C program \n and while loop - c

Question

guys I have a C program question. My goal is to make a change operation working for taking a price and giving out the current amount remaining. I code in java, so this is my first time in C, Im not looking to have my entire code done for me. I can do the code, however im having trouble getting it to execute the way I want. My problem here is that when I use \n my code seems to work, but my output is really weird, i have to add constant spaces and repeat my lines. not sure why this is happening, Also my while loop does not seem to execute, which is making no sense to me. If anyone could help , I would apprectiate it. Thank you for reading, ps I reply isntantly
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/* Header comment that describes the purpose of the program
* Name Karanvir Dhillon
* Date Jan 12
*/
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main (void) {
double tendered;
double changeDue;
double price;
int hundred=0;
int twenty=0;
int ten=0;
int five=0;
int toonoe=0;
int loonie=0;
int quarter=0;
int dime=0;
int nickle=0;
int penny=0;
/* Statements to be executed */
printf("Total purchase price and tendered amount\n");
scanf("%lf %lf ", &price, &tendered);
printf(" %lf and %lf is \n", tendered,price);
changeDue=tendered-price;
printf("%lf \n", changeDue);
if(tendered<price){
printf("Not enough money recieved as payment \n");
}
if(tendered==price){
printf("Exact payment, no change given \n");
}
if(tendered>price){
printf("%lf Amount to be paid is \n", changeDue);
}
while(changeDue!=0.00){
if(changeDue<=100.00){
changeDue=changeDue-100.00;
hundred=hundred+1;
}
if(changeDue<=20.00){
changeDue=changeDue-20.00;
twenty=twenty+1;
}
if(changeDue<=10){
changeDue=changeDue-10.00;
ten=ten+1;
}
if(changeDue<=5){
changeDue=changeDue-5.00;
five=five+1;
}
if(changeDue<=2){
changeDue=changeDue-2.00;
toonoe=toonoe+1;
}
if(changeDue<=1){
changeDue=changeDue-1.00;
loonie=loonie+1;
}
if(changeDue>1){
for(int i=0;i<changeDue;i++){
if(i==0.25&&changeDue>=0.25){
changeDue=changeDue-0.25;
quarter=quarter+1;
}
if(i==0.10&&changeDue>=0.10){
changeDue=changeDue-0.10;
dime=dime+1;
}
if(i==0.05&&changeDue>=0.05){
changeDue=changeDue-0.05;
nickle=nickle+1;
}
if(i==0.01&&changeDue<0.05){
changeDue=changeDue-0.01;
penny=penny+1;
}
}
}
}
if(hundred!=0){
printf("%d hundred$ bills given as change \n",hundred);
}
if(twenty!=0){
printf("%d twenty$ bills given as change \n",twenty);
}
if(ten!=0){
printf("%d ten$ bills given as change \n",ten);
}
if(five!=0){
printf("%d five$ bills given as change \n",five);
}
if(toonoe!=0){
printf("%d toonie coins given as change \n",toonoe);
}
if(loonie!=0){
printf("%d loonie coins given as change \n",loonie);
}
if(quarter!=0){
printf("%d quarter coins given as change \n",quarter);
}
if(dime!=0){
printf("%d dime coins given as change \n",dime);
}
if(nickle!=0){
printf("%d nicke coins given as change \n",nickle);
}
if(penny!=0){
printf("%d penny coins given as change \n",penny);
}
return 0;
}

Answer 1

In most C compilers, including ours, the newline escape sequence '\n' yields an ASCII line feed character. The C escape sequence for a carriage return is '\r'.
Include a '\r' along with (or perhaps instead of) the '\n' in output strings. For example:
printf("Hello world\r\n");