I'm trying to run a program in C on my mac that asks the user to input a set of names. The program then sorts and capitalizes all the names and prints them capitalized and sorted. It then allows the user to search for a name. However, most of the time (but not every time) I try to run the code it returns a segmentation fault: 11 error. My guess is that the problem has something to do with fgets or my array but I don't really know.
Here's my code:
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#define SIZE 50
#define LENGTH 50
#define TRUE 1
#define FALSE 0
void printList(char names[SIZE][LENGTH], int length);
void toUpperCase(char names[SIZE][LENGTH], int length);
void sort(char names[SIZE][LENGTH], int length);
void startSearch(char names[SIZE][LENGTH], int length);
int binSearch(char names[SIZE][LENGTH], int l, int r, char x[LENGTH]);
int main(void){
char names[SIZE][LENGTH]; //stores the list of names
printf("Enter student names (q to stop)...\n");
int i = 0;
do {
printf("Student name #%d: ", i);
fgets(names[i], LENGTH, stdin); //fill the list of names
int len = strlen(names[i])-1; //fgets includes \n character
if(names[i][len] == '\n') //if the last character is \n
names[i][len] = '\0'; //change it to \0
if(strcmp(names[i], "") == 0)
printf("Invalid input: Type a name\n");
else
i++;
}
while(strcmp(names[i-1],"q")!=0 && i<SIZE); //Stop collecting names after input "q"
//or if the names array is full
int length = i-1; //# of names in the names array
sort(names, length);
toUpperCase(names, length);
printList(names, length);
startSearch(names, length);
printf("Done!\n");
return 0;
}
//Converts all the names in the names array to upper case
void toUpperCase(char names[SIZE][LENGTH], int length){
for(int i = 0; i < length; i++){
for(int j = 0; names[i][j]!='\n'; j++){
if(islower(names[i][j]))
names[i][j] = toupper(names[i][j]);
}
}
}
//sorts the names in the names array (bubble sort)
void sort(char names[SIZE][LENGTH], int length){
int i, j;
char temp[LENGTH];
for (i = 0; i < length-1; i++)
for (j = 0; j < length-i-1; j++)
if (strcmp(names[j],names[j+1])>0){
strcpy(temp, names[j]);
strcpy(names[j], names[j+1]);
strcpy(names[j+1], temp);
}
}
//prints the names in the names array
void printList(char names[SIZE][LENGTH], int length){
printf("Student list: [\n");
for(int i = 0; i < length; i++)
if(i == length-1)
printf("\t%s\n", names[i]);
else
printf("\t%s,\n", names[i]);
printf("]\n");
}
//The first method for searching the list
void startSearch(char names[SIZE][LENGTH], int length){
char search[LENGTH];
while(strcmp(search, "q")!=0){
printf("Enter a name to search (q to exit): ");
fgets(search, LENGTH, stdin); //gets the name to search
int len = strlen(search)-1;
if(search[len] == '\n')
search[len] = '\0';
if(strcmp(search, "q") == 0) //if entered value is q
break; //break out of the loop
//Since the list is all upper case change the search value to upper case
for(int j = 0; search[j]!='\n'; j++){
if(islower(search[j]))
search[j] = toupper(search[j]);
}
printf("Searching for %s ...\n", search);
// if binSearch returns true then the item is in the list
if(binSearch(names, 0, length-1, search) == TRUE)
printf("%s is in the list!\n", search); /
else
printf("%s is NOT in the list!\n", search);
}
}
//binary search for the names array
int binSearch(char names[SIZE][LENGTH], int l, int r, char x[LENGTH]){
while (l <= r)
{
int m = l + (r-l)/2;
if(strcmp(names[m], x) == 0)
return TRUE;
if(strcmp(names[m], x) < 0)
l = m + 1;
else
r = m - 1;
}
return FALSE;
}
I assume you're using fixed arrays of SIZE and LENGTH for learning purposes. For actual string-related work, you'd do well to heed kpra's advice and using the more complex, but more powerful, pointers (allocating them and deallocating at need).
In your reading loop you kill all the "\n"'s replacing them with zeroes.
Yet in your toUppercase() code you look for a "\n" instead of a 0x0. This risks blowing the buffer:
//Converts all the names in the names array to upper case
void toUpperCase(char names[SIZE][LENGTH], int length){
for(int i = 0; i < length; i++){
for(int j = 0; names[i][j]!='\n'; j++){
// what happens here if \n is not found and j exceeds SIZE?
if(islower(names[i][j]))
names[i][j] = toupper(names[i][j]);
}
}
}
You could replace \n with 0x0, but I think a safer loop would be:
for(int j = 0; j < SIZE; j++) {
if (yourstring[j] == 0) {
break;
}
This way you're sure never to overshoot SIZE, and the cycle is ended anyway if the end of string is found. Notice that this '\n' comparison is used also in the search loop.
Related
I have made one program, where you enter a few characters (10 max). It makes you a list, count average length of surnames, tell about how much different names. But the problem is, when I enter the last number (10) - it sorts me it incorrectly (like 39399349349, 3443993). Beneath I will present my code. I am newbie in C, so please don't shut on me) I am convinced that sorting function is incorrect, but don't know what exactly(
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct people {
int num[10];
char surname[20];
char name[10];
} peoples[10], c;
int compare_people_num(const void *a, const void *b);
int main()
{
int i, j, k = 0, l = 0, m = 0, n = 0;
float s = 0;
char str[100];
system("chcp 1251 > nul");
for (i = 0, j = 0; i < 10; i++, j++)
{
printf("Enter number, surname, name %d of your human: ", i + 1);
fgets(str, sizeof str, stdin);
sscanf(str, "%d %s %s", &peoples[j].num, &peoples[j].name, &peoples[j].name);
while (str[n] != '\n')
{
if (str[n] != ' ')
{
peoples[j].num[k] = str[n];
}
else
break;
n++;
k++;
}
n++;
k = 0;
while (str[n] != '\n')
{
if (str[n] != ' ')
{
peoples[j].surname[k] = str[n];
}
else
break;
n++;
k++;
}
n++;
k = 0;
while (str[n] != '\n')
{
if (str[n] != '\0')
{
peoples[j].name[k] = str[n];
}
else
break;
n++;
k++;
}
n = 0;
k = 0;
}
for (i = 0; i < 10; i++)
{
for (j = i + 1; j < 10; j++)
{
if (!strcmp(peoples[i].name, peoples[j].name))
m = 1;
}
if (m == 0)
l++;
m = 0;
s = s + strlen(peoples[i].surname);
}
for (i = 0; i < 9; i++)
for (j = 0; j < 9; j++)
if (strcmp(peoples[j].num, peoples[j+1].num) > 0)
{
qsort(peoples, 10, sizeof(struct people), &compare_people_num);
}
for (i = 0; i < 10; i++)
{
printf("%d ", peoples[i].num);
printf("%s ", peoples[i].name);
printf("%s ", peoples[i].surname);
printf("\n");
}
printf("\nYou have %d different names\n", l);
printf("Avarege lenght of surname is = %f\n", s / 10);
}
int compare_people_num(const void *a, const void *b)
{
const struct people *p1 = a;
const struct people *p2 = b;
return p1->num - p2->num; // Change order to reverse sort
}
I went through your code and removed things that weren't needed. In both your input and sorting, it seemed like you were doing things twice. I tried to document the changes I made and explain why they should be made.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
// It's generally a good idea to use #define when you have some global constants
// I made some of the constants larger than what you showed to prevent issues
#define MAX_NAME_LEN 40
#define MAX_SURNAME_LEN 40
#define NUM_PEOPLE 10
#define BUFF_LEN 100
// Separate your struct...
struct person {
int num;
char name[MAX_NAME_LEN];
char surname [MAX_SURNAME_LEN];
};
// ... and array decleration
static struct person people[NUM_PEOPLE];
// I added this function, to make it easier to display a person
void print_person (const struct person * p) {
printf("Person %d %s %s\n", p->num, p->name, p->surname);
}
// This function will print out every person in the people array
void print_people (void) {
for (int i=0; i<NUM_PEOPLE; i++) {
print_person(&people[i]);
}
}
// Compares two people by number
int compare_people_num (const void * a, const void * b) {
struct person * p0 = (struct person *) a;
struct person * p1 = (struct person *) b;
return p0->num - p1->num;
}
// Compares two people by name
int compare_people_name (const void * a, const void * b) {
struct person * p0 = (struct person *) a;
struct person * p1 = (struct person *) b;
return strcmp(p0->name, p1->name);
}
int main (void) {
int i;
char buffer[BUFF_LEN];
for (i=0; i<NUM_PEOPLE; i++) {
printf("Enter number, surname, and name of person %d: ", i+1);
fflush(stdout); // fflush makes sure that our text is shown to the user
fgets(buffer, BUFF_LEN, stdin); // Read user input in to buffer
// It's unclear what you were doing here
// This sscanf line takes a line of text, and splits it into a number and two words
// It then stores that number in people[i].num, and stores the words in name and surname
// However, right after this, you have several while loops that appear to be manually doing the same
// thing all over again. If you want to read all of the input in, just the line below is enough
sscanf(buffer, "%d %s %s", &people[i].num, people[i].name, people[i].surname);
}
// We've read all of the people in now
// Uncomment the next line to check out the output at this state:
// print_people();
// To count names, we first need to sort the people by their name
// We do this using a qsort call
qsort(people, NUM_PEOPLE, sizeof(struct person), compare_people_name);
// Once the names are sorted, we'll calculate how many different names there are
// We start the count at 1, and start checking from the second person (index 1)
// This is because the first person will always be unqiue, and we can't compare to
// person negative 1
int n_names = 1;
for (i=1; i<NUM_PEOPLE; i++) {
char * current = people[i].name;
char * previous = people[i-1].name;
if (!strcmp(current, previous)) {
n_names ++;
}
}
// Now we have to sort the people based on their num field
// Again, in your code, it looked like you were doing this more than nessecary
// We just have to call qsort once, as such
qsort(people, NUM_PEOPLE, sizeof(struct person), compare_people_num);
// We will also do a loop through to calculate the average surname length
float avg_surname_len = 0;
for (i=0; i<NUM_PEOPLE; i++) {
avg_surname_len += (float)strlen(people[i].surname);
}
avg_surname_len /= (float)NUM_PEOPLE;
// We're all done! The people are sorted by number.
print_people();
printf("There are %d unique names\n", n_names);
printf("The average surnames is %f characters\n", avg_surname_len);
}
I have to code in an array that can count an element. For example, if the user enters a 2, 2, 2, 1,1 then the user wants to count the number 2 then the result will be ELEMENT is 2 and FREQUENCY is 3. but I have a problem with the parts of " ENTER THE NUMBER YOU WANT TO BE COUNTED". I use scanf but when I run it I cannot enter any number.
Here's my code:
void frequency()
{
system("cls");
int num;
int count=0;
printf("Enter a number you want to be count: \n ");
scanf("i%", &num);
printf(" ELEMENT | FREQUENCY \n ");
for (i = 0; i<=n; i++)
{
if (a[i]==a[num])
count++;
}
printf(" \n %i ", num);
printf(" \t\t");
printf("%i \n ", count);
getch();
}
Your program requires understanding on two parts:
Get input and split input by delimiter, which can be done by using strtok.
Algorithm for finding the duplicated elements in an array.
#include <stdio.h>
#include <string.h>
int main() {
frequency();
return 0;
}
void frequency() {
char str[100];
printf("Enter a number you want to be count: \n ");
gets(str);
int init_size = strlen(str);
char delim[] = " ";
char *ptr = strtok(str, delim);
char *pch;
int arr[20];
int count = 0;
int ncount, i, j;
int a[count], Freq[count];
while(ptr != NULL) {
/*printf("'%s'\n", ptr);*/
/*Converts the string argument str to an integer (type int)*/
arr[count] = atoi(ptr);
/*strtok accepts two strings - the first one is the string to split, the second one is a string containing all delimiters*/
ptr = strtok(NULL, delim);
/*Initialize frequency value to -1*/
Freq[count] = -1;
count += 1;
}
/*Count the frequency of each element*/
for (i = 0; i < count; i++) {
ncount = 1;
for(j = i + 1; j < count; j++) {
/*Part to perform checking for duplicate elements*/
if(arr[i] == arr[j]) {
ncount++;
/*Make sure not to count frequency of same element again*/
Freq[j] = 0;
}
}
/*If frequency of current element is not counted*/
if(Freq[i] != 0) {
Freq[i] = ncount;
}
}
printf(" ELEMENT | FREQUENCY \n");
printf("-------------------------\n");
for (i = 0; i < count; i++) {
if(Freq[i] != 0) {
printf("\t%d\t\t\t%d\n", arr[i], Freq[i]);
}
}
}
Also, from your code:
You did not define i and n, which is required by your for loop. Also, since your for loop is for (i = 0; i<=n; i++), you have to define the value of n, which is the length of elements inputted by the user, in order to loop through the number of elements you expected.
int i, n, num;
...
...
for (i = 0; i<=num; i++)
Your scanf("i%", &num); should be scanf("%i", &num); instead.
You did not initialize your array a. You should have this line of code before assigning values to your array a. The value 20 can be adjusted by yourself depending on how many inputs are expected. Also, it can be coded in a flexible way instead of hardcoded as 20.
...
int i, num;
int count=0;
int a[20];
...
...
Lastly, it is a good practice to include the function's library before using it. In your case, you should include #include <conio.h> to use the getch() function.
I am trying to change the sorting of a the arr list which could consist of zero, one, two as the inputted and stored values for arr. The stringreplace function is meant to shift every single element by one so the new sorting would be one, two, zero. I am trying to replace the elements with one another by using the strncpy function but I think it is a bit faulty, how could i fix this?
strncpy function
char stringreplace( char a[], int b){
for(int j = 0; j > b -1; j++){
strncpy(a[j], a[j+1], sizeof(a));}
for(int j = 0; j > b; j++){
printf("%s",a[j]);}
}
main function
int main()
{
char input[100];
char arr[100]= {0};
int number;
printf("Input the number of strings: ");
scanf("%d", &number);
for(int i= 0; i < number; i++){
printf("Input the number of strings: ");
scanf("%s", input);
arr[i] = input;
}
stringreplace(arr, number);
return 0;
}
You may consider allocating strings dynamically, assigning a pointer for each string into an array words, and then rotating each pointer in the array to the left.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void lrot_words(char *words[], int n);
int main(void)
{
char *p, word[100], *words[100];
int i, num_words;
printf("Enter the number of words: ");
scanf("%d", &num_words);
for(i = 0; i < num_words; i++){
printf("Enter a word: ");
scanf("%s", word);
if ((p = malloc(strlen(word) + 1)) == NULL) {
fprintf(stderr, "Error: malloc failed\n");
exit(EXIT_FAILURE);
}
words[i] = strcpy(p, word);
}
lrot_words(words, num_words);
for (i = 0; i < num_words; i++) {
printf("%s\n", words[i]);
}
return 0;
}
void lrot_words(char *words[], int n)
{
char *temp = words[0];
int i;
for (i = 0; i < n - 1; i++) {
words[i] = words[i+1];
}
words[i] = temp;
}
As stated in the title I am trying to find all lower-case letters that are not in a series of words. There are no upper-case letters, digits, punctuation, or special symbols.
I need help fixing my code. I am stuck and do not know where to go from here.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
int letters[26];
char words[50];
int i = 0, b = 0;
printf("Enter your input : ");
scanf("%s", words);
for(i = 0; i < 26; i++){
letters[i] = 0;
}
while(!feof(stdin)){
for(b = 0; b < strlen(words) - 1; b++){
letters[ words[b] - 'a']++;
scanf("%s", words);
}
}
printf("\nMissing letters : %c ", b + 97);
return 0;
}
My output is giving me some random letter that I do not know where it is coming from.
Here is a working first implementation.
As well as the comments that have already been made, you should use functions wherever possible to separate out the functionality of the program into logical steps. Your main function should then just call the appropriate functions in order to solve the problem. Each function should be something that is self contained and testable.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_INPUT 20 /* Max input to read from user. */
char *readinput(void);
void find_missing_lower_case(char *, int);
int main()
{
char *user_input = readinput();
int len_input = strlen(user_input);
printf("user input: %s\n", user_input);
printf("len input: %d\n", len_input);
find_missing_lower_case(user_input, len_input);
/* Free the memory allocated for 'user_input'. */
free(user_input);
return 0;
}
char *readinput()
{
char a;
char *result = (char *) malloc(MAX_INPUT);
int i;
for(i = 0; i < MAX_INPUT; ++i)
{
scanf("%c", &a);
if( a == '\n')
{
break;
}
*(result + i) = a;
}
*(result + i) = '\0';
return result;
}
void find_missing_lower_case(char *input, int len_input)
{
int a = 97; /* ASCII value of 'a' */
int z = 122; /* ASCII value of 'z' */
int lower_case_chars[26] = {0}; /* Initialise all to value of 0 */
/* Scan through input and if a lower case char is found, set the
* corresponding index of lower_case_chars to 1
*/
for(int i = 0; i < len_input; i++)
{
char c = *(input + i);
if(c >= a && c <= z)
{
lower_case_chars[c - a] = 1;
}
}
/* Iterate through lower_case_chars and print any values that were not set
* to 1 in the above for loop.
*/
printf("Missing lower case characters:\n");
for(int i = 0; i < 26; i++)
{
if(!lower_case_chars[i])
{
printf("%c ", i + a);
}
}
printf("\n");
}
I figured it out and this is the code I used.
int main(void)
{
int array[26];
char w;
int i=0;
for(i=0; i<26; i++) {
array[i]=0; }
printf("Enter your input: ");
scanf("%c", &w);
while(!feof(stdin)) {
array[w-97] = 1;
scanf("%c", &w); }
printf("Missing letters: ");
for(i=0; i<26; i++) {
if(array[i] == 0) {
printf("%c ", i+97); }
}
printf("\n");
return 0;
}
I've made a program that allows you to choose the size of the grid and it allows you to enter up to 20 words. Now I have to insert the entered words horizontally into the original array using a function. The function must return a value for success and a value for failure to enter the word into the puzzle board. I need help getting started with what the actual function should look like along with the function prototype. Pseudocode would be helpful. I'm a fairly new programmer so any help is great. Thank you
#include<stdio.h>
#include<string.h>
void printmatrix(char matrix[][20],int);
void inserthor(char matrix[][20],int);
int main(void)
{
//declare variables
char matrix[20][20];
char words[20][100];
int x;
int a,b;
int i=0;
int n=0;
for (a=0;a<20;a++)
{
for (b=0;b<20;b++)
{
matrix[a][b] = '+';
}
}
while (x<10 || x>20)
{
printf("How large would you like the puzzle to be (between 10 and 20):\n");
scanf("%d",&x);
}
printmatrix(matrix,x);
//part 3
printf("Enter up to 20 words to hide in the puzzle.\n");
printf("Enter the word 'done' after your last word if entering less than 20 words.\n");
for (i = 0; i < 20; i++)
{
printf("Enter word %2d:\n", i+1);
if (scanf("%99s", words[i]) != 1 || strcmp(words[i], "done") == 0)
break;
}
n = i;
printf("%d words entered\n", n);
for (i = 0; i < n; i++)
printf("Word %2d = [%s]\n", i+1, words[i]);
return 0;
}
void printmatrix(char matrix[][20],int x)
{
int i,j;
printf("Empty Puzzle:\n");
for (i=0;i<x;i++)
{
for (j=0;j<x;j++)
{
printf(" %c ", matrix[i][j]);
}
printf("\n");
}
}
Your function prototype
void inserthor(char matrix[][20],int);
lacks the parameter with the word to be entered and the value to be returned. You could use
char *inserthor(char matrix[][20], int order, char *word)
{
int i, j, l = strlen(word);
for (i = 0; i < order; ++i)
for (j = 0; j <= order-l; ++j)
if (matrix[i][j] == '+') return memcpy(&matrix[i][j], word, l);
return NULL;
}
which returns the address of the inserted word for success and NULL for failure.