Reverse the output of printf function in while loop - c

Question

I wrote a code for a b-adic representation of a chosen number.
#include <stdio.h>
int b_adisch (int a, int b)
{
int x, y, mod, mod1;
x = a / b;
mod1 = a % b;
printf("%i\n", mod1);
do {
y = x / b;
mod = x % b;
x = y;
printf("%i\n", mod);
} while(x != 0);
return a ;
}
int main (void)
{
int a, b;
printf("pls input a ");
scanf("%i", &a);
printf("pls input b ");
scanf("%i", &b);
b_adisch(a, b);
return 0;
}
The output order will be reversed
since the printf has to be put into the while loop and the calculation starts with the last number of the representation.
Example if a = 10 and b = 2
The output is 0101
but it should be 1010
How can I change my code to make this happen?

Answer 1

How can i change my code to make this happen?
2 approaches:
Compute the digits from least to most significant and save in a adequate sized buffer. This is similar to OP's approach yet saves the results of each digit's computation for later printing.
#include <assert.h>
#include <limits.h>
void b_adisch(int value, int base) {
// Let us work with simple cases first.
assert(value >= 0);
assert(base >= 2 && base <= 10);
// Adequate sized buffer
char buffer[sizeof value * CHAR_BIT + 1];
// Start at end
char *end = &buffer[sizeof buffer - 1];
*end = '\0';
do {
end--;
int digit = value%base; // Find least digit
value /= base;
*end = digit + '0'; // save the digit as text
} while (value);
printf("<%s>\n", end); // print it as a string
}
Use recursion. A more radical change; This computes and prints the output of the more significant digits first.
void b_adischR_helper(int value, int base) {
// If the value is at least 2 digits, print the most significant digits first
if (value >= base) {
b_adischR_helper(value/base, base);
}
putchar(value % base + '0'); // Print 1 digit as text
}
void b_adischR(int value, int base) {
// Let us work with simple cases first.
assert(value >= 0);
assert(base >= 2 && base <= 10);
printf("<");
b_adischR_helper(value, base);
printf(">\n");
}
Test
int main() {
b_adisch(10, 2);
b_adischR(10, 2);
b_adisch(INT_MAX, 10);
b_adischR(INT_MAX, 10);
b_adisch(INT_MAX, 2);
b_adischR(INT_MAX, 2);
}
Output
<1010>
<1010>
<2147483647>
<2147483647>
<1111111111111111111111111111111>
<1111111111111111111111111111111>

Answer 2

You can store the output in an array as here it is stored in "arr" and later print the output in reverse order (from end to start).
#include <stdio.h>
int arr[10000]={0};
void b_adisch (int a, int b)
{
int x, y, mod, mod1,i=0,j;
x = a / b;
mod1 = a % b;
arr[i++]=mod1;
do {
y = x / b;
mod = x % b;
x = y;
arr[i++]=mod;
} while(x != 0);
for(j=i-1;j>=0;j--)
printf("%i\n",arr[j]);
}
int main (void)
{
int a, b;
printf("pls input a ");
scanf("%i", &a);
printf("pls input b ");
scanf("%i", &b);
b_adisch(a, b);
return 0;
}