SQL Server - Grouping all partition table size - sql-server

Question

I'm using sp_msforeachDB to identify the size occupied at table level. In case of a partition table, is it possible to group all the partitions of a particular table and give a consolidated size occupied.
For instance, Table A has 12 partitions. sp_msforeachDB provides 12 rows of Table A with the size, rowcount etc. Is there any way to consolidate all the 12 rows in one single row
SELECT CAST(MONTH(#Date) AS VARCHAR,
CAST(YEAR(#Date) AS VARCHAR,
#DBName as db,
t.Name as TableName,
s.Name as SchemaName,
p.Rows as RowCount,
SUM(a.total_pages) * 8 as TotalSpaceKB
FROM sys.tables t
INNER JOIN sys.indexes i ON t.Object_ID = i.Object_ID
INNER JOIN sys.partitions p ON i.Object_ID = p.Object_ID and i.Index_ID = p.Index_ID
INNER JOIN sys.allocation_units a ON p.partition_ID = a.container_ID
LEFT OUTER JOIN sys.schemas s ON t.schema_ID = s.schema_ID
WHERE p.Rows > 0 and t.is_ms_shipped = 0 and i.Object_ID > 255
GROUP BY t.Name, s.Name, p.Rows

Answer 1

Take the SUM of p.Rows instead of grouping by it.
SELECT CAST(MONTH(GetDate()) AS VARCHAR),
CAST(YEAR(GetDate()) AS VARCHAR),
DB_NAME() as db,
t.Name as TableName,
s.Name as SchemaName,
Sum(p.Rows) as [RowCount],
SUM(a.total_pages) * 8 as TotalSpaceKB
FROM sys.tables t
INNER JOIN sys.indexes i ON t.Object_ID = i.Object_ID
INNER JOIN sys.partitions p ON i.Object_ID = p.Object_ID and i.Index_ID = p.Index_ID
INNER JOIN sys.allocation_units a ON p.partition_ID = a.container_ID
LEFT OUTER JOIN sys.schemas s ON t.schema_ID = s.schema_ID
WHERE p.Rows > 0 and t.is_ms_shipped = 0 and i.Object_ID > 255
GROUP BY t.Name, s.Name;