Calculate time difference in HH:MM:SS - sql-server

Question

I am trying to get the time difference between 2 times. I have a query which calculate the time in hours but what I want is to calculate in this (hh:mm) or (hh:mm:ss) format.
Is there any function or way I can achieve this ?
DECLARE #T TABLE
([EmpID] int, [TimeIn] datetime, [TimeOut] datetime);
INSERT INTO #T
([EmpID], [TimeIn], [TimeOut]) VALUES
(1, '2018-01-10 9:00:00', NULL),
(1, NULL, '2018-01-10 11:00'),
(1, '2018-01-10 11:30:00', NULL),
(1, NULL, '2018-01-10 13:00'),
(1, '2018-01-10 13:30:00', NULL),
(1, NULL, '2018-01-10 18:00'),
(1, '2018-01-11 9:00:00', NULL),
(1, NULL, '2018-01-11 11:00'),
(1, '2018-01-11 11:30:00', NULL),
(1, NULL, '2018-01-11 13:00'),
(1, '2018-01-11 13:30:00', NULL),
(1, NULL, '2018-01-11 18:33')
;
SELECT
FirstIN = CAST(MIN([AttendanceTimeIn]) AS TIME),
LastOUT = CAST(MAX([AttendanceTimeOut]) AS TIME),
HoursSpent = DATEDIFF(HOUR, CAST(MIN(AttendanceTimeIn) AS TIME), CAST(MAX(AttendanceTimeOut) AS TIME)),
CAST(COALESCE(AttendanceTimeIn, AttendanceTimeOut) AS DATE) [Date]
FROM #T
GROUP BY
CAST(COALESCE(AttendanceTimeIn, AttendanceTimeOut) AS DATE)

Answer 1

You can use this for With DATETIME
DECLARE #START_DATE datetime DECLARE #END_DATE datetime
-- Set the timeframe variables
SET #START_DATE = '2011-01-01 16:00:00' SET #END_DATE = '2011-01-01 22:47:22'
-- Use datediff to show the results in the
-- HH:MM:SS format
SELECT CONVERT(VARCHAR(6), datediff(second, #START_DATE, #END_DATE)/3600) + ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), (datediff(second, #START_DATE, #END_DATE) %
3600) / 60), 2) + ':' + RIGHT('0' + CONVERT(VARCHAR(2), datediff(second,
#START_DATE, #END_DATE) % 60), 2)
Result :
HH:MM:SS
6:47:22
OR With TIME
-- Declare some variables for the requested timeframe
DECLARE #START_DATE TIME
DECLARE #END_DATE TIME-- Set the timeframe variables
SET #START_DATE = '16:00:00'
SET #END_DATE = '22:47:22'-- Use datediff to show the results in the
-- HH:MM:SS format
SELECT CONVERT(VARCHAR(6), Datediff(second, #START_DATE, #END_DATE)/3600)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), (Datediff(second, #START_DATE,
#END_DATE) %
3600) / 60), 2)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), Datediff(second, #START_DATE, #END_DATE
) % 60)
, 2) AS 'HH:MM:SS'
AS Per Edit
;
WITH cte
AS (SELECT EMPID,
Min(TIMEIN) timein,
Max(TIMEOUT) timeout,
Cast(COALESCE(TIMEIN, TIMEOUT) AS DATE) d
FROM #T
GROUP BY EMPID,
Cast(COALESCE(TIMEIN, TIMEOUT) AS DATE))
SELECT EMPID,
D AS Day,
CONVERT(VARCHAR(6), Datediff(second, TIMEIN, TIMEOUT)/3600)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), (Datediff(second, TIMEIN, TIMEOUT) %
3600) /
60), 2)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), Datediff(second, TIMEIN, TIMEOUT) % 60)
, 2 )
AS [Hours Worked]
FROM cte
ORDER BY D ASC
Result
empid Day Hours Worked
1 2018-01-10 9:00:00
1 2018-01-11 9:33:00
Resolve After Mistake of preiviuos senario
SELECT FirstIN, LastOUT,
CONVERT(VARCHAR(6), Datediff(second, FirstIN, LastOUT)/3600)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), (Datediff(second, FirstIN, LastOUT) %
3600) /
60), 2)
+ ':'
+ RIGHT('0' + CONVERT(VARCHAR(2), Datediff(second, FirstIN, LastOUT) % 60)
, 2 ) AS
HoursSpent,[Date] FROM (
SELECT
FirstIN = CAST(MIN([TimeIn]) AS TIME),
LastOUT = CAST(MAX([TimeOut]) AS TIME),
HoursSpent = DATEDIFF(HOUR, CAST(MIN(TimeIn) AS TIME), CAST(MAX(TimeOut) AS TIME)),
CAST(COALESCE(TimeIn, TimeOut) AS DATE) [Date]
FROM #T
GROUP BY
CAST(COALESCE(TimeIn, TimeOut) AS DATE)) AS a

Answer 2

Check this snippet which returns difference at seconds level (HH:mm:ss)
SELECT CONVERT(time,
DATEADD(s,
DATEDIFF(s,
'2018-01-07 09:53:00',
'2018-01-07 11:53:01'),
CAST('1900-01-01 00:00:00.0000000' as datetime2)
)
)
If you need HH:mm only change 's' for 'mi'
And if you need difference in days too use this one:
SELECT CONVERT(datetime2,
DATEADD(s,
DATEDIFF(s,
'2018-01-07 09:53:00',
'2018-01-07 11:53:01'),
CAST('0001-01-01 00:00:00.0000000' as datetime2)
)
)