C programming array swap [closed] - c

Question

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 5 years ago.
Improve this question
I have been trying to do this for 4 hours with no luck and I really need to have it done. It is my school's task.
#include <stdio.h>
#include <stdlib.h>
int main() {
char strings[5][5][5][5][5];
char *temp[5];
int b[5];
int a[5];
int x;
int i;
int z;
int a_value;
int b_value;
//get 5 strings from the input
for (i = 0; i < 5; i++) {
scanf("%s", strings[i]);
}
//Get 5 numbers from the input
for (x = 0; x < 5; x++) {
scanf("%d %d", & b[x], & a[x]);
//printf("B is %d and A is %d\n", b[x], a[x]);
a_value = a[x];
b_value = b[x];
temp[b_value] = strings[a_value];
//If the values of a and b are equal to -1 denote the operation (end it)
if (b[x] == -1 && a[x] == -1) {
break;
}
}
//Get the swapped values
for (z = 0; z<=x; z++) {
printf("%s\n", temp[z]);
}
return 0;
}
Input:
aadf
bazz
abkt
bbaa
zzzz
1 3
0 4
3 2
-1 -1
The output is supposed to be like this
zzzz
bbaa
bazz
abkt
aadf
What I get is this
zzzz
bbaa
abkt
So everything works fine and strings get replaced based on that but the problem is that if b and a are not given so the swapped value should be the normal value and I don't know how to do it.
The task exactly says:
Read 5 strings from standard input and put them in an array. Each string is 4 characters length. Then prepare a function, that swaps i-th and j-th elements of the array. Indexes of i and j are given as standard input as two numbers separated by space. There can be more than one operations - each swap operation is separated by new line. Values -1 and -1 denote the end of operations. Print strings separated by new line.
Please help me and thanks ;)

Answer 1

Why 5D array, char strings[5][5][5][5][5] ? you just want to 5 strings as input So for this take 2D array
char strings[5][4];// total 5 strings , in each you can stores 4 characters.
Next things How will you scan data for 2D arrays, you need to rotate two loops namely for rows and columns . Assume row = 5 & col = 4
for (i = 0; i < row; i++) {
for(j = 0; j < col; j++) {
scanf("%c", &strings[i][j]);
}
}
Next this temp[b_value] = strings[a_value]; statement you need to modify, modify according your requirement.
I hope this helps.

Answer 2

Here's you code, corrected and optimized:
#include <stdio.h>
#include <stdlib.h>
int main() {
char strings[5][5];
char temp[4];
int x,y;
//get 5 strings from the input
for (int i = 0; i < 5; i++) {
scanf("%s", strings[i]);
}
do{
scanf("%d %d", & x, & y);
// Assign string[x] to temp
for(int i=0;i<4;i++){
temp[i] = strings[x][i];
}
// Assign string[y] to string[x]
for(int i=0;i<4;i++){
strings[x][i] = strings[y][i];
}
// Assign temp to string[y]
for(int i=0;i<4;i++){
strings[y][i] = temp[i];
}
}while(x!=-1 && y!=-1);
//Get the swapped values
for (int i = 0; i< 5; i++) {
printf("%s\n", strings[i]);
}
return 0;
}
I have tested it. Let me know if you need any explanation.