In batch my menu will not work - batch-file

Question

I was trying to create a simple menu system with batch but i can't tell if it's the 'goto' or the input part that i messed up on. help will be appreciated!
#echo off
cls
echo ==============MENU==============
echo 1.
echo 2.
echo 3.
echo choose.
set/p "menuInput"
if %menuInput%==1 (goto :1)
if %menuInput%==2 (goto :2)
if %menuInput%==3 (goto :3)
else echo error
:1 echo 1
:2 echo 2
:3 echo 3

Answer 1

The syntax of set /p is incorrect. Use set /? to read the help.
The parentheses around (goto :1) don't buy you anything.
The else is both syntactically incorrect (must be on the same logical line as the if) and useless (because if the if had succeeded control would have been passed to :3).
You are missing a bunch of exit /b or goto :eof in order to prevent control falling through the options.

Answer 2

ok i updated your code now this shold work
code here
#echo off
:menu
cls
title menu
echo ==============MENU==============
echo 1.
echo 2.
echo 3.
set /p menuInput=? 1-3
if %menuInput% EQU 1 goto 1
if %menuInput% EQU 2 goto 2
if %menuInput% EQU 3 goto 3
goto error
:1
echo1
pause
:2
echo2
pause
:3
echo3
pause
:error
echo error press 1-3
pause>nul
goto menu

Answer 3

As mentioned by #AlexP,your syntax of set /p is incorrect
you need to use set < space > /p < space > userinput=
and not set/p and there should be = sign after your variable name
SET /P variable=[promptString]
Read More about using SET & IF ELSE and also CHOICE
(edit- removed misleading code for error check)
sample batch with menu using Choice and SET /P IF Else while choosing option from menu.
Example 1 using IF ELSE (input error check)
#echo off
::Your Menu to choose from
:menu
cls
echo ==============MENU==============
echo 1.command menu item 1
echo 2.command menu item 2
echo 3.command menu item 3
echo.
set /p userinput=
if %userinput%==1 (
goto 1
) else if %userinput%==2 (
goto 2
) else if %userinput%==3 (
goto 3
) else (
goto error
)
:1
echo command 1
pause>nul
goto menu
:2
echo command 2
pause>nul
goto menu
:3
echo command 3
pause>nul
goto menu
::Incorrect Input go back to menu
:error
echo Incorrect User Input
pause>nul
goto menu
:end
exit
Example 2 using CHOICE command (no error input check)
#echo off
::Your Menu to choose from
:menu
cls
echo ==============MENU==============
echo 1.command menu item 1
echo 2.command menu item 2
echo 3.command menu item 3
::check and limit user input to selection
choice /C 123 /N /M "Your Selection"
IF "%ERRORLEVEL%"=="1" goto 1
IF "%ERRORLEVEL%"=="2" goto 2
IF "%ERRORLEVEL%"=="3" goto 3
:1
echo command 1
pause>nul
goto menu
:2
echo command 2
pause>nul
goto menu
:3
echo command 3
pause>nul
goto menu

Answer 4

Wrong is set /p.
try set /p menuInput =