su - $USER -c "$CMD stop > /dev/null 2>&1" yields this error
su: must be run from a terminal. When set :pty, true in deploy.rb the prompt holds on. How can I solve this issue?
The su command generally doesn't work well with Capistrano. The preferred way to run a command as a different user involves passwordless sudo: http://capistranorb.com/documentation/getting-started/authentication-and-authorisation/#authorisation
Related
I'm writing script to run iperf on linux device accessible via adb.
From a terminal, when I run the command: adb shell iperf -c ......
I get the log of the command 50 s after the command starting.
inconvenient: during 50 s you are not sure that iperf has started
I tried the logcat command (logcat --pid ...), It gives the same result.
From a terminal, when I enter adb session first and then I run the command: iperf -c .....
I get the log of the command in real time.
inconvenient: I'm not able to automate the procedure, because I have to start the adb session first
For the first use case: Is there a way to force "log flush" in order to get the log in real time?
For the second use case: Is there a way to send commands to already opened adb shell session?
Is there any other ways to launch iperf on device and get the log in real time?
The solution i found is the library pexpect that allow to interact with adb session.
I have a program running on armbian single board computer. The program starts with -b option during the startup of the system. I created this simple shell script
#!/bin/bash
#Myprog server start
sudo -b /home/myprog/myprog
This program is C written and it sometimes outputs some information with printf functions. But since it is started with -b option there's is noting in the console.
Now when I log in to the armbian via ssh with Putty I want to occasionally read the output of this program. Is it even possible?
Not exactly what you’re asking, but generally speaking it’s better practice to redirect output to a log file than to try to interactively look at the console output for a background app.
Something like:
sudo -b /home/prog/myprog >> /home/prog/log.txt 2>&1
Should do it.
Then view output with
tail -f /home/prog/log.txt
If it’s really important to you to run interactively without logs, I would suggest running it from within “screen” without backgrounding it.
screen
sudo /home/prog/myprog
Then ctrl-d to detach and let it run in background. screen -r to reattach.
I'm using a psuedo terminal, /bin/sh -i, by calling normal commands for posix_openpty() then fork(), in language C.
When I run from command line GUI terminal like this
$ ./MyTerminal
or
$ sudo ./MyTerminal
or as root like this
# ./MyTerminal
all works very good and as expected, no problems.
However, when I make a systemd service file like this, it works fine
[Service]
User=root
But when I try to get systemd to run it as normal user like this
[Service]
User=debian
THe first output for /bin/sh -i is
/bin/sh: 0: can't access tty; job control turned off $
And the terminal does not really work.
When I run /bin/bash, fork() w/posix_openpty() is returns me this, but the terminal generally works ok
bash: cannot set terminal process group (-1): Inappropriate ioctl for device
bash: no job control in this shell
Is such a weird prolem because when running outside of systemd everything works perfect. I see this problem in 1 other question but no clear solution. So what I have to change to make systemd run my file perfectly? Thanks for your help.
I have compiled a c program into an executable that I would now like to integrate into the applications menu in Debian 7.4 XFCE. In order to run the application under normal circumstances, I am required to type
sudo myprogram
Now I have created my .desktop file and placed it in /usr/share/applications
[Desktop Entry]
Type=Application
Encoding=UTF-8
Name=myprogram
Comment=configuration loader
Exec=sudo loader
Icon=/usr/share/icons/hicolor/48x48/apps/myprogram.png
Terminal=false
Categories=Development;IDE
The item is added to my applications menu as expected, and the icon shows up properly. The problem, however, is that double clicking the menu item to launch the application does nothing.
If I navigate to /usr/bin (where I have placed my executable) and type "sudo myprogram", the program launches as expected.
What can I do to fix this issue and get the program to launch from the menu? Perhaps /usr/bin is not the correct place to put it, or I have the incorrect Exec command. I greatly appreciate the help.
I ended up using (after installing gksu)
Exec = gksu myprogram
this launches a graphical sudo prompt, which is sufficient for my needs.
This is what the setuid bit in the permissions is for. It makes executables run with permissions of the file owner. This only works on actual executables, not on shell scripts!
sudo chmod u+s myprogram
sudo chown root myprogram
./myprogram # now runs as root
Please be careful when using this as it will always execute that program as root no matter who executes it. You can limit access by setting it to your usergroup and deny all execute.
chgrp "${USER}" myprogram # provided you have individual groups set up
chmod a-x myprogram # deny all execute
This approach does not need additional installation of packages.
Terminal=true opens a new terminal window which runs
sudo -i to ask for the password.
Then, using sh to run the program, the Terminal is closed and myprogram runs in the background because it has a & at the end.
[Desktop Entry]
Type=Application
Name=...
Exec=sudo -i sh -c "myprogram &"
Terminal=true
Request: Please report if it works under your OS.
Tested under:
Xubuntu
The pkexec solution from askubuntu:
Exec=pkexec env DISPLAY=$DISPLAY XAUTHORITY=$XAUTHORITY APP_COMMAND
Try adding this to .desktop
Path=/path/to/myprogram
I'm having trouble getting an answer to my question, in laymens terms. It is probably my lack of knowledge on the subject so, I'm dumbing down the question. I have a windows machine that I run the putty tool from and connect to a linux box. I run " killall /bob/bin/myfile.out " then close putty then type in a cmd prompt pscp.exe myfilet.out.2.3.4 root#192.168.1.1:/bob/bin/myfile.out . Can someone show me how to combine these into a single windows batch file? thank you
You could use the free command line tool Plink to run commands on external servers via SSH.
#echo off
Plink root#192.168.1.1 "killall /bob/bin/myfile.out"
pscp.exe myfilet.out.2.3.4 root#192.168.1.1:/bob/bin/myfile.out || echo an error occurred when copying the file.
the command after || on the second line will only run if an error level is set by the previous command.
I can't add comments yet, but can you elaborate on how you login with putty, but not do the exact same thing with plink? Plink not only accepts all the same options as putty, but if you have a saved session in putty, you can access it from plink. Without any subcommands, plink should essentially make you CMD shell look like a crude putty window, with subcommands, it will execute them and return:
C:\Users\riglerjo>plink savedputtysession
Using username "rigler".
# hostname
s9-chicago.accountservergroup.com
-bash-3.2$ exit
logout
Run the remote command as an option on plink:
C:\Users\riglerjo>plink savedputtysession hostname
s9-chicago.accountservergroup.com