Layout routes with react router - reactjs

Question

I'm trying to do layouts with react-router.
When my user hits / I want to render some layout. When my user hits /login, or /sign_up I want the layout to render, with the relevant component for /login or /sign_up rendered.
Currently, my App.js looks like this
return (
<div className={className}>
<Route path="/" component={Auth} />
<ModalContainer />
</div>
);
My Auth.js looks like this
return (
<AuthFrame footerText={footerText} footerClick={footerClick}>
<Route path="/login" component={LoginContainer} />
<Route path="/sign_up" component={SignUpContainer} />
</AuthFrame>
);
So AuthFrame will get rendered when I hit /, and then react router looks for login or sign_up to render the other containers.
However, when I hit /, only the AuthFrame will render.
I would like for / to be treated as /login.
How do I achieve this?

Answer 1

The Switch component is useful in these cases:
return (
<AuthFrame footerText={footerText} footerClick={footerClick}>
<Switch>
<Route path="/login" component={LoginContainer} />
<Route path="/sign_up" component={SignUpContainer} />
{/* Default route in case none within `Switch` were matched so far */}
<Route component={LoginContainer} />
</Switch>
</AuthFrame>
);
see: https://github.com/ReactTraining/react-router/blob/master/packages/react-router/docs/api/Switch.md

Answer 2

I think you're forced to introduce a prop/state which indicates the status of your viewer. This means is he signed in or just a guest of your website.
Your router can't obviously render /login if you you hit / but the router allows you to redirect to another page:
class AuthContainer extends React.Component {
defaultProps = {
loggedIn: false
}
render() {
return <div>
<Route path="/login" component={LoginContainer}/>
<Route path="/sign_up" component={SignUpContainer}/>
</div>
}
}
class PublicHomePage extends React.Component {
render() {
return <div>
<Route path="/settings" component={SettingsComponent}/>
<Route path="/profile" component={ProfileComponent}/>
<Route path="/and_so_on" component={AndSoOnComponent}/>
</div>
}
}
class App
extends React.Component {
defaultProps = {
loggedIn: false
}
render() {
const {loggedIn} = this.props;
if (loggedIn) {
return <PublicHomePage/>
}
return <Route exact path="/" render={() => (
<Redirect to="/login"/>
)}/>
}
}
I hope this code works for you. It isn't quite perfect but it should give you an idea how you could solve your problem.

Answer 3

In your case I would probably manipulate a bit with Routes in react-router. This code in AuthFrame should do the trick:
return (
<AuthFrame footerText={footerText} footerClick={footerClick}>
{["/", "/login"].map((path, ind) =>
<Route exact key={ind} path={path} component={LoginContainer} />
)}
<Route exact path="/sign_up" component={SignUpContainer} />
</AuthFrame>);
Note the usage of exact on the routes, this is to prevent matching login component on /sign_up since it will also match / and prevent rendering both login and signup when accessing the root path (/).