TSQL turning these multiple CASE queries into one query - sql-server

Question

I have the following CASE queries that return 1 if they find anything, and 0 otherwise. I would like to turn these into a single query that returns 1 if any of them are true, or 0 otherwise. How can I acomplish this?
SELECT CASE WHEN count(PLACE.CODE) > 0 THEN 1 ELSE 0 END
FROM PLACE
WHERE STYLE = 'RED'
AND RULES = 'NO'
SELECT CASE WHEN count(GARDEN.AREA) > 0 THEN 1 ELSE 0 END
FROM GARDEN
WHERE PLACE = 'GROUND'
AND MAZE = '1'
SELECT CASE WHEN count(place_area.AVAILABLE_AREA) > 0 THEN 1 ELSE 0 END
FROM PLACE_AREA as place_area
INNER JOIN USED_PLACE as used_place
ON used_place.COLOR = 'RED'
AND used_place.MAKE = 'INDUSTRY'
WHERE place_area.CODE = 'FLOOR'
AND place_area.DANCE = '0'

Answer 1

If I understand you correctly, you can union all the result and calculate the sum, if sum > 0 then there was at least one 1
Select Case When Sum(x.col) > 0 THEN 1 ELSE 0 END from
(
SELECT CASE WHEN count(PLACE.CODE) > 0 THEN 1 ELSE 0 END as col
FROM PLACE
WHERE STYLE = 'RED'
AND RULES = 'NO'
Union All
SELECT CASE WHEN count(GARDEN.AREA) > 0 THEN 1 ELSE 0 END as col
FROM GARDEN
WHERE PLACE = 'GROUND'
AND MAZE = '1'
Union All
SELECT CASE WHEN count(place_area.AVAILABLE_AREA) > 0 THEN 1 ELSE 0 END as col
FROM PLACE_AREA as place_area
INNER JOIN USED_PLACE as used_place
ON used_place.COLOR = 'RED'
AND used_place.MAKE = 'INDUSTRY'
WHERE place_area.CODE = 'FLOOR'
AND place_area.DANCE = '0'
) x

Answer 2

SELECT
CASE
WHEN
EXISTS(
SELECT TOP 1 1
FROM PLACE
WHERE STYLE = 'RED'
AND RULES = 'NO'
AND count(PLACE.CODE) > 0
)
OR EXISTS (
SELECT TOP 1 1
FROM GARDEN
WHERE PLACE = 'GROUND'
AND MAZE = '1'
AND count(GARDEN.AREA) > 0
)
OR EXISTS (
SELECT TOP 1 1
FROM PLACE_AREA as place_area
INNER JOIN USED_PLACE as used_place
ON used_place.COLOR = 'RED'
AND used_place.MAKE = 'INDUSTRY'
WHERE place_area.CODE = 'FLOOR'
AND place_area.DANCE = '0'
AND count(place_area.AVAILABLE_AREA) > 0
)
THEN 1
ELSE 0
END