Split(reader.ReadLine, ",")
For y = 0 To 5
arr(y, x) = lineArr(y)
Next
x = x + 1
ReDim Preserve arr(5, UBound(arr, 2) + 1)
Loop
Return arr
End Function
Related
for belows code the line vItemsNotInMaster(k) = vCheckItems(i) throws a type mismatch error once the array vItemsNotInMaster shall be populated. I am not sure why - as the caller sub and function array variables are all declared as Variants and types did not change according to the Locals Window.
I tried different data types but, this does throw other error messages.
Public Sub Testing()
Dim myArray1(1 To 4) As Variant
Dim myArray2(1 To 4) As Variant
Dim myArray3 As Variant
myArray1(1) = "one1"
myArray1(2) = "two3"
myArray1(3) = "three5"
myArray1(4) = "four7"
myArray2(1) = "one1"
myArray2(2) = "two3"
myArray2(3) = "different"
myArray2(4) = "four7"
myArray3 = Comparing_TwoArrays(myArray1, myArray2)
Stop
End Sub
Public Function Comparing_TwoArrays(ByVal vCheckItems As Variant, ByVal vMasterList As Variant) As Variant
Dim vItemsNotInMaster As Variant
Dim isMatch As Boolean
Dim i As Integer
Dim j As Integer
Dim k As Integer
ReDim vArray3(1 To UBound(vCheckItems, 1) + UBound(vMasterList, 1))
k = 1
For i = LBound(vCheckItems, 1) To UBound(vCheckItems, 1)
isMatch = False
For j = LBound(vMasterList, 1) To UBound(vMasterList, 1)
If vCheckItems(i) = vMasterList(j) Then
isMatch = True
Exit For
End If
Next j
If (isMatch = False) Then
vItemsNotInMaster(k) = vCheckItems(i) '---> Throws type mismatch
k = k + 1
End If
Next i
If (k > 1) Then
ReDim Preserve vArray3(1 To k - 1)
Else
vArray3 = Empty
End If
Comparing_TwoArrays = vArray3
End Function
Does someone has an idea?
Code Example credited to: https://bettersolutions.com/vba/arrays/comparing.htm
As I said in my comment, replacing vItemsNotInMaster(k) = vCheckItems(i) with vArray3(k) = vCheckItems(i) will solve the problem.
But if you need learning arrays manipulation, the next more compact code returns the same in less code lines number:
Public Sub Testing_()
Dim myArray1(1 To 4) As String
Dim myArray2(1 To 4) As String
Dim myArray3 As Variant
myArray1(1) = "one1"
myArray1(2) = "two2"
myArray1(3) = "three5"
myArray1(4) = "four7"
myArray2(1) = "one1"
myArray2(2) = "two3"
myArray2(3) = "different"
myArray2(4) = "four7"
myArray3 = Application.IfError(Application.match(myArray1, myArray2, 0), "x") 'it palces "x" when not a match...
Debug.Print Join(myArray3, "|") 'just to visually see the return...
'for a single case:
Debug.Print "(first) missing element: " & myArray1(Application.match("x", myArray3, 0)) 'it returns according to the first occurrence
'For more than one missing occurrence:
Dim i As Long
For i = 1 To UBound(myArray3)
If myArray3(i) = "x" Then
Debug.Print "Missing: " & myArray1(i)
End If
Next i
End Sub
To return occurrences independent of array elements position, it is also simpler to use Application.Match (with a single iteration). If interested, I can also post such a function...
As pointed out by #FunThomas the function does not return anything. Fix for type mismatch error is to Redim the vItemsNotInMaster array for each new item, while preserving the already populated values.
The vArray3 variable does not make sense and function should be rewritten as:
Public Function Comparing_TwoArrays(ByVal vCheckItems As Variant, ByVal vMasterList As Variant) As Variant
Dim vItemsNotInMaster()
Dim isMatch As Boolean
Dim i As Integer
Dim j As Integer
Dim k As Integer
k = 1
For i = LBound(vCheckItems, 1) To UBound(vCheckItems, 1)
isMatch = False
For j = LBound(vMasterList, 1) To UBound(vMasterList, 1)
If vCheckItems(i) = vMasterList(j) Then
isMatch = True
Exit For
End If
Next j
If (isMatch = False) Then
ReDim Preserve vItemsNotInMaster(1 To k)
vItemsNotInMaster(k) = vCheckItems(i) '---> Throws type mismatch
k = k + 1
End If
Next i
Comparing_TwoArrays = vItemsNotInMaster
End Function
Return Matching Array Elements
The function will return an array of the not matching elements from the check array in the master array.
If all elements are matching (are found in master), it will return an array whose upper limit is less than its lower limit.
Option Explicit
Public Sub Testing()
Dim myArray1(1 To 4) As Variant
Dim myArray2(1 To 4) As Variant
Dim myArray3 As Variant
myArray1(1) = "one1"
myArray1(2) = "two3"
myArray1(3) = "three5"
myArray1(4) = "four7"
myArray2(1) = "one1"
myArray2(2) = "two3"
myArray2(3) = "different"
myArray2(4) = "four7"
myArray3 = NotInMasterArray(myArray1, myArray2)
If LBound(myArray3) <= UBound(myArray3) Then
' Column
Debug.Print "Column" & vbLf & Join(myArray3, vbLf)
' Delimited row:
Debug.Print "Row" & vbLf & Join(myArray3, ",")
Else
Debug.Print "All elements from Check array found in Master array."
End If
Stop
End Sub
Public Function NotInMasterArray( _
arrCheck() As Variant, _
arrMaster() As Variant, _
Optional ByVal ResultLowerLimit As Variant) _
As Variant()
' Write the check array's limits to variables.
Dim cLB As Variant: cLB = LBound(arrCheck)
Dim cUB As Long: cUB = UBound(arrCheck)
' Determine the lower limit ('nLB') of the result array.
Dim nLB As Long
If IsMissing(ResultLowerLimit) Then ' use the check array's lower limit
nLB = cLB
Else ' use the given lower limit
nLB = ResultLowerLimit
End If
' Calculate the result array's upper limit.
Dim nUB As Long: nUB = cUB - cLB + nLB
' Define the initial result array ('arrNot') making it the same size
' as the check array (it is possibly too big; it is only of the correct size,
' if all check array's elements are not found in the master array).
Dim arrNot() As Variant: ReDim arrNot(nLB To nUB)
' Write the result array's lower limit decreased by 1 to the result
' array's limit counter variable (to first count and then write).
Dim n As Long: n = nLB - 1
Dim c As Long ' Check Array Limit Counter
' Loop through the elements of the check array.
For c = cLB To cUB
' Check if the current element is not found in the master array.
If IsError(Application.Match(arrCheck(c), arrMaster, 0)) Then
n = n + 1 ' count
arrNot(n) = arrCheck(c) ' write
'Else ' found in master; do nothing
End If
Next c
If n < nLB Then ' all found in master
arrNot = Array() ' i.e. UBound(arrNot) < LBound(arrNot)
Else ' not all are found in master
If n < nUB Then ' not all elements are not found...
ReDim Preserve arrNot(nLB To n) ' ... resize to 'n'
'Else ' all elements are not found; do nothing
End If
End If
' Assign the result array to the result of the function.
NotInMasterArray = arrNot
End Function
Public Function MostOccuring(items() As Variant) As String
Dim count() As Integer
Dim strings() As Object
Dim Index As Integer
For Index = 0 To items.Length - 1
If srings.Exists(items(Index)) Then
count(strings.IndexOf(items(Index))) = 1 + count(strings.IndexOf(items(Index)))
Else
count(Index) = 1
strings(Index) = items(Index)
End If
Next
End
MostOccuring = strings(count.IndexOf(count.Max()))
End Function
This is my mostocurring function
This is how I call it
And it return '#VALUE!'. Why? It should return the most occuring string of the cells. Thanks.
You may also try something like this...
Public Function MostOccuring(items As Range) As String
Dim cell As Range
Dim dict, it
Dim maxCnt As Long
Set dict = CreateObject("Scripting.Dictionary")
For Each cell In items
If Not dict.exists(cell.Value) Then
dict.Item(cell.Value) = 1
Else
dict.Item(cell.Value) = dict.Item(cell.Value) + 1
End If
Next cell
For Each it In dict.keys
If dict.Item(it) > maxCnt Then
maxCnt = dict.Item(it)
MostOccuring = it
End If
Next it
End Function
In the below script the the function returns only the final value that is 6 as the return value. Can anybody help me to return the intermediate values also as 3,4,5,6.
Function test_array() As Variant
Dim test() As Integer
Dim i As Integer
For i = 0 To 3
ReDim Preserve test(i)
test(i) = 3 + i
test_array = test(i)
Next i
End Function
For having output as 3,4,5,6, you need to create a string array and you can use Join function for the desired output.
PFB for the code. I hope this will help.
Function test_array() As String
Dim test() As String
Dim i As Integer
For i = 0 To 3
ReDim Preserve test(i)
test(i) = 3 + i
Next i
test_array = Join(test, ",")
End Function
In order to return the whole array, you just need to modify your line test_array = test(i) to test_array = test , and put it outside the For loop. The reason for that is once test array is fully populated inside your For loop, you copy it contents to test_array, and return it to the calling procedure.
I added a short test Function procedure just to show that all the array results are returned to the calling procedure.
Function test_array Code
Function test_array() As Variant
Dim test() As Integer
Dim i As Integer
For i = 0 To 3
ReDim Preserve test(i)
test(i) = 3 + i
Next i
test_array = test
End Function
Sub Test_Func Code
Sub Test_Func()
Dim myArr() As Integer
Dim i As Integer
myArr = test_array
For i = LBound(myArr) To UBound(myArr)
MsgBox "Array element " & i & " value is " & myArr(i)
Next i
End Sub
Edit 1: return all the elements inside the array to the cell (as a String):
Function test_array() As String
Dim test() As Integer
Dim testStr As String
Dim i As Integer
For i = 0 To 3
ReDim Preserve test(i)
test(i) = 3 + i
If testStr = "" Then
testStr = test(i)
Else
testStr = testStr & "," & test(i)
End If
Next i
test_array = testStr
End Function
'Little modification to your code will return all value as comma separated value like "3,4,5,6" in a cell
Function test_array() As Variant
Dim test() As Integer
Dim i As Integer
Dim ret As String
For i = 0 To 3
ReDim Preserve test(i)
test(i) = 3 + i
ret = ret & "," & test(i)
Next i
test_array = ret
End Function
Sub test1()
Cells(1, 1) = test_array()
'This must produce string "3,4,5,6" in cell A1 of active excel sheet
End Sub
I have an array that I gathered from a code that splits and then slices an array.
Refer to this question: Split multidimensional array and then slice it
I have added this line of code: splitted = Application.Transpose(splitted)
Now the array is defined the following way:
When I try to run the following code:
For r = LBound(splitted) To UBound(splitted)
Debug.Print uniqueValues(splitted(r))
Next r
I get this error: run time error 9 subscript out of range
For reference with the original code, I receive this output:
It works fine with my function and I can only imagine that it has to do with the difference in the definition of the array.
The function requires this input: Function uniqueValues(uniqueArray As Variant) As Integer:
Function uniqueValues(uniqueArray As Variant) As Integer
Dim arr As New Collection, a
Dim i As Long
On Error Resume Next
For Each a In uniqueArray
arr.Add a, a
Next
uniqueValues = arr.Count
End Function
This is the code from the function that dee provided:
Sub SplitMe()
Dim source As Variant, tempArr As Variant
source = ActiveSheet.Range("A3:A5")
If Not IsArray(source) Then _
Exit Sub
Dim r As Integer
Dim parts() As String
Dim splitted As Variant
ReDim splitted(LBound(source) To UBound(source))
For r = LBound(source) To UBound(source)
parts = VBA.Split(source(r, 1), "\")
splitted(r) = parts
Next r
splitted = Application.Transpose(splitted)
'ReDim tempArr(LBound(splitted) To UBound(splitted))
'tempArr = Application.Index(splitted, 0, 1)
For r = LBound(splitted) To UBound(splitted)
Debug.Print uniqueValues(splitted(r))
Next r
End Sub
Try this:
Sub SplitMe()
Dim source As Variant, tempArr As Variant
source = ActiveSheet.Range("A3:A5")
If Not IsArray(source) Then _
Exit Sub
Dim r As Integer
Dim parts() As String
Dim splitted As Variant
ReDim splitted(LBound(source) To UBound(source))
For r = LBound(source) To UBound(source)
parts = VBA.Split(source(r, 1), "\")
splitted(r) = parts
Next r
splitted = Application.Transpose(splitted)
For r = LBound(splitted, 1) To UBound(splitted, 1)
Debug.Print uniqueValues(splitted, r)
Next r
End Sub
Function uniqueValues(uniqueArray As Variant, indx As Integer) As Integer
Dim arr As New Collection, a, s As String
Dim i As Long
On Error Resume Next
For i = LBound(uniqueArray, 2) To UBound(uniqueArray, 2)
a = uniqueArray(indx, i)
s = s & IIf(s <> "", ", ", "") & a
arr.Add a, a
Next
Debug.Print s, arr.Count
uniqueValues = arr.Count
End Function
I have an array prLst that is a list of integers. The integers are not sorted, because their position in the array represents a particular column on a spreadsheet. I want to know how I find a particular integer in the array, and return its index.
There does not seem to be any resource on showing me how without turning the array into a range on the worksheet. This seems a bit complicated. Is this just not possible with VBA?
Dim pos, arr, val
arr=Array(1,2,4,5)
val = 4
pos=Application.Match(val, arr, False)
if not iserror(pos) then
Msgbox val & " is at position " & pos
else
Msgbox val & " not found!"
end if
Updated to show using Match (with .Index) to find a value in a dimension of a two-dimensional array:
Dim arr(1 To 10, 1 To 2)
Dim x
For x = 1 To 10
arr(x, 1) = x
arr(x, 2) = 11 - x
Next x
Debug.Print Application.Match(3, Application.Index(arr, 0, 1), 0)
Debug.Print Application.Match(3, Application.Index(arr, 0, 2), 0)
EDIT: it's worth illustrating here what #ARich pointed out in the comments - that using Index() to slice an array has horrible performance if you're doing it in a loop.
In testing (code below) the Index() approach is almost 2000-fold slower than using a nested loop.
Sub PerfTest()
Const VAL_TO_FIND As String = "R1800:C8"
Dim a(1 To 2000, 1 To 10)
Dim r As Long, c As Long, t
For r = 1 To 2000
For c = 1 To 10
a(r, c) = "R" & r & ":C" & c
Next c
Next r
t = Timer
Debug.Print FindLoop(a, VAL_TO_FIND), Timer - t
' >> 0.00781 sec
t = Timer
Debug.Print FindIndex(a, VAL_TO_FIND), Timer - t
' >> 14.18 sec
End Sub
Function FindLoop(arr, val) As Boolean
Dim r As Long, c As Long
For r = 1 To UBound(arr, 1)
For c = 1 To UBound(arr, 2)
If arr(r, c) = val Then
FindLoop = True
Exit Function
End If
Next c
Next r
End Function
Function FindIndex(arr, val)
Dim r As Long
For r = 1 To UBound(arr, 1)
If Not IsError(Application.Match(val, Application.Index(arr, r, 0), 0)) Then
FindIndex = True
Exit Function
End If
Next r
End Function
array of variants:
Public Function GetIndex(ByRef iaList() As Variant, ByVal value As Variant) As Long
Dim i As Long
For i = LBound(iaList) To UBound(iaList)
If value = iaList(i) Then
GetIndex = i
Exit For
End If
Next i
End Function
a fastest version for integers (as pref tested below)
Public Function GetIndex(ByRef iaList() As Integer, ByVal value As Integer) As Integer
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Function
' a snippet, replace myList and myValue to your varible names: (also have not tested)
a snippet, lets test the assumption the passing by reference as argument means something. (the answer is no) to use it replace myList and myValue to your variable names:
Dim found As Integer, foundi As Integer ' put only once
found = -1
For foundi = LBound(myList) To UBound(myList):
If myList(foundi) = myValue Then
found = foundi: Exit For
End If
Next
result = found
to prove the point I have made some benchmarks
here are the results:
---------------------------
Milliseconds
---------------------------
result0: 5 ' just empty loop
result1: 2702 ' function variant array
result2: 1498 ' function integer array
result3: 2511 ' snippet variant array
result4: 1508 ' snippet integer array
result5: 58493 ' excel function Application.Match on variant array
result6: 136128 ' excel function Application.Match on integer array
---------------------------
OK
---------------------------
a module:
Public Declare Function GetTickCount Lib "kernel32.dll" () As Long
#If VBA7 Then
Public Declare PtrSafe Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As LongPtr) 'For 64 Bit Systems
#Else
Public Declare Sub Sleep Lib "kernel32" (ByVal dwMilliseconds As Long) 'For 32 Bit Systems
#End If
Public Function GetIndex1(ByRef iaList() As Variant, ByVal value As Variant) As Long
Dim i As Long
For i = LBound(iaList) To UBound(iaList)
If value = iaList(i) Then
GetIndex = i
Exit For
End If
Next i
End Function
'maybe a faster variant for integers
Public Function GetIndex2(ByRef iaList() As Integer, ByVal value As Integer) As Integer
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Function
' a snippet, replace myList and myValue to your varible names: (also have not tested)
Public Sub test1()
Dim i As Integer
For i = LBound(iaList) To UBound(iaList)
If iaList(i) = value Then: GetIndex = i: Exit For:
Next i
End Sub
Sub testTimer()
Dim myList(500) As Variant, myValue As Variant
Dim myList2(500) As Integer, myValue2 As Integer
Dim n
For n = 1 To 500
myList(n) = n
Next
For n = 1 To 500
myList2(n) = n
Next
myValue = 100
myValue2 = 100
Dim oPM
Set oPM = New PerformanceMonitor
Dim result0 As Long
Dim result1 As Long
Dim result2 As Long
Dim result3 As Long
Dim result4 As Long
Dim result5 As Long
Dim result6 As Long
Dim t As Long
Dim a As Long
a = 0
Dim i
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
Next
result0 = oPM.TimeElapsed() ' GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex1(myList, myValue)
Next
result1 = oPM.TimeElapsed()
'result1 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = GetIndex2(myList2, myValue2)
Next
result2 = oPM.TimeElapsed()
'result2 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
Dim found As Integer, foundi As Integer ' put only once
For i = 1 To 1000000
found = -1
For foundi = LBound(myList) To UBound(myList):
If myList(foundi) = myValue Then
found = foundi: Exit For
End If
Next
a = found
Next
result3 = oPM.TimeElapsed()
'result3 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
found = -1
For foundi = LBound(myList2) To UBound(myList2):
If myList2(foundi) = myValue2 Then
found = foundi: Exit For
End If
Next
a = found
Next
result4 = oPM.TimeElapsed()
'result4 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue, myList, False)
Next
result5 = oPM.TimeElapsed()
'result5 = GetTickCount - t
a = 0
't = GetTickCount
oPM.StartCounter
For i = 1 To 1000000
a = pos = Application.Match(myValue2, myList2, False)
Next
result6 = oPM.TimeElapsed()
'result6 = GetTickCount - t
MsgBox "result0: " & result0 & vbCrLf & "result1: " & result1 & vbCrLf & "result2: " & result2 & vbCrLf & "result3: " & result3 & vbCrLf & "result4: " & result4 & vbCrLf & "result5: " & result5 & vbCrLf & "result6: " & result6, , "Milliseconds"
End Sub
a class named PerformanceMonitor
Option Explicit
Private Type LARGE_INTEGER
lowpart As Long
highpart As Long
End Type
Private Declare Function QueryPerformanceCounter Lib "kernel32" (lpPerformanceCount As LARGE_INTEGER) As Long
Private Declare Function QueryPerformanceFrequency Lib "kernel32" (lpFrequency As LARGE_INTEGER) As Long
Private m_CounterStart As LARGE_INTEGER
Private m_CounterEnd As LARGE_INTEGER
Private m_crFrequency As Double
Private Const TWO_32 = 4294967296# ' = 256# * 256# * 256# * 256#
Private Function LI2Double(LI As LARGE_INTEGER) As Double
Dim Low As Double
Low = LI.lowpart
If Low < 0 Then
Low = Low + TWO_32
End If
LI2Double = LI.highpart * TWO_32 + Low
End Function
Private Sub Class_Initialize()
Dim PerfFrequency As LARGE_INTEGER
QueryPerformanceFrequency PerfFrequency
m_crFrequency = LI2Double(PerfFrequency)
End Sub
Public Sub StartCounter()
QueryPerformanceCounter m_CounterStart
End Sub
Property Get TimeElapsed() As Double
Dim crStart As Double
Dim crStop As Double
QueryPerformanceCounter m_CounterEnd
crStart = LI2Double(m_CounterStart)
crStop = LI2Double(m_CounterEnd)
TimeElapsed = 1000# * (crStop - crStart) / m_crFrequency
End Property
Here's another way:
Option Explicit
' Just a little test stub.
Sub Tester()
Dim pList(500) As Integer
Dim i As Integer
For i = 0 To UBound(pList)
pList(i) = 500 - i
Next i
MsgBox "Value 18 is at array position " & FindInArray(pList, 18) & "."
MsgBox "Value 217 is at array position " & FindInArray(pList, 217) & "."
MsgBox "Value 1001 is at array position " & FindInArray(pList, 1001) & "."
End Sub
Function FindInArray(pList() As Integer, value As Integer)
Dim i As Integer
Dim FoundValueLocation As Integer
FoundValueLocation = -1
For i = 0 To UBound(pList)
If pList(i) = value Then
FoundValueLocation = i
Exit For
End If
Next i
FindInArray = FoundValueLocation
End Function
Is this what you are looking for?
public function GetIndex(byref iaList() as integer, byval iInteger as integer) as integer
dim i as integer
for i=lbound(ialist) to ubound(ialist)
if iInteger=ialist(i) then
GetIndex=i
exit for
end if
next i
end function
Taking care of whether the array starts at zero or one.
Also, when position 0 or 1 is returned by the function, making sure that the same is not confused as True or False returned by the function.
Function array_return_index(arr As Variant, val As Variant, Optional array_start_at_zero As Boolean = True) As Variant
Dim pos
pos = Application.Match(val, arr, False)
If Not IsError(pos) Then
If array_start_at_zero = True Then
pos = pos - 1
'initializing array at 0
End If
array_return_index = pos
Else
array_return_index = False
End If
End Function
Sub array_return_index_test()
Dim pos, arr, val
arr = Array(1, 2, 4, 5)
val = 1
'When array starts at zero
pos = array_return_index(arr, val)
If IsNumeric(pos) Then
MsgBox "Array starting at 0; Value found at : " & pos
Else
MsgBox "Not found"
End If
'When array starts at one
pos = array_return_index(arr, val, False)
If IsNumeric(pos) Then
MsgBox "Array starting at 1; Value found at : " & pos
Else
MsgBox "Not found"
End If
End Sub
'To return the position of an element within any-dimension array
'Returns 0 if the element is not in the array, and -1 if there is an error
Public Function posInArray(ByVal itemSearched As Variant, ByVal aArray As Variant) As Long
Dim pos As Long, item As Variant
posInArray = -1
If IsArray(aArray) Then
If not IsEmpty(aArray) Then
pos = 1
For Each item In aArray
If itemSearched = item Then
posInArray = pos
Exit Function
End If
pos = pos + 1
Next item
posInArray = 0
End If
End If
End Function
The only (& even though cumbersome but yet expedient / relatively quick) way I can do this, is to concatenate the any-dimensional array, and reduce it to 1 dimension, with "/[column number]//\|" as the delimiter.
& use a single-cell result multiple lookupall macro function on the this 1-d column.
& then index match to pull out the positions. (usuing multiple find match)
That way you get all matching occurrences of the element/string your looking for, in the original any-dimension array, and their positions. In one cell.
Wish I could write a macro / function for this entire process. It would save me more fuss.