FirstIn and LastOut in sqlserver - sql-server

Question

I have a table name [EmployeeAttendance] and I have records in it in respective order.
SELECT EI.[FirstName]+' '+EI.[LastName] [EmployeeName], [Dpt].[FullName] [Department], [Desig].[FullName] [Designation], FirstIN = CAST(MIN([AttendanceTimeIn]) AS TIME), LastOUT = CAST(MAX([AttendanceTimeOut]) AS TIME), HoursSpent = DATEDIFF(HOUR, CAST(MIN(AttendanceTimeIn) AS TIME), CAST(MAX(AttendanceTimeOut) AS TIME))
FROM [HRM].[tbl_EmployeeInfo] [EI], [HRM].[tbl_Designation] [Desig], [HRM].[tbl_Department] [Dpt], [HRM].[tbl_EmployeeAttendance] [Attendance]
WHERE [Dpt].[ID] = [EI].[DeptCode] AND [Desig].[ID] = [EI].[DesignationCode] AND [Attendance].[EmpCode] = [EI].[ID] AND [EI].[RecordStatusCode] != '13'
AND CAST([AttendanceTimeIn] as date) = CAST(GetDate()-1 as Date)
GROUP BY
EI.[FirstName]+' '+EI.[LastName], [Dpt].[FullName], [Desig].[FullName], CAST([Attendance].[AttendanceTimeIn] AS DATE)
This is what I am getting as output.
Ajmal John Projects Project Associate 10:16:38.0000000 NULL NULL
Asif Asif Office Staff Office Boy 09:28:36.0000000 NULL NULL
Muhammad Asim Support Database Support Engineer 10:47:28.0000000 19:16:17.0000000 9
Sajjad Ahmed Projects Project Manager 09:41:34.0000000 NULL NULL
Sidra Khizar Quality Assurance SQA Engineer 10:18:48.0000000 NULL NULL
Because I have placed TimeIn and TimeOut in same row it is giving me TimeOut but as for other fields I have Time Out in 2nd row so it is giving Null. Not sure why

Answer 1

If Your Data Type Is TIME, then this works fine
DECLARE #T TABLE
([EmpID] int, [TimeIn] TIME, [TimeOut] TIME)
;
INSERT INTO #T
([EmpID], [TimeIn], [TimeOut])
VALUES
(1, '9:00', NULL),
(1, NULL, '11:00'),
(1, '11:30', NULL),
(1, NULL, '13:00'),
(1, '13:30', NULL),
(1, NULL, '18:00')
;
;WITH TM
AS
(
SELECT
EmpID,
MIN([TimeIn]) as StartTime,
MAX([TimeOut]) as EndTime
FROM #T
GROUP BY EmpId
)
SELECT
*,
HoursSpent = DATEDIFF(HOUR, StartTime, EndTime)
FROM TM
Result
If The DataType is different Try Casting it as Time inside the MAX and MIN Functions

Answer 2

If TimeIn and TimeOut are of TIME datatype then this works
DECLARE #EmployeeAttendance TABLE (EmpID INT, TimeIn TIME, [TimeOut] TIME);
INSERT INTO #EmployeeAttendance
(EmpID, TimeIn, TimeOut)
SELECT 1, '9:00', NULL UNION ALL
SELECT 1, NULL, '11:00' UNION ALL
SELECT 1, '11:30', NULL UNION ALL
SELECT 1, NULL,'13:00' UNION ALL
SELECT 1,'13:30', NULL UNION ALL
SELECT 1,NULL,'18:00';
SELECT
EmpID
, FirstIN = MIN([TimeIn])
, LastOUT = MAX([TimeOut])
, HoursSpent = DATEDIFF(HOUR, MIN(TimeIn), MAX(TimeOut))
--, MAX([TimeOut])-MIN([TimeIn]) AS HoursSpent
FROM
#EmployeeAttendance
GROUP BY
EmpID;
Output
If the columns are DATETIME then try this
DECLARE #EmployeeAttendance TABLE (EmpID INT, TimeIn DATETIME, [TimeOut] DATETIME);
INSERT INTO #EmployeeAttendance
(EmpID, TimeIn, TimeOut)
SELECT 1, '9:00', NULL UNION ALL
SELECT 1, NULL, '11:00' UNION ALL
SELECT 1, '11:30', NULL UNION ALL
SELECT 1, NULL,'13:00' UNION ALL
SELECT 1,'13:30', NULL UNION ALL
SELECT 1,NULL,'18:00';
SELECT
EmpID
, FirstIN = CAST(MIN([TimeIn]) AS TIME)
, LastOUT = CAST(MAX([TimeOut]) AS TIME)
, HoursSpent = DATEDIFF(HOUR, CAST(MIN(TimeIn) AS TIME), CAST(MAX(TimeOut) AS TIME))
--, MAX([TimeOut])-MIN([TimeIn]) AS HoursSpent
FROM
#EmployeeAttendance
GROUP BY
EmpID;

Answer 3

If you have the TimeIn & TimeOut as DateTime field in SQL server then it can be achieved as below:
SELECT
EmpID,
MIN(cast(TimeIN as time)) as FirstIN,
MAX(cast(TimeOut as time)) as LastOUT,
DATEDIFF(hour,MIN([TimeIn]),MAX([TimeOut])) AS HoursSpent
FROM [EmployeeAttendance]
GROUP BY EmpId
Query gives output for above sample data is as follows:
EmpID FirstIN LastOUT HoursSpent
1 09:00:00.0000000 18:00:00.0000000 9