Assembly Language code to find positive numbers in a Array of numbers - arrays

Question

We can only edit bold part to find positive number from given array. This is what i have tried in visual basic and i am just getting result as zero, Can someone say where it got wrong?
int solution(const int arr[], size_t arr_size)
{
int result = 0;
__asm
{
**MOV eax, arr
MOV edx, eax
MOV ebx, 10
XOR ecx, ecx
LEA esi, size arr
NEXT2 :
MOV edi, esi
SHR edi, 10
JNC NEXT1
JMP NEXT3
NEXT1 : INC ecx
NEXT3 : INC SI
DEC ebx
JNZ NEXT2
MOV[result], ecx;**
}
return result;
}
int main()
{
int result;
int arr[] = { 0, -1, 2, -3, 4, -5, 6, -7, 8, -9 };
result = solution(arr, sizeof(arr) / sizeof(arr[0]));
printf("Grade 6 result = %d\n", result);
getchar();
return 0;
}

Answer 1

1) Here is a piece of code I use to get the size of an array:
mov ebx, 0 ; set ebx to zero to start checking at index 0
countloop:
inc ebx ;Increase ebx for next loop
cmp arr[ebx], '\0' ;compare arr at index [ebx] to end char '\0'
jne countloop ;if not equal, jump back and try for next index
mov arrlength, ebx ;if equal to '\0', load the value of ebx (actual length of the array) into the empty length variable
The reason why you look for '\0' is that the string is stored like a char array and the register only stores the first char, the loops to get the other until it get that 'end' characters. I believe other characters would get the loop to stop, not sure which one, but \0 does work
2) Then use the value stored in arrlength as the number of loops you will need to check your array and find positives.
MOV ecx, arrlength ; This sets the loop counter register (ECX) to the size of your array
MOV ebx, 0 ; Set this to 0 as we will use it again as index
MOV esi, 0 ; Same
compareLoop:
MOV eax, arr[ebx] ; load value of arr at index ebx
CMP eax, 0 ; sets flag, comparing eax to 0
JL lessThan ;JL --> jump if first operand lower than second operand
MOV newArr[esi], eax ;Put the value (which is >0, in a new array)
add esi, 4 ; To point to the next position
lessThan:
add ebx, 4 ; adding for to ebx so that now it has the index of next value in array
loop compareLoop ; until ecx = 0
I basically showed you how I would do it, I am far from a pro, and simply don't understand the way you proceeded.