I'm writing a protractor test which asserts a URL against two different browser URLs.
I tried using toMatch with a regular expression but I get an error.
Is it possible to assert an actual string value against 2 or more expected string values and see if it is equal to any of them?
expect(url1).toMatch(/this.url|www.google.com/);
Sounds like you want to use toContain() which works for finding an item in an array. So switch your assertion around because you want to pass it an array of URLs [this.url, 'www.google.com'] and assert that it will contain url1.
expect([this.url, 'www.google.com']).toContain(url1);
Note: While this should work, personally I don't like to have my values on the receiving end of the assertion i.e. toContain(url1), I would rather that be passed first expect(url1).... However, in the end it's still asserting actual vs expected values so not a huge deal in my opinion.
https://jasmine.github.io/2.0/introduction.html
Related
For my simulation, I have a field that is called particle.current_theta. When this field is a single variable, I assign it a new value that is called just "theta" on my line 177. This theta has its value changed further down within my code, on lines 202 and 206. I want what I have printed in my terminal as tree_theta and current_theta to be very similar to each other but not quite identical (This part of the code basically detects whether or not my particle is entering or exiting a region). You can see all this in the image below:
Now, I need to make the field I have called particle.current_theta a [1x1] array, and assign the entry in my [1x1] array the "theta" value, as usual. However, simply making particle.current_theta a [1x1] array radically changes its value within the terminal and causes my simulation to break. You can see how the value for particle.theta (printed in terminal as "current theta") is now drastically different in the code below:
I suspect that making particle.currenttheta an array is making it mutate whenever theta is changed in some of those lines below. How do I prevent that from happening, and get results that are identical to using just a single variable. To be precise, I want particle.current_theta to save the numerical information that theta has at line 177 of code but not be changed afterwards. Because of the large size of my code now and the function calls within function calls, it would be infeasible for me to be able to create a mwe that replicates this issue. However, all help and advice is appreciated, and I will respond to and clarify any questions that people may have.
If theta is a scalar (and it appears to be), then it's unlikely that changing its value is what is changing particle.currenttheta. What is more likely is that you're passing the currenttheta to some function, and changing the value of the passed argument inside the function. Julia arrays are passed to functions "by reference", in the sense that a copy is not made, and instead any changes made inside the function change the original array. When you had currenttheta as a scalar (which are passed "by value" instead), when you pass that to a function, changes made inside the function do not affect the original currenttheta's value.
So if you're passing currenttheta to a function somewhere and don't want it to be modified inside the function, pass copy(particle.currenttheta) in that call instead.
If you're not doing that, or that doesn't solve the problem, we need more of the code to figure out where the change might actually be happening. If not the whole of it, at least the parts that handle currenttheta, and the parts that print it. (Also, it would massively help with clarity if you would use consistent names in the output. Sometimes it's treetheta and current theta, other times it's theta and particle.currentheta, and it's not clear where these are being printed from and what the difference - if any - is.)
I have a UserForm with a ListBox for the user to select values. Those values are populated in UserForm_Initialize() via a function call to the base module, which returns an array as variant. This works without problems.
If the user selects some values and presses a button, the buttons Click event calls another function in the base module to pass on the user-entered array and compute things. This does not work at all. The value received in the base module is always nonexistent (not even null, but I don't know the correct VBA term, nothing is there at all).
Things I have tried so far:
Passing all arguments ByVal: Did not make a difference
Using global shared variables: This did work, but I don't want to rely on them if all I do is pass a single array to a single function. This also introduces state into the code which has to be managed, especially when reusing the function
Accessing the functions by full qualifiers: Did not make a difference. The functions are found and executed correctly, but the argument variables are empty, therefore the functions fail later on when doing the calculations.
My question is: How can I pass arrays from UserForms to Modules (not vice versa) without relying on global variables and without losing the array content?
This question may be related to this question about passing a String from Form to Module, but the accepted answer does not help in my case (using global variables).
When adding the code as requested in the comments, I stumbled upon that fact that I could print the content of the array, but it would not show anything in the debugger and the size would be 0.
The size issue was because I used Len(array) instead of Application.CountA(array) and I had a leftover On error resume next from earlier still in the code, which meant that no error was raised and size was always set to zero... This was the reason for the strange behaviour.
I have the following nested struct:
hole 1x200 struct, diam 1x12 struct, which has the following fields: pos, freq1, fre12
That is:
hole(1 to 200).diam(1 to 12).pos
.freq1
.freq2
From a value (freq1 and freq2), I would like to obtain the field name of the struct. So I will need to find the value that matches with freq1 and freq2 and show the fieldname.
I tried to use structfun in order to apply a function to each field.
[struct.field]=structfun(#(x) find(x.freq1==27.059783995484867 & freq2==76.468355874897000))
But I guess I am writing something wrong on the code.
Also I create an anonymous fuction but I have the following error:
'Error using structfun / Inputs to STRUCTFUN must be scalar
structures'
. How ever when I verified if an specific value of the struct is scalar, I have a positive answerd: isscalar(hole(130).diam(10))
I belive I more near the solution using this script:
myfun=#(yourarray,desiredvalue) yourarray==desiredvalue;
%//Apply function to each field of scalar structure, it SCALAR??
desiredfieldindex=myfun(structfun(#(x) x,hole),26.697046257785030)
desiredFieldName=fNames(desiredFieldIndex)
I don´t know if I am in the rigth path, or I should utilize the function find. ALso I that case I don´t know how to implement it.
Couple of things.
FLOATING POINT VALUES! Careful!! Never compare a floating point value as val==0.3! do abs(val-0.3)<10^-8 or something similar. Read more here.
You are using structfun wrong. The function needs 2 arguments, and you are just passing 1! However, structfun will apply a function to each field so you are not using it rigth either in that sense. Lets see an example
example:
a.hithere=5;
a.notthis=3;
fun=#(x)x==5;
[isfive]=structfun(fun,a)
isfive =
1
0
As you can see, it applies the function to each of them. If you try to change the function to fun=#(x)x.hithere==5 you will get an error! As the function is applied to each field, and x.hithere.hithere or x.notthis.hithere do not exist.
If you want to check both values, you will need to check them independently making two separated calls to structfun or avoiding structfun and just making a for loop.
Sometimes you need to ng-if or ng-show an item in html based on some choices made earlier. One of these for me is "Additional Item". You can enter one set of information, and also if you want, an additional set. This creates an array of 2 similar objects. With this setup, you can only have 1 or 2 objects in this array. (important, since the scope of this question needs to be limited this way)
I want to ng-show an html directive based on "myItemsArray.length > 1". Since the array can (read should) only be 1 or 2 in length (not 0), this should work. However, it does not, because AngularJS seems to be adding an item "proto" to the array which adds to the count. See the image.
The problem is, proto makes the array length equal 2. I am not going to just look for length > 2 because i really don't know if i can count on proto always being there, and i just think thats bad practice anyway.
Also, i know there are MANY other ways of doing this (setting a boolean, or using another var to indicate etc, but i really just want to work with count of items in the array because "business logic"..
EDIT:
After doing a little debugging, i'm seeing that i have an array of "Object, undefined". How is this even possible :)
Some search lead me to this. Why are some values in my array undefined
EDIT:
Seems that using a delete may cause this problem
So the other day I had my colleague review my code and he saw that I was using array[0], in Java terms this is basically getting the first element of the array. I did this several times for different purposes, all of which is to get the first element in an array/collection, for example list.get(0), to which he strongly disagreed with.
His argument was that somebody from non-programming background would have problem understanding it and using 0 in such cases is basically hard-coding, which is bad practice. I google-ed several times and all suggestions to getting the first element in an array or any collection is providing them the index, which is 0 in this case.
Could anyone provide me with a suggestion on getting the first element in a meaningful way?
Try using linkedlist's getfirst method to get the first element of the list.
If you were to use an ArrayList is backed by an array and hence its perfectly valid to use index as 0 to get first element.