I have a SQL query already that gets the data I need but I'm struggling to figure out how to get that into a chart. This is sample data as result of my query:
year month day mode amount duration
2013 2 22 0 1 36001
2013 7 7 1 1 55062
2015 12 23 1 6 13
2015 12 23 4 4 11
2015 12 23 7 31 104
2015 12 23 8 2 4
2015 12 23 12 11 21
2015 12 23 13 3 8
2016 3 24 1 207 519
If I wanted to graph lets say amount grouped per year, month and day how would that be done in JFreeChart?
Related
I need to calculate the previous wage of director before he joins a new company.
I have created a simple dataset for one director (in practice I have many observations of director_id). This director with ID = 1 manages 5 firms which he joined in different years (the variable called enter). If director joined firm number 2 in 2011, I need the average of the variable wage for all years before 2011 which he was managing. For the same director = 1, I need a different mean(wage) for firm number 3 which he joined in 2012 (which will include mean(wage) from previous 2 companies that he managed before entering company 3 in 2012).
Below is the data. I would really appreciate your help in coding this problem.
clear
input enter year wage director_id firm_id
2006 2006 6.4790964 1 1
2006 2010 6.4783854 1 1
2006 2011 6.4067149 1 1
2006 2012 6.3716507 1 1
2006 2013 6.2248578 1 1
2006 2014 6.0631728 1 1
2011 2011 5.0127039 1 2
2011 2012 4.9616795 1 2
2011 2013 4.9483747 1 2
2011 2014 5.2612371 1 2
2012 2012 4.5389338 1 3
2012 2013 4.4322848 1 3
2012 2014 4.3223209 1 3
2013 2013 4.336947 1 4
2013 2014 4.27459 1 4
2015 2015 -.60586482 1 5
2015 2016 .085194588 1 5
end
I just need to exclude from mean(wage) all values that happen after he enters, so really need to regard only years before he enters a new company.
A recipe for what I think you seek is that the mean previous wage in other firms =
(SUM of previous wages in all firms MINUS sum of previous wages in this firm) / (COUNT of previous years in all firms MINUS count of previous years in this firm).
Your example is helpful but the wage variable is too irregular to allow easy eyeball checks.
Consider this sequence, where rangestat is from SSC.
clear
input enter year wage director_id firm_id
2006 2006 6.4790964 1 1
2006 2010 6.4783854 1 1
2006 2011 6.4067149 1 1
2006 2012 6.3716507 1 1
2006 2013 6.2248578 1 1
2006 2014 6.0631728 1 1
2011 2011 5.0127039 1 2
2011 2012 4.9616795 1 2
2011 2013 4.9483747 1 2
2011 2014 5.2612371 1 2
2012 2012 4.5389338 1 3
2012 2013 4.4322848 1 3
2012 2014 4.3223209 1 3
2013 2013 4.336947 1 4
2013 2014 4.27459 1 4
2015 2015 -.60586482 1 5
2015 2016 .085194588 1 5
end
sort year firm_id
replace wage = _n
rangestat (sum) SUM=wage (count) COUNT=wage, int(year . -1) by(director_id)
rangestat (sum) sum=wage (count) count=wage, int(year . -1) by(director_id firm_id)
replace sum = 0 if sum == .
replace count = 0 if count == .
gen wanted = (SUM - sum) / (COUNT - count)
list, sepby(year)
+---------------------------------------------------------------------------------+
| enter year wage direct~d firm_id SUM COUNT sum count wanted |
|---------------------------------------------------------------------------------|
1. | 2006 2006 1 1 1 . . 0 0 . |
|---------------------------------------------------------------------------------|
2. | 2006 2010 2 1 1 1 1 1 1 . |
|---------------------------------------------------------------------------------|
3. | 2006 2011 3 1 1 3 2 3 2 . |
4. | 2011 2011 4 1 2 3 2 0 0 1.5 |
|---------------------------------------------------------------------------------|
5. | 2006 2012 5 1 1 10 4 6 3 4 |
6. | 2011 2012 6 1 2 10 4 4 1 2 |
7. | 2012 2012 7 1 3 10 4 0 0 2.5 |
|---------------------------------------------------------------------------------|
8. | 2006 2013 8 1 1 28 7 11 4 5.666667 |
9. | 2011 2013 9 1 2 28 7 10 2 3.6 |
10. | 2012 2013 10 1 3 28 7 7 1 3.5 |
11. | 2013 2013 11 1 4 28 7 0 0 4 |
|---------------------------------------------------------------------------------|
12. | 2006 2014 12 1 1 66 11 19 5 7.833333 |
13. | 2011 2014 13 1 2 66 11 19 3 5.875 |
14. | 2012 2014 14 1 3 66 11 17 2 5.444445 |
15. | 2013 2014 15 1 4 66 11 11 1 5.5 |
|---------------------------------------------------------------------------------|
16. | 2015 2015 16 1 5 120 15 0 0 8 |
|---------------------------------------------------------------------------------|
17. | 2015 2016 17 1 5 136 16 16 1 8 |
+---------------------------------------------------------------------------------+
I'm trying to figure out if it's possible to transform table rows to columns where the number of rows included changes at the time of the query. Here's a sample of what I'm trying to do:
Characteristics Table
strategy
year
month
aaa
aa
a
InvestmentA
2020
12
5
4
10
InvestmentB
2020
12
8
15
25
Investment(n)
2020
12
x
x
x
Output
year
month
Credit Type
InvestmentA
InvestmentA
Investment(n)
2020
12
aaa
5
8
x
2020
12
aa
4
15
x
2020
12
a
10
25
x
I've a Matrix to show the values over the months. But the last column I want to show the Varianve between the current month and the previous month. I've this dataset (Months):
Servername Month Year Reference Value Previous_Value
SV1 8 2017 80 11 Null
SV1 9 2017 80 13 11
SV1 10 2017 80 18 13
SV1 11 2017 80 21 18
SV1 12 2017 80 12 21
SV1 1 2018 80 18 12
Basically, I want to build a expression that allows me to get the value from MAX(Month) and MAX(Year). I try this:
=IIF(Fields!Month.Value = max(Fields!Month.Value, "Months") and Fields!Year.Value = max(Fields!Year.Value, "Months"),Fields!Previous_Value.Value,0)
But when I run the report I'm getting 0 to all of my machines... And my final matrix are:
**Servername 8 9 10 11 12 1 Previous_Value**
SV1 11 13 18 21 12 18 12
How can I do this?
Thanks!
Your expression is saying if Month = MAX(Fields!Month.Value) which is 12 and Year = Max(Fields!Year.Value) which is 2018 then show Previous_Value.
As non of your rows match this then it won't work.
I've not tested this but try aggregating the month and year and comparing to that. This is easier to do in SQL by adding a new column
SELECT *, ([Year] *100) + [Month] as YearMonthKey FROM myTable
Now your expression can just check YearMonthKey against MAX(Fields!YearMonthKey.Value)
Let's say I have maximum temperature data for the last 20 years. My data frame has a column for month, day, year and MAX_C (temperature data). I want to calculate the mean (and standard deviation, and range) maximum temperature from June 31 of one year to July 1 of the preceding year (i.e. mean max daily temp from July 1, 1991 to June 31, 1992). Is there an efficient way to do this?
My approach, thus far, has been to create an array:
maxt.prev12<-tapply(maxt$MAX_C,INDEX=list(maxt$month,maxt$day,maxt$year),mean)
I put mean in as the function as tapply was not producing an array without a function after the INDEX, but mean is not actually calculating anything here. Then I was thinking about trying to take January through June from one the matrices (i.e. 1992), and July through December from the preceding matrix (i.e. 1991), and then computing the mean. I'm not entirely sure how to do that part, however, there must be a more efficient way of performing these calculations in R
EDIT
Here is a simple sample set of data
maxt
day month year MAX_C
1 1 1990 29
1 2 1990 28
1 3 1990 32
1 4 1990 26
1 5 1990 24
1 6 1990 32
1 7 1990 30
1 8 1990 28
1 9 1990 28
1 10 1990 24
1 11 1990 30
1 12 1990 30
1 1 1991 25
1 2 1991 26
1 3 1991 28
1 4 1991 25
1 5 1991 24
1 6 1991 32
1 7 1991 26
1 8 1991 32
1 9 1991 26
1 10 1991 26
1 11 1991 27
1 12 1991 26
1 1 1992 27
1 2 1992 25
1 3 1992 29
1 4 1992 32
1 5 1992 27
1 6 1992 27
1 7 1992 24
1 8 1992 25
1 9 1992 28
1 10 1992 26
1 11 1992 31
1 12 1992 27
I would create an "indicator year" column which was equal to the year if month in July-Dec but equal to year-1 when month in Jan-June.
EDITED month reference in light of the fact it was numeric rather than character:
> maxt$year2 <- maxt$year
> maxt[ maxt$month %in% 1:6, "year2"] <-
+ maxt[ maxt$month %in% 1:6, "year"] -1
> # month.name is a 12 element constant vector in all versions of R
> # check that it matches the spellings of your months
>
> mean_by_year <- tapply(maxt$MAX_C, maxt$year2, mean, na.rm=TRUE)
> mean_by_year
1989 1990 1991 1992
28.50000 27.50000 27.50000 26.83333
If you wanted to change the labels so they reflected the non-calendar year derivation:
> names(mean_by_year) <- paste(substr(names(mean_by_year),3,4),
+ as.character( as.numeric(substr(names(mean_by_year),3,4))+1),
sep="_")
> mean_by_year
89_90 90_91 91_92 92_93
28.50000 27.50000 27.50000 26.83333
Although I don't think it will be quite right at the millennial turn.
Ok I need to make this program to display "cal" 3 month(one month before and one month after) side by side, rather than just one single month it displays in any Linux/UNIX. I got it working to display 3 calendar by using "system(customCommand)" three times; but then it's not side by side.
I got some hint to use the following system calls:
close(..) pipe(..) dup2(..) read(..) and write(..)
my question is what should I start with? Do I need to create child process and than catch it in pipe(..)?
How can I display three calendar side by side.
ex.
February 2009 March 2009 April 2009
S M Tu W Th F S S M Tu W Th F S S M Tu W Th F S
1 2 3 4 5 6 7 1 2 3 4 5 6 7 1 2 3 4
8 9 10 11 12 13 14 8 9 10 11 12 13 14 5 6 7 8 9 10 11
15 16 17 18 19 20 21 15 16 17 18 19 20 21 12 13 14 15 16 17 18
22 23 24 25 26 27 28 22 23 24 25 26 27 28 19 20 21 22 23 24 25
29 30 31 26 27 28 29 30
Assuming you want to write it yourself instead of using "cal -3", what I'd do (in psuedo code):
popen three calls to "cal" with the appropriate args
while (at least one of the three pipes hasn't hit EOF yet)
{
read a line from the first if it isn't at EOF
pad the results out to a width W, print it
read a line from the second if it isn't at EOF
pad the results out to a width W, print it
read a line from the third if it isn't at EOF
print it
print "\n"
}
pclose all three.
if "cal -3" doesn't work, just use paste :)
$ TERM=linux setterm -regtabs 24
$ paste <(cal 2 2009) <(cal 3 2009) <(cal 4 2009)
febbraio 2009 marzo 2009 aprile 2009
do lu ma me gi ve sa do lu ma me gi ve sa do lu ma me gi ve sa
1 2 3 4 5 6 7 1 2 3 4 5 6 7 1 2 3 4
8 9 10 11 12 13 14 8 9 10 11 12 13 14 5 6 7 8 9 10 11
15 16 17 18 19 20 21 15 16 17 18 19 20 21 12 13 14 15 16 17 18
22 23 24 25 26 27 28 22 23 24 25 26 27 28 19 20 21 22 23 24 25
29 30 31 26 27 28 29 30
$
(setterm ignores -regtabs unless TERM=linux or TERM=con.)
just do
cal -3
Does this not work?
cal -3
Ok, how about cal -3?
cal -3 12 2120 to make it a special month and year, with one before and one after.
The approach I would use for this would be to capture the output, split it into lines, and printf the lines out next to each other. I'd probably do it in Perl, though, rather than C.
Or just use cal -3, if your cal has it.