Illuminate \ Database \ QueryException (42S02)
SQLSTATE[42S02]: Base table or view not found: 1146 Table 'influencingquotes.posts' doesn't exist (SQL: select count(*) as aggregate from posts where quote_title = gtav hyhui)
I am not sure why this Database\QueryException is occurring :(
The Error says that the posts table is missing, maybe you forget to run:
php artisan migrate
1.If in database you couldn't find posts table
Then you need to try to find migration file for it
which for laravel 5 located in project_root_dir\database\migrations
Then via command line
php artisan migrate
2.If in database exist table, but name is wrong , for example name is post
In post model you need to specify table name
protected $table = 'post';
If it doesn't help, you need to write us
1.what you see in database, which tables or views exists there
2.What files you see in project_root_dir\database\migrations directory.
Related
I use DB::setDatabaseName(<database name>) to reset the databasename, then I use DB::table(<table name>)->get() to retrieve data. However laravel does not change to new database.
This is my error message:
Illuminate/Database/QueryException with message 'SQLSTATE[42P01]:
Undefined table: 7 ERROR: relation "t" does not exist LINE 1: select
* from "t" ^ (SQL: select * from "t")'
The table t is in another database. I think when I use DB::setDatabaseName(<database name>) it would work.
Thank you for your help!
I don't know your database of detail information, but this help you to check database have changed.
// current database is 'db_1'
echo DB::getDatabaseName(); // return db_1
// Set database to 'db_2'
DB::setDatabaseName('db_2');
// If success, should return 'db_2' now.
echo DB::getDatabaseName();
// Check database tables.
DB::select('show tables');
I was facing a similar issue.
But changing the database solely might not always work.
You could use config->set() like so
config()->set('database.connections.mysql', $database_name);
But in my case I had to reconnect the database to change it dynamically.
So maybe this one works for the OP.
\DB::disconnect();
config()->set('database.pgsql.database', $database_name); // psgl = Postgress
\DB::reconnect();
You'll find more info here Laravel 6 config()->get('database.connections.mysql') not matching DB:connection()
Hope it helps
I am not sure if my issue connecting to the Scala Play 2.5.x Framework or to PostgreSQL so I am going to describe my setup.
I am using the Play 2.5.6 with Scala and PostgreSQL 9.5.4-2 from the BigSQL Sandboxes. I use the Play Framework default evolution package to manage the DB versions.
I created a new database in BigSQL Sandbox's PGSQL and PGSQL created a default schema called public. I use this schema for development.
I would like to create a table with the following script (1.sql in DB evolution config):
# Initialize the database
# --- !Ups
CREATE TABLE user (
id SERIAL PRIMARY KEY,
name TEXT NOT NULL,
email TEXT NOT NULL,
creation_date TIMESTAMP NOT NULL
);
# --- !Downs
DROP TABLE user;
Besides that I would like to read the table with a code like this:
val resultSet = statement.executeQuery("SELECT id, name, email FROM public.user WHERE id=" + id.toString)
I got an error if I would like to execute any of the mentioned code or even if I use the CREATE TABLE... code in pgadmin. The issue is with the user table name. If I prefix it with public (i.e. public.user) everything works fine.
My questions are:
Is it normal to prefix the table name with the schema name every time? It seems to odd to me.
How can I make the public schema a default option so I do not have to qualify the table name? (e.g. CREATE TABLE user (...); will not throw an error)
I tried the following:
I set the search_path for my user: ALTER USER my_user SET search_path to public;
I set the search_path for my database: ALTER database "my_database" SET search_path TO my_schema;
search_path correctly shows this: "$user",public
I got the following errors:
In Play: p.a.d.e.DefaultEvolutionsApi - ERROR: syntax error at or near "user"
In pgadmin:
ERROR: syntax error at or near "user"
LINE 1: CREATE TABLE user (
********** Error **********
ERROR: syntax error at or near "user"
SQL state: 42601
Character: 14
This has nothing to do with the default schema. user is a reserved word.
You need to use double quotes to be able to create such a table:
CREATE TABLE "user" (
id SERIAL PRIMARY KEY,
name TEXT NOT NULL,
email TEXT NOT NULL,
creation_date TIMESTAMP NOT NULL
);
But I strongly recommend not doing that. Find a different name that does not require a quoted identifier.
Cakephp V. 2.5
My database table name is group_key_persons and My Model Name is GroupKeyPerson when i am writing this code to fetching the data.
$this->loadModel ( 'GroupKeyPerson' );
$data = $this->GroupKeyPerson->find('all');
pr($data);
It return an error :
Missing Database Table
Error: Table group_key_people for model GroupKeyPerson was not found in datasource default.
But i am preety sure database table is exist. but why the hell is people comes from in my table.??
The plural of "person" is "people" not "persons". So your table name should "group_key_people"
I have created a table :
add jar /../xlibs/hive-json-serde-0.2.jar;
CREATE EXTERNAL TABLE SerdeTest
(Unique_ID STRING
,MemberID STRING
,Data ARRAY>
)
PARTITIONED BY (Pyear INT, Pmonth INT)
ROW FORMAT SERDE "org.apache.hadoop.hive.contrib.serde2.JsonSerde";
ALTER TABLE SerdeTest ADD
PARTITION (Pyear = 2014, Pmonth =03) LOCATION '../Test2';
The data in the file :
{"Unique_ID":"ABC6800650654751","MemberID":"KHH966375835","Data":[{"SerialNo":1,"VariableName":"Var1","VariableValue":"A_49"},{"SerialNo":2,"VariableName":"Var2","VariableValue":"B_89"},{""SerialNo":3,"VariableName":"Var3","VariableValue":"A_99"}]}
Select query that I am using:
select Data[0].SerialNo from SerdeTest where Unique_ID = 'ABC6800650654751';
however, when I run this query I get the following error:
java.lang.RuntimeException: org.apache.hadoop.hive.ql.metadata.HiveException: Hive Runtime Error while processing row [Error getting row data with exception java.lang.ClassCastException: org.json.JSONArray cannot be cast to [Ljava.lang.Object;
at org.apache.hadoop.hive.serde2.objectinspector.StandardListObjectInspector.getList(StandardListObjectInspector.java:98)
at org.apache.hadoop.hive.serde2.SerDeUtils.buildJSONString(SerDeUtils.java:330)
at org.apache.hadoop.hive.serde2.SerDeUtils.buildJSONString(SerDeUtils.java:386)
at org.apache.hadoop.hive.serde2.SerDeUtils.getJSONString(SerDeUtils.java:237)
at org.apache.hadoop.hive.serde2.SerDeUtils.getJSONString(SerDeUtils.java:223)
at org.apache.hadoop.hive.ql.exec.MapOperator.process(MapOperator.java:539)
at org.apache.hadoop.hive.ql.exec.mr.ExecMapper.map(ExecMapper.java:157)
at org.apache.hadoop.mapred.MapRunner.run(MapRunner.java:50)
at org.apache.hadoop.mapred.MapTask.runOldMapper(MapTask.java:418)
at org.apache.hadoop.mapred.MapTask.run(MapTask.java:349)
at org.apache.hadoop.mapred.Child$4.run(Child.java:270)
at java.security.AccessController.doPrivileged(Native Method)
at javax.security.auth.Subject.doAs(Subject.java:415)
at org.apache.hadoop.security.UserGroupInformation.doAs(UserGroupInformation.java:1127)
at org.apache.hadoop.mapred.Child.main(Child.java:264)
]
Can anyone please suggest me what am I doing wrong
Few suggestions:
Make sure that all the packages of hive and hive-json-serde-0.2.jar have execute permission for hadoop user.
Hive creates a file called derby.log and metastore_db in the hive directory. It should be allowed to the user invoking the hive query to create files and directories.
Location for data should have / at the end. e.g. LOCATION '../Test2/';
In short, the working JAR is json-serde-1.3-jar-with-dependencies.jar which can be found here. This one is working with 'STRUCT' and can even ignore some malformed JSON. During the creation of the table, include the following code:
ROW FORMAT SERDE 'org.openx.data.jsonserde.JsonSerDe'
WITH SERDEPROPERTIES ("ignore.malformed.json" = "true")
LOCATION ...
If needed, it is possible to recompile it from here or here. I tried the first repository and it is compiling fine for me, after adding the necessary libs. The repository has also been updated recently.
Check for more details here.
CREATE TABLE LOG_FILES (
LOG_DTM VARCHAR(18),
LOG_TXT VARCHAR(300)
)
ORGANIZATION EXTERNAL(
TYPE ORACLE_LOADER
DEFAULT DIRECTORY LOG_DIR
ACCESS PARAMETERS(
RECORDS DELIMITED BY NEWLINE
FIELDS(
LOG_DTM position(1:18),
LOG_TXT position(19:300)
)
)
LOCATION('logadm'))
)
REJECT LIMIT UNLIMITED
/
LOG_DIR is an oracle directory that points to /u/logs/
The problem though is that the contents of /u/logs/ looks like this
logadm_12012012.log
logadm_13012012.log
logadm_14012012.log
logadm_15012012.log
Is there any way i can specify the location of the file dynamically? i.e. every time i run Select * from LOG_FILES it should use the log file of the day. (e.g. log_adm_DDMMYYYYY).
I know i can use alter table log_files location ('logadm_15012012.log') but i would like not to have to issue the alter command.
Any other possibilities?
Thanks
It's a shame you're running 10g. On 11g we can associate a pre-processor script - a shell script - with an external table. In your case you could run a script which would figure out the latest file and then issue a copy command. Something like:
cp logadm_15012012.log logadm
Adrian Billington has blogged about this feature here. Frankly his write-up is more helpful than the official docs.
But as you're on 10g all you can do is run the ALTER TABLE statement, or use a scheduled job (cron or whatever) to sync a new file with the generic name.