I'm trying to find the largest or max value in an array/range (E44:I205) among rows with values in column D (D44:D2015) that match a word. For instance:
D E F G H I
Cheetah Cat 0 1 2 3 4
Tiger Cat 1 1 2 3 4 5
Dog 0 0 1 2 3
Among the rows with the word "*"&"cat", I want to find the max value. In this example, the formula should = 5. I've tried the following formula, but it just returns the first instance of "cat" and the associated max value in that row.
=LARGE(IF($D$25:$D$205="*"&"cat",$E$44:$I$205,),1)
Any help is much appreciated!
Use:
=AGGREGATE(14,6,E25:I205/(RIGHT(D25:D205,3)="cat"),1)
Related
I have a problem with pd.Series(a).unique()
I made a Series, and I used .unique().
However, this deletes the pd.Series index.
How can I made unique Array with original index?
Instead of using .unique() you can use .drop_duplicates():
x = pd.Series([1,2,3,1,1,2,4,5,6], index=list("abcdefghi"))
print(x)
a 1
b 2
c 3
d 1
e 1
f 2
g 4
h 5
i 6
dtype: int64
.drop_duplicates() will remove all duplicates from the Series while maintaining reference to the index. You can choose whether you want to keep the index location of the "first" or the "last" duplicated item via the keep argument:
# Keep the first entry of each duplicated value
x.drop_duplicates(keep="first")
a 1
b 2
c 3
g 4
h 5
i 6
dtype: int64
# Keep the last entry of each duplicated item
x.drop_duplicates(keep="last")
c 3
e 1
f 2
g 4
h 5
i 6
dtype: int64
I have an array A defined as
A = [1 0 1 1 0 1 2 3 1 2 3 ];
I want to make histogram of this array. I have tried with
hist(A)
But the problem is it shows value 1 is 5 times, 2 is 2 times and so on. But I want like it as at position 1 value 1, at 2 value is 0 , at 3 value is 1 and so on.
hist counts the number of occurances of each value in the input* and uses those for the height of the bars. This is why the output is what you mention. What you want, however, is just bar because your input A already is a histogram.
bar(A);
%// Add some histogram labels
xlabel('Index')
ylabel('Frequency')
*This isn't technically correct since it depends on the bins, but for this specific input it is the case.
Given a logical column vector (size n x 1) v and an array a (size m x n) how do I generate a new array consisting of all the columns in a where the numerical index of said column (1...n) is 1 at the corresponding location in v.
So for example if v was
1
0
0
1
and a was
1 4 7 10
2 5 8 11
3 6 9 12
the new array would be
1 10
2 11
3 12
because the first and fourth elements of v are 1 (true), so the new array should contain the first and fourth columns of a.
I have tried a bunch of things involving normal logical indexing and transpose but I can't get it to work. All help is appreciated
You want to use the logical indexing to select the columns and select all rows. In the example below, I have explicitly cast v as a logical just in case it's not a logical matrix already.
new = a(:, logical(v))
1 10
2 11
3 12
I want to merge multiple arrays of unique occurrences to a single array. To get the arrays in the first place I use this code, where image series is a slice from a tiff image imported using imread:
a = unique(img_series);
occu = [a,histc(img_series(:),a)];
I do that multiple times, because the tiff image I'm using has multiple hundred images stacked, which my RAM will not support to import at once. So each 'occu' looks something like this (first number is the unique value, second number is the number of occurrences):
occu1 occu2 .....
0 1 1 2
12 1 10 1
14 1 12 1
15 1 14 2
.. .. .. .. .....
Now I want to merge them all together, or better merge them in each iteration, when I'm reading another stacked image.
The merged results should be a 2D matrix similar to the one above. The number of occurrences of the same values should be added to one another, as this is the whole point of counting them. So the result of the above example should be this:
occu_total
0 1
1 2
10 1
12 2
14 3
15 1
.. ..
I found the join command, but that one does not seem to work here. I guess I could do it the long way of searching the matching number and add the occurrences together and so on, but there must be a quicker way of doing it.
A = [0 1;12 1; 14 1;15 1];B = [1 2;10 1;12 1;14 2];
tmp = [A;B]; %// merge arrays into a single one
tmp(:,1) = tmp(:,1)+1;%// remove zero occurrences by adding 1 to everything
C = accumarray(tmp(:,1),tmp(:,2)); %// add occurrences all up
D = [1:numel(C)].'; %// create numbered array
E = [D C];
E((C==0),:)=[]; %// get output
E(:,1) = E(:,1)-1;%// subtract the 1 again
E =
0 1
1 2
10 1
12 2
14 3
15 1
Job for accumarray. This takes the first argument as your dictionary key, and adds the values of the each key together. The addition and subtraction of 1 is done because 0 cannot be an index in MATLAB. To circumvent this (assuming you have no negative numbers), you can simply add 1 and remove that afterwards, shifting all your indices to positive integers. If you hit negative numbers, subtract tmp(:,1) = min(tmp(:,1)+1 and add E(:,1) = min(tmp(:,1)-1
I use R for my statistical analysis.
I wanna group my data in an array based on the ID column. This results in having an array of unique IDs which each cell includes a data array of correspondence ID. Since the number of the data per ID is not similar, therefor each array in each cell has different length.
So I wonder how I can create an array of arrays varied in length using R?
I already having the following codes but get an error:
#number of unique IDs
size<-unique(data[,1]);
for (i in 1:length (gr))
{
index<- which(data[,1]==gr[i]);
data_c[[i,1]]<-data[index,];
}
Here is the error
more elements supplied than there are to replace
Thanks in advance for any comment.
I explain my problem by an example:
I have following data called it DATA_ALL:
DATA_ALL[]=
id age T1 T2 T3 T4
1 20 1 0 0 0
1 20 NA 0 NA 0
1 20 0 0 0 0
5 30 1 NA 0 0
5 30 0 0 0 1
6 40 0 1 0 0
I want to group the data of each id and put all in an array (array of arrays):
DATA_GROUPED []=
id data
1 1 X1[]=[an array includes all data from DATA_ALL where the id=1]
2 5 X2[]=[an array includes all data from DATA_ALL where the id=5]
3 6 X3[]=[an array includes all data from DATA_ALL where the id=6]
Please note that the length of X1!=X2!=X3
So how I can create the DATA_GROUPED[] matrix??
It is nearly impossible to answer your question in relation to your code, but in general, I think what you want to do is create a list of vectors, a bit like this:
one<-letters[1]
two<-letters[2:3]
three<-letters[4:6]
combined<-list(one=one, two=two, three=three)
Be sure to use indexing correctly now, and preferably with [[:
for(i in 1:length(combined))
{
cat("The contents of item", names(combined)[i], "are:", combined[[i]], "\n")
}
Output:
The contents of item one are: a
The contents of item two are: b c
The contents of item three are: d e f
Edit (following edit of question):
split.data.frame(DATA_ALL, DATA_ALL[,1])
Check ?split and note the first paragraph in Details.
Note this indeed creates a list of matrices/arrays.