index.txt:
2 6
8 12
text.txt number 1~15 are head number.
1
2
3 a
4 b
5 c
6
7
8
9 e
10 f
11 g
12
13
14
15
I want to print number 2~6 and 8~12 line
code:
setlocal EnableExtensions EnableDelayedExpansion
for /f "tokens=1,2,* delims= " %%a in (index.txt) do (
set /a start=%%a
set /a final=%%b
for /f "skip=%start% tokens=1,* delims=:" %%i in ('findstr /n ".*" text.txt') do (if %%i LEQ %final% echo %%j)
)
endlocal
but this not work
for /f "tokens=1,* delims=:" %%i in ('findstr /n ".*" text.txt') do (if %%i GEQ %%a if %%i LEQ %%b echo %%j)
No need to use start or final at all.
I am new to Batch and I would like to know if I can find out all combinations of numbers in order.
In this case I have 49 Numbers from 1 - 49 , and I have to pick 6 Numbers to be the results.
For example:
1 2 3 4 5 6
1 2 3 4 5 7
...
1 2 3 4 5 49
1 2 3 4 6 7
1 2 3 4 6 8
etc...
This is my old code:
#echo off > NEWFILE & setLocal EnableDelayedExpansion
set a=44
set b=45
set c=46
set d=47
set e=48
set f=49
for /L %%a in (1 1 !a!) do (
for /L %%b in (2 1 !b!) do (
for /L %%c in (3 1 !c!) do (
for /L %%d in (4 1 !d!) do (
for /L %%e in (5 1 !e!) do (
for /L %%f in (6 1 !f!) do (
echo.%%a %%b %%c %%d %%e %%f
))))))) >> NEWFILE
goto :EOF
However it returns:
1 2 3 4 5 6
1 2 3 4 5 7
...
1 2 3 4 5 49
1 2 3 4 6 6
Two 6's appeared.
I don't seem to be able to fix it, please help, thanks very much!
When you post a question you should post your efforts to solve it, describe the method used and the problems you had; otherwise you may get similar answers with no explanations at all, like this one:
EDIT: As users dbenham and aschipfl indicated, my original code have a small bug: the set /A i=M-1 line should be placed after the :nextSet label. This is the right code:
#echo off
setlocal EnableDelayedExpansion
set "N=%1"
set "M=%2"
set "line="
for /L %%i in (1,1,%M%) do (
set "C[%%i]=%%i"
set "line=!line! ^!C[%%i]^!"
)
:nextSet
set /A i=M-1
for /L %%j in (!C[%M%]!,1,%N%) do (
set "C[%M%]=%%j"
echo %line%
)
:nextPos
set "C=!C[%i%]!"
if %C% equ %N% (
set /A i-=1
if !i! equ 0 goto :EOF
goto nextPos
)
for /L %%i in (%i%,1,%M%) do (
set /A C+=1,C[%%i]=C
)
if !C[%M%]! gtr %N% goto nextPos
goto nextSet
Obviously, the corrected code generate a much larger number of results and this version is particularly slow... :(
The new version below use the exact same code of dbenham's solution; its only advantage is that you may change the parameters used to generate the result in a very easy way:
#echo off
setlocal EnableDelayedExpansion
set "N=%1"
set "M=%2"
set /A j=N-M, prev=0
set "for=" & set "line=" & set "endfor="
for /L %%i in (1,1,%M%) do (
set /A j+=1
set "for=!for! set /A start=!prev!+1 & for /L %%%%i in (^!start^!,1,!j!) do ("
set "line=!line! %%%%i"
set "endfor=!endfor!)"
set "prev=%%%%i"
)
REM ECHO !FOR! echo !LINE! %ENDFOR%
%for% echo %line% %endfor%
Output example:
C:\> test.bat 6 4
1 2 3 4
1 2 3 5
1 2 3 6
1 2 4 5
1 2 4 6
1 2 5 6
1 3 4 5
1 3 4 6
1 3 5 6
1 4 5 6
2 3 4 5
2 3 4 6
2 3 5 6
2 4 5 6
3 4 5 6
To get your results, use: test.bat 49 6
2ND EDIT: Faster method added
When the problem to solve is the excessive time a process takes, an obvious alternative is to use a faster programming language. The solution below use JScript, that is somewhat similar to Batch file programming:
#if (#CodeSection == #Batch) #then
#echo off
echo Start: %time%
cscript //nologo //E:JScript "%~F0" > result.txt
echo End: %time%
goto :EOF
#end
// JScript code section
for ( var A=1; A <= 44; ++A ) {
for ( var B=A+1; B <= 45; ++B ) {
for ( var C=B+1; C <= 46; ++C ) {
for ( var D=C+1; D <= 47; ++D ) {
for ( var E=D+1; E <= 48; ++E ) {
for ( var F=E+1; F <= 49; ++F ) {
WScript.Echo(A,B,C,D,E,F);
}
}
}
}
}
}
This is a Batch-JScript hybrid script; save it with .BAT extension. This program took a little less than 9 minutes in my cheap-and-slow lap-top computer to generate a 239 MB file with 13983816 lines.
The problem is compute intensive, given that there are 13,983,816 unique permutations. (See https://en.wikipedia.org/wiki/Lottery_mathematics#Calculation_explained_in_choosing_6_from_49.)
The Rojo answer should work, but the GOTO and repetitive FOR /F parsing and IF logic will slow things down considerably.
The code is much faster if you use nested FOR /L loops.
#echo off
setlocal enableDelayedExpansion
for /l %%A in (1 1 44) do (
set /a start=%%A+1
for /l %%B in (!start! 1 45) do (
set /a start=%%B+1
for /l %%C in (!start! 1 46) do (
set /a start=%%C+1
for /l %%D in (!start! 1 47) do (
set /a start=%%D+1
for /l %%E in (!start! 1 48) do (
set /a start=%%E+1
for /l %%F in (!start! 1 49) do (
echo %%A %%B %%C %%D %%E %%F
)
)
)
)
)
)
This will still be unbearably slow to let this script print the results to the screen. I estimate it will take 1.25 hours on my machine. Redirecting the output to a file is about 5 times faster, around 15 minutes.
In the future, please show some code demonstrating that you've attempted to solve the problem yourself, showing where you got stuck, where the output is not as expected, etc. Questions resembling "Here are my requirements. Code this for me" generally aren't well-received around here. How you got an upvote without showing any code is beyond me, but c'est la vie.
In this instance, I found the problem interesting, so I thought I'd go ahead and get you started. Challenge: accepted. Here's one way to do it.
#echo off
setlocal enabledelayedexpansion
set "series=1 2 3 4 5 6"
:loop
echo %series%
if "%series%"=="44 45 46 47 48 49" goto :EOF
for /f "tokens=1-6" %%a in ("%series%") do (
set /a i1=%%a, i2=%%b, i3=%%c, i4=%%d, i5=%%e, i6=%%f+1
if !i6! gtr 49 set /a i5+=1, i6=i5+1
if !i5! gtr 48 set /a i4+=1, i5=i4+1, i6=i5+1
if !i4! gtr 47 set /a i3+=1, i4=i3+1, i5=i4+1, i6=i5+1
if !i3! gtr 46 set /a i2+=1, i3=i2+1, i4=i3+1, i5=i4+1, i6=i5+1
if !i2! gtr 45 set /a i1+=1, i2=i1+1, i3=i2+1, i4=i3+1, i5=i4+1, i6=i5+1
set "series=!i1! !i2! !i3! !i4! !i5! !i6!"
)
goto loop
Here's another solution that should be more efficient.
#echo off
setlocal enabledelayedexpansion
set "series=1 2 3 4 5 6"
set total=0
for /L %%a in (1,1,44) do (
set /a i2 = %%a + 1
for /L %%b in (!i2!, 1, 45) do (
set /a i3 = %%b + 1
for /L %%c in (!i3!, 1, 46) do (
set /a i4 = %%c + 1
for /L %%d in (!i4!, 1, 47) do (
set /a i5 = %%d + 1
for /L %%e in (!i5!, 1, 48) do (
set /a i6 = %%e + 1
for /L %%f in (!i6!, 1, 49) do (
rem // Uncomment this echo to watch the progress (severely decreases efficiency)
rem echo %%a %%b %%c %%d %%e %%f
set /a total += 1
)
)
)
)
)
echo Total so far: !total!
)
rem // Should have gone through 13983816 iterations
In a Windows cmd script (aka bat script), I have a FOR /L loop from 1 to 8, where I need to do a bit shift and somehow format a variable as a hexadecimal number (which if you ask, is a single CPU identifier bit to feed into /AFFINITY).
I can't figure out how to do the last step. This is my loop.cmd file:
#ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
FOR /L %%i IN (1,1,8) DO (
SET /A "J=1<<%%i"
ECHO %%i and !J!
)
which does everything but format a hex number:
1 and 2
2 and 4
3 and 8
4 and 16
5 and 32
6 and 64
7 and 128
8 and 256
expected output is:
1 and 2
2 and 4
3 and 8
4 and 10
5 and 20
6 and 40
7 and 80
8 and 100
How do you format a hexadecimal number?
#ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
FOR /L %%i IN (1,1,8) DO (
SET /A "J=1<<%%i"
CALL :DECTOHEX J
ECHO %%i and !J!
)
GOTO :EOF
:DECTOHEX VAR
SET "DEC=!%1!"
SET "HEX="
:NEXT
SET /A DIGIT=DEC%%16, DEC/=16
SET "HEX=%DIGIT%%HEX%"
IF %DEC% NEQ 0 GOTO NEXT
SET "%1=%HEX%"
EXIT /B
EDIT: Reply to the comment
Previous solution works correctly when the shifted value have just one bit on, as stated in the question. If the shifted value may have several bits on then a more general decimal-to-hexadecimal conversion is required, like the one below:
#ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
REM DEFINE THE HEXA DIGITS
SET "HEXA=0123456789ABCDEF"
FOR /L %%i IN (1,1,8) DO (
SET /A "J=3<<%%i"
CALL :DECTOHEX J
ECHO %%i and !J!
)
GOTO :EOF
:DECTOHEX VAR
SET "DEC=!%1!"
SET "HEX="
:NEXT
SET /A DIGIT=DEC%%16, DEC/=16
SET "HEX=!HEXA:~%DIGIT%,1!%HEX%"
IF %DEC% NEQ 0 GOTO NEXT
SET "%1=%HEX%"
EXIT /B
#echo off
setlocal enabledelayedexpansion
set x=2
set n=1
set /a result=n
for /l %%a in (1,1,10) do (
set /a result*=x
if "!result:~0,1!"=="1" set result=!result:16=10!
echo %%a and !result!
)
output:
1 and 2
2 and 4
3 and 8
4 and 10
5 and 20
6 and 40
7 and 80
8 and 100
9 and 200
10 and 400
#echo off
setlocal enableDelayedExpansion
set /a "counter=0"
set "cycle7zForw=273 256 192 128 96 64 48 32 24 16 12 8"
for /l %%N in (1 1 12) do (
set /a "counter+=1"
call :therest
)
set cycle
pause
exit
:therest
for /f "tokens=%counter%" %%i in ("%cycle7zForw%") do set cycle7zForw%%N=%%i
exit /b
How do I set a variable that counts the number of values inside cycle7zForw and then put it in for /l %%N in (1 1 %variable%) do (
On my example, it counts 12, but I don't want to manually write 12, because there could be any number of values inside cycle7zForw.
You could solve with a different approach.
This replaces the spaces into linefeeds.
Then a single FOR /F loops through all numbers.
#echo off
setlocal enableDelayedExpansion
set /a "counter=0"
set "cycle7zForw=273 256 192 128 96 64 48 32 24 16 12 8"
set temp=!cycle7zForw: =^
!
for /f "delims=" %%i in ("!temp!") do (
set /a counter+=1
set cycle!counter!=%%i
)
set cycle
I want to make a batch file that prints out to a text file a list of combination of numbers and letters.
Using {0, ..., 9, a, ..., z, A, ..., Z} as my character pool, I have 62 unique characters.
The word length starts as 1 and increases up to a predetermined value.
The script starts at length = 1 and prints out 0 to Z.
Then it proceeds to length = 2 and prints out 00 to ZZ, and so on...
Here is an iterative solution that is much faster.
No need for CALL.
Each permutation is only generated once.
I was able to generate up to length 4 with over 15 million permutations in less than 5 minutes.
#echo off
setlocal enableDelayedExpansion
set chars=0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
set maxPos=61
del output.txt 2>nul
>prior.txt echo(""
for /l %%I in (1 1 %1) do (
>new.txt (
for /f %%A in (prior.txt) do for /l %%N in (0 1 %maxPos%) do echo(%%~A!chars:~%%N,1!
)
type new.txt>>output.txt
move /y new.txt prior.txt >nul
)
del prior.txt
Perhaps this is what you want?
TEST.BAT
#echo off
set charPool=_0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ
set charLen=62
(for /L %%a in (1,1,%1) do (
set permutation=
call :makePermutation %%a
)) > textfile.txt
goto :EOF
:makePermutation level
setlocal EnableDelayedExpansion
set lastPermutation=%permutation%
for /L %%i in (1,1,%charLen%) do (
set permutation=!lastPermutation!!charPool:~%%i,1!
if %1 gtr 1 (
set /A newLevel=%1-1
call :makePermutation !newLevel!
) else (
echo(!permutation!
)
)
exit /B
The batch file must be started with a number as parameter which is the unit length.
For example on using TEST.BAT 1 the text file textfile.txt contains 62 lines.
Note that TEST.BAT 2 generates 3906 combinations (strictly speaking, permutations in statistical sense) from 0 to ZZ, and TEST.BAT 3 generates 242234 combinations from 0 to ZZZ!
Calculation example for estimating the number of strings in text file (size of file):
Running TEST.BAT with 5 as parameter produces
62 ^ 5 + 62 ^ 4 + 62 ^ 3 + 62 ^ 2 + 62 ^ 1 = 931.151.402
strings in text file.