WPF: Change Progress-Bar color with IMultiValueConverter - wpf

Question

Ok so i have this properties in my View Model:
public double Progress
{
get { return _progress; }
set
{
_progress= value;
OnPropertyChanged();
}
}
public bool IsChecked
{
get { return _isChecked; }
set
{
_isChecked = value;
OnPropertyChanged();
}
}
And as you can see this implement INotifyPropertyChanged.
This is my Progress-Bar:
<ProgressBar Name="progressBarColumn"
Minimum="0"
Maximum="100"
Value="{Binding Progress, UpdateSourceTrigger=PropertyChanged}"
Width="{Binding Path=Width, ElementName=ProgressCell}"
Style="{StaticResource CustomProgressBar2}"/>
And my Style:
<Style x:Key="CustomProgressBar2" TargetType="ProgressBar">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="ProgressBar" >
<Grid x:Name="Root">
<Border Name="PART_Track"
CornerRadius="0"
Background="Blue"
BorderBrush="Blue"
BorderThickness="1"/>
<Border Name="PART_Indicator"
CornerRadius="0"
Background="Gray"
BorderBrush="Gray"
BorderThickness="1"
HorizontalAlignment="Left" />
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
So this works fine, my Progress-Bar color is Blue and fill with Gray color.
Now i want to add two more things and dont know when:
1. When my Progress-Bar reach the Value of 100 i want it Background become Green.
When my Property called IsChecked is False i want that my Background become Red.
So until here i have this IMultiValueConverter:
public class ProgressToPropgressBarBackgroundConverter : IMultiValueConverter
{
public object Convert(object[] values, Type targetType, object parameter, CultureInfo culture)
{
// Do my stuff
}
public object[] ConvertBack(object value, Type[] targetTypes, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}
The problem is that i dont know where to add my converter and how.
EDIT:
<Style x:Key="CustomProgressBar2" TargetType="ProgressBar">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="ProgressBar" >
<Grid x:Name="Root">
<Border Name="PART_Track"
CornerRadius="0"
Background="{TemplateBinding Background}"
BorderBrush="{TemplateBinding Background}"
BorderThickness="1"/>
<Border Name="PART_Indicator"
CornerRadius="0"
Background="{TemplateBinding Foreground}"
BorderBrush="{TemplateBinding Foreground}"
BorderThickness="1"
HorizontalAlignment="Left" />
</Grid>
</ControlTemplate>
</Setter.Value>
</Setter>
<Style.Triggers>
<DataTrigger Value="100" Binding="{Binding Path=Value, RelativeSource={RelativeSource AncestorType=ProgressBar}}">
<Setter Property="Foreground" Value="DarkCyan"/>
</DataTrigger>
<DataTrigger Binding="{Binding IsChecked}" Value="true">
<Setter Property="Background" Value="{DynamicResource ProgressBackgroundColor}" />
<Setter Property="Foreground" Value="{DynamicResource ProgressBarFillColor}" />
</DataTrigger>
<DataTrigger Binding="{Binding IsChecked}" Value="false">
<Setter Property="Background" Value="#55B3B3B6" />
</DataTrigger>
</Style.Triggers>
</Style>

Answer 1

You logic is simple enough you can avoid a converter and simply use triggers in your style:
<Style.Triggers>
<DataTrigger Binding=“{Binding Progress}” Value=“100”>
<Setter Property=“Background” Value=“Green” />
</DataTrigger>
<DataTrigger Binding=“{Binding IsChecked}” Value=“True”>
<Setter Property=“Background” Value=“Red” />
</DataTrigger>
</Style.Triggers>
Then you need to update your control template to properly respect the control’s Background property. You can use TemplateBinding for this:
<Border Name="PART_Track"
CornerRadius="0"
Background="{TemplateBinding Background}"
BorderBrush="{TemplateBinding Background}"
BorderThickness="1"/>
<Border Name="PART_Indicator"
CornerRadius="0"
Background="{TemplateBinding Foreground}"
BorderBrush="{TemplateBinding Foreground}"
BorderThickness="1"
HorizontalAlignment="Left" />
And if you want the same Blue and Gray default colors, add them to the style:
<Setter Property=“Background” Value=“Blue”/>
<Setter Property=“Foreground” Value=“Gray”/>