Looking Time windows for 24 Hr interval - sql-server

I am executing below query in SQL Server 2012
print dateadd(day,datediff(day,1,getdate()),0)
print dateadd(day,datediff(day,0,getdate()),0)
and getting below result
Nov 9 2017 12:00AM
Nov 10 2017 12:00AM
But i am looking result like below
Nov 9 2017 12:00AM
Nov 10 2017 11:59PM
Please help !!


You would seem to want:
print cast(getdate() as date);
print dateadd(minute, -1, dateadd(day, 2, cast(getdate() as date)))
Or, alternatively:
print cast(getdate() as date);
print dateadd(minute, 2*24*60-1, cast(getdate() as date))

Related

Obtaining the date of 2 Saturdays ago and Last Friday

How can I obtain the date of 2 Fridays ago and 2 Saturdays ago (SQL Server 2012+)
For example,
if run today, Monday Oct 12, my query should result in Sat Oct 3 and Friday Oct 9
if run on Tuesday Oct 20, my dates should be Sat Sat Oct 10 and Friday Oct 16
I am looking for an answer like select xyz getdate() ....

#Andresbi, your examples states 2 Saturdays before and 1 Friday before.
I think this code gives you the result:
declare #dt datetime = '20201020'
select
(
/* Previous sunday */
#dt - datepart(dw, #dt) + 1
/* Previous saturday */
- 1
/* and the saturday before */
- 7
),
(
/* Previous sunday */
#dt - datepart(dw, #dt) + 1
/* Previous friday */
- 2
)

select dateadd(day, -08, dateadd(wk, datediff(wk, 0, getdate()), 0))
select dateadd(day, -10, dateadd(wk, datediff(wk, 0, getdate()), 0))

rolling less than 13 months in sql

I have a very tricky question here. I know how to write a rolling months in SQl but the thing now is how can i write rolling less than 13 months. For example : How should i write rolling months for less than 13 months. for example April 1 2018 to march 21 2017. I know how to write rolling months like april 18 to april 17 or march 17. If someone can help me with this that would be great. Thanks!!
DECLARE #Date DATE
declare #BeginDate varchar(100)
declare #EndDate varchar(100)
SELECT #BeginDate = DATEADD(MONTH, -12, CAST(dateadd(d,-(day(getdate()-1)),getdate()) AS date))
SELECT #EndDate = CAST(dateadd(d,-(day(getdate())),getdate()) AS DATE)

If you're using SQL Server, try this.
SELECT DATEADD(dd, 1, EOMONTH(DATEADD(mm, -14, GETDATE()))) AS StartOfMonth
SELECT EOMONTH(DATEADD(mm, -1, GETDATE())) AS EndOfMonth

Query last 12 months of data where year and month are separate columns

I'm trying to figure out a way to query the last 12 completed months of data, so it would go up to last month and ignore this month.
I've done this before when the table had a date column, but this new table I'm working with separates the date into two month and year columns.
How would I go about this in SQL Server 2012?
Thanks in advance.
SAMPLE DATA:
CalendarYear CalendarMonth TotalSales
2014 3 35.00
2014 4 220.00
2015 2 243.00
2015 5 17.93
2015 6 216.36
2015 10 370.93
2015 12 350.00
2016 1 116.75
2016 2 13.78
DESIRED OUTPUT (assuming current time is in February 2016):
CalendarYear CalendarMonth TotalSales
2015 2 243.00
2015 5 17.93
2015 6 216.36
2015 10 370.93
2015 12 350.00
2016 1 116.75

I've assumed the Day part is always the 1st of the month.
WHERE
CONVERT(DATETIME, CalendarYear + '-' + CalendarMonth + '- 01') >= DATEADD(mm, -12, GETDATE())
The above assumes the columns are strings. Below I've done a version where the columns are numbers.
WHERE
CONVERT(DATETIME, CAST(CalendarYear AS NVARCHAR(4)) + '-' + CAST(CalendarMonth AS NVARCHAR(2)) + '-01') >= DATEADD(mm, -12, GETDATE())

You can just apply same code/logic to year and month you want data.
where to_date(year || month, 'YYYYMM')
between add_months(trunc(sysdate, 'MM'), -12) and trunc(sysdate)

Get last 6 months monthname.month number and Years in simple select statement

How to get last 6 months month name, month number and Years in simple select statement in sqlserver .
The no of months is 6, and is fixed
12 Dec 2015
11 Nov 2015
10 Oct 2015
9 Sep 2015
8 Aug 2015
7 Jul 2015
6 Jun 2015
This should handle year end boundaries
say, if the current month is Feb 2016, the result should give 2015 months.
2 Feb 2016
1 Jan 2016
12 Dec 2015
11 Nov 2015
10 Oct 2015
9 Sep 2015
8 Aug 2015

You can do it with the following:
SELECT MONTH(DATEADD(mm, -m, GETDATE())) AS m,
LEFT(DATENAME(mm, DATEADD(mm, -m, GETDATE())), 3) AS n,
YEAR(DATEADD(mm, -m, GETDATE())) AS y
FROM (VALUES (0),(1),(2),(3),(4),(5),(6)) t(m)
Output:
m n y
12 Dec 2015
11 Nov 2015
10 Oct 2015
9 Sep 2015
8 Aug 2015
7 Jul 2015
6 Jun 2015

Try this
;with cte as
(
select 0 as num
union all
select num+1 from cte where num<6
)
select month(dates),datename(month,dates),year(dates)
from
(
select dateadd(mm,-num,datadd(dd,1,eomonth(getdate(),-1))) as dates
from cte
) A
SQL FIDDLE DEMO

select datepart(m,GETDATE()) MonthNumber,left(datename(month,GETDATE()),3) as Month,year(GETDATE()) as Year union all
select datepart(m,DATEADD(month,-1,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-1,GETDATE())),3) as Month,year(DATEADD(month,-1,GETDATE())) as Year union all
select datepart(m,DATEADD(month,-2,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-2,GETDATE())),3) as Month,year(DATEADD(month,-2,GETDATE())) as Year union all
select datepart(m,DATEADD(month,-3,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-3,GETDATE())),3) as Month,year(DATEADD(month,-3,GETDATE())) as Year union all
select datepart(m,DATEADD(month,-4,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-4,GETDATE())),3) as Month,year(DATEADD(month,-4,GETDATE())) as Year union all
select datepart(m,DATEADD(month,-5,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-5,GETDATE())),3) as Month,year(DATEADD(month,-5,GETDATE())) as Year union all
select datepart(m,DATEADD(month,-6,GETDATE())) MonthNumber,left(datename(month,DATEADD(month,-6,GETDATE())),3) as Month,year(DATEADD(month,-6,GETDATE())) as Year
The above query will work for most of the RDBMS.
For SQL Server specific use the below query.
SELECT MONTH(DATEADD(month, -month, GETDATE())) AS MonthNumber ,
LEFT(DATENAME(MONTH, DATEADD(month, -month, GETDATE())), 3) AS MonthName,
YEAR(DATEADD(month, -month, GETDATE())) AS Year
FROM ( VALUES (0), (1), (2), (3), (4), (5),(6) ) t ( month )

Try DATEADD:
Select * FROM Table where YourDate>=DATEADD(m, -6, GETDATE())

Format date to include day of week

I have a SQL Server 2012 query that converts date to VARCHAR
SELECT
CONVERT(VARCHAR(12), dbo.Download.Date_of_Download, 107) as Date_to_Display,
dbo.Download.Number_of_Computers
FROM dbo.Download
ORDER BY dbo.Download.Date_of_Download DESC
Below are results
Date_to_Display Number_of_Computers
-----------------------------------
Aug 14, 2014 240
Aug 13, 2014 519
Aug 12, 2014 622
Aug 11, 2014 2132
Aug 10, 2014 1255
Aug 09, 2014 3240
How do I include day of week, i.e. Saturday, Aug 09, 2014 ?

try this:
select datename(dw,getdate())
output:
------------------------------
Thursday
(1 row(s) affected)
using your query:
SELECT
Datename(dw, dbo.Download.Date_of_Download)+', '+CONVERT(VARCHAR(12), dbo.Download.Date_of_Download, 107) as Date_to_Display,
dbo.Download.Number_of_Computers
FROM dbo.Download
ORDER BY dbo.Download.Date_of_Download DESC

In SQL Server version 2012 and later, there is the FORMAT TSQL function that can do what you want. The "dddd" portion does day of the week:
SELECT
FORMAT(dbo.Download.Date_of_Download, 'dddd MMM dd, yyyy') as Date_to_Display,
dbo.Download.Number_of_Computers
FROM dbo.Download
ORDER BY dbo.Download.Date_of_Download DESC
MS docs: https://learn.microsoft.com/en-us/sql/t-sql/functions/format-transact-sql

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