Where orWhere Laravel 5.5 logical DB issue - database

Question

I am in agony
This is my helper
$friend_query = Friend::where([
'user_id' => Auth::id(),
'friend_id' => $friend_id,
])->orWhere([
'user_id' => $friend_id,
'friend_id' => Auth::id(),
])->first();
$friendship = new stdClass();
$friendship->exist = false;
$friendship->accepted = false;
if (! is_null($friend_query))
{
$friendship->accepted = $friend_query->accepted;
$friendship->exist = true;
}
var_dump($friendship->exist);
exit;
return $friendship;
And when I am logged as 'user_id' => auth::id() - everything is fine but when I am logged as 'friend_id' who got request always var_dump return me true... This is third day I can not find solution. The photo of DB included in post.

Answer 1

When you want to "group" your where clauses, you should pass a closure instead then perform your condition inside it. Say for example, you want your query to look like this
SELECT * FROM friends WHERE (user_id = ? AND friend_id = ?) OR (user_id = ? AND friend_id = ?) LIMIT 1
Then the eloquent version of this would be
$friend_query = Friend::where(function ($query) use ($friend_id) {
$query->where('user_id', Auth::id())
->where('friend_id', $friend_id);
})->orWhere(function ($query) use ($friend_id) {
$query->where('friend_id', Auth::id())
->where('user_id', $friend_id);
})->first();

Answer 2

Thank you,
just little syntax error should be
->orWhere(function ($query) {
but there is one problem - Undefined variable: friend_id
it goes like this
function friendship($friend_id){
friend_query = Friend::where([
'user_id' => Auth::id(),
'friend_id' => $friend_id,
])->orWhere(function ($query) {
$query->where([
'user_id' => $friend_id,
'friend_id' => Auth::id(),
]);
})
->first();
... }

Answer 3

Try it like this :
$friend_query = Friend::where([
'user_id' => Auth::id(),
'friend_id' => $friend_id,
])
->orWhere(function ($query) use($friend_id) {
$query->where([
'user_id' => $friend_id,
'friend_id' => Auth::id(),
]);
})
->first();