Good Day All!
I have a batch script, and when I echo a variable like this
echo %variable1%
I get out put like this
TestLine1
TestLine2
TestLine3
TestLine4
My goal would be to modify this variable to remove all the newline characters so the output would look more like
TestLine1TestLine2TestLine3TestLine4
Is there a simple way to do this without creating files?
Thank you for your assistance.
You can use the command tr:
cleanedVariable1=$(echo $variable1 | tr -d '\n' )
echo $cleanedVariable1
The command tr removes or translates characters. The option -d removes the given characters. In this case, we are removing all new lines from our variable and assign it to a new variable.
Related
I'm stucked on a bash script.
I'm having a config.ini files like this :
#Username
username=user
#Userpassword
userpassword=password
And i'm looking in a bash script to extract this information and put it in a associative array. My script looks like :
declare -A array
OIFS=$IFS
IFS='='
grep -vE '^(\s*$|#)' file | while read -r var1 var2
do
array+=([$var1]=$var2)
done
echo ${array[#]}
But the array seems to be empty because the commande echo ${array[#]} gives no output.
Any idea why me script don't work ? Thanks for your help and sorry for my bad english.
Common error - "grep | while" causes the while loop to be executed in a separate shell and the variables inside the loop are not global to your shell. Use a here string instead:
while read -r var1 var2
do
array+=([$var1]=$var2)
done <<< $(grep -vE '^(\s*$|#)' file)
Assuming the file can be trusted (ie the content is regulated and known), the simplest method would be to source the ini file and then directly use the variable names within the script:
. config.ini
You can either use the period (.) as above or the source builtin command
I am trying to make a array/list from a bash output and then I want to for loop it. I keep on getting Syntax error: "(" unexpected (expecting "done"). If I had to put it in python term, I want to break the string up by \n and then for loop it.
IFS=$'\n'
DELETE = ($($MEGACOPY --dryrun --reload --download --local $LOCALDIR --remote $REMOTEDIR | sed 's|F '$LOCALDIR'|'$REMOTEDIR'|g'))
unset IFS
# And remove it
for i in $DELETE; do
$MEGARM $i
done
First, shell is not python. Spaces around equal signs don't work:
DELETE = ($($MEGACOPY --dryrun --reload --download --local $LOCALDIR --remote $REMOTEDIR | sed 's|F '$LOCALDIR'|'$REMOTEDIR'|g'))
When the shell sees the above, it interprets DELETE as a program name and = as its first argument. The error that you see is because the shell was unable to parse the second argument.
Replace the above with:
DELETE=($("$MEGACOPY" --dryrun --reload --download --local "$LOCALDIR" --remote "$REMOTEDIR" | sed 's|F '"$LOCALDIR"'|'"$REMOTEDIR"'|g'))
Second, regarding the for loop, DELETE is an array and arrays have special syntax:
for i in "${DELETE[#]}"; do
"$MEGARM" "$i"
done
Notes:
Unless you want word splitting and pathname expansion, all shell variables should be inside double-quotes.
It is best practices to use lower or mixed case for variable names. The system uses all upper case variables for its name and you don't want to accidentally overwrite one of them.
My data set(data.txt) looks like this [imageID,sessionID,height1,height2,x,y,crop]:
1,0c66824bfbba50ee715658c4e1aeacf6fda7e7ff,1296,4234,194,1536,0
2,0c66824bfbba50ee715658c4e1aeacf6fda7e7ff,1296,4234,194,1536,0
3,0c66824bfbba50ee715658c4e1aeacf6fda7e7ff,1296,4234,194,1536,0
4,0c66824bfbba50ee715658c4e1aeacf6fda7e7ff,1296,4234,194,1536,950
These are a set of values which I wish to use. I'm new to shell script :) I read the file line by line like this ,
cat $FILENAME | while read LINE
do
string=($LINE)
# PROCESSING THE STRING
done
Now, in the code above, after getting the string, I wish to do the following :
1. Split the string into comma separated values.
2. Store these variables into arrays like imageID[],sessionID[].
I need to access these values for doing image processing using imagemagick.
However, I'm not able to perform the above steps correctly
set -A doesn't work for me (probably due to older BASH on OSX)
Posting an alternate solution using read -a in case someone needs it:
# init all your individual arrays here
imageId=(); sessionId=();
while IFS=, read -ra arr; do
imageId+=(${arr[0]})
sessionId+=(${arr[1]})
done < input.csv
# Print your arrays
echo "${imageId[#]}"
echo "${sessionId[#]}"
oIFS="$IFS"; IFS=','
set -A str $string
IFS="$oIFS"
echo "${str[0]}";
echo "${str[1]}";
echo "${str[2]}";
you can split and store like this
have a look here for more on Unix arrays.
I have a file (my_ID_file) of IDs, one ID per line, no other excess white white spaces. it was created from using the cut command form another file. the file looks like 101 lines of this...
PA10
PA102
PA103
PA105
PA107
PA109
I am trying to use these IDs in a for loop to create a directory structure. so I use the readarray function as such to create the array...
readarray TIDs < my_ID_file
and then use a for loop as such to create the directory structure...
for T in "${TIDs[#]}"
do
mkdir "$T"_folder
done
this produces directories named....
PA10?_folder
PA102?_folder
PA103?_folder
PA105?_folder
PA107?_folder
PA109?_folder
If however I declare the array manually like....
TIDs=(PA10 PA102 PA103 PA105 PA107 PA109)
and then run the for loop I get the correct directory structure produced like....
PA10_folder
PA102_folder
PA103_folder
PA105_folder
PA107_folder
PA109_folder
Where are these question marks coming from? how can i declare arrays from files like this without having this question mark appearing in subsequent use of the array?
Thanks
Your text file has DOS-style line endings. The "?" appear because the carriage returns would mess up ls output. Try od -c my_ID_file
Solution: dos2unix my_ID_file
take #2: readarray does not remove the line's newline by default. You really want
readarray -t TIDs < my_ID_file
reference: http://www.gnu.org/software/bash/manual/bashref.html#index-mapfile
This is my code:
grep $to_check $forbidden >${dir}variants_of_interest;
cat ${dir}variants_of_interest | (while read line; do
#process ${line} and echo result
done;
)
Thank to grep I get lines of data that I then process separately in loop. I would like to use variable instead of using file variants_of_interest.
Reason for this is that I am afraid that writing to file thousands of time (and consequently reading from it) rapidly slows down computation, so I am hoping that avoiding writing to file could help. What do you think?
I have to do thousands of grep commands and variants_of_interest contains up to 10 lines only.
Thanks for your suggestions.
You can just make grep pass its output directly to the loop:
grep "$to_check" "$forbidden" | while read line; do
#process "${line}" and echo result
done
I removed the explicit subshell in your example, since it is already in a separate one due to the piping. Also don't forget to quote the $line variable to prevent whitespace expansion on use.
You dont have to write a file. Simply iterate over the result of grep:
grep $to_check $forbidden | (while read line; do
#process ${line} and echo result
done;
)
This might work for you:
OIFS="$IFS"; IFS=$'\n'; lines=($(grep $to_check $forbidden)); IFS="$OIFS"
for line in "${lines[#]}"; do echo $(process ${line}); done
The first line places the results of the grep into the variable array lines.
The second line processes the array lines placing each line into the variable line