Find word in a string with a character - sql-server

Question

I have tried so many times but could not find the exact query yet.
The one I made works in few string but doesn't work in another(It is uncertain).
What i want is the word which has '.' in it like "abcde sfjhjk.dkjb sajb njdhf", what i want is "sfjhjk.dkjb" as result . This is just an example.
The query returns all letters in some cases while truncates few digits in other cases. You can check by providing different values.
I tried below :
This doesn't work:
DECLARE #QUERY VARCHAR(MAX)='
renewreque0_.amount AS AMOUNT48_,
renewreque0_.charge_type AS CHARGE3_48_,
renewreque0_.commission_rate AS COMMISSION4_48_
'
SET NOCOUNT ON;
DECLARE #TABLENAME TABLE(TABLE_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
DECLARE #COLUMNS_JOIN TABLE(COL VARCHAR(MAX),COLUMN_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
DECLARE #NAME VARCHAR(MAX),#ALIAS VARCHAR(MAX),#J_QUERY VARCHAR(MAX),#W_QUERY VARCHAR(MAX)
DECLARE #WHERE_JOIN TABLE(COL VARCHAR(MAX),COLUMN_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
WHILE CHARINDEX('.',#QUERY)>1
BEGIN
SET #NAME = REVERSE( SUBSTRING(REVERSE(#QUERY),CHARINDEX('.',REVERSE(#QUERY))+1,CHARINDEX(' ',#QUERY)) )
SET #ALIAS= REVERSE(LEFT(REVERSE(#QUERY),CHARINDEX('.',REVERSE(#QUERY))))
SET #ALIAS=LEFT(#ALIAS,CHARINDEX(' ',#ALIAS))
SET #NAME=LTRIM(RTRIM(#NAME))
SET #ALIAS=LTRIM(RTRIM(#ALIAS))
INSERT INTO #COLUMNS_JOIN SELECT #NAME+#ALIAS,#NAME,REVERSE(LEFT(REVERSE(#ALIAS),LEN(#ALIAS)-1))
SET #QUERY=REPLACE(#QUERY,#NAME+#ALIAS,'')
END
SELECT * FROM #COLUMNS_JOIN
This works:
DECLARE #QUERY VARCHAR(MAX)='
AND t8_.username LIKE ?
AND t4_.branch_id = ?
AND t1_.account_no = ?
AND t0_.remarks = ?
AND t0_.collect_from = ?
'
SET NOCOUNT ON;
DECLARE #TABLENAME TABLE(TABLE_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
DECLARE #COLUMNS_JOIN TABLE(COL VARCHAR(MAX),COLUMN_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
DECLARE #NAME VARCHAR(MAX),#ALIAS VARCHAR(MAX),#J_QUERY VARCHAR(MAX),#W_QUERY VARCHAR(MAX)
DECLARE #WHERE_JOIN TABLE(COL VARCHAR(MAX),COLUMN_NAME VARCHAR(MAX),ALIAS VARCHAR(MAX))
WHILE CHARINDEX('.',#QUERY)>1
BEGIN
SET #NAME = REVERSE( SUBSTRING(REVERSE(#QUERY),CHARINDEX('.',REVERSE(#QUERY))+1,CHARINDEX(' ',#QUERY)) )
SET #ALIAS= REVERSE(LEFT(REVERSE(#QUERY),CHARINDEX('.',REVERSE(#QUERY))))
SET #ALIAS=LEFT(#ALIAS,CHARINDEX(' ',#ALIAS))
SET #NAME=LTRIM(RTRIM(#NAME))
SET #ALIAS=LTRIM(RTRIM(#ALIAS))
INSERT INTO #COLUMNS_JOIN SELECT #NAME+#ALIAS,#NAME,REVERSE(LEFT(REVERSE(#ALIAS),LEN(#ALIAS)-1))
SET #QUERY=REPLACE(#QUERY,#NAME+#ALIAS,'')
END
SELECT * FROM #COLUMNS_JOIN
Can anybody please help.

Answer 1

I would first use an SplitString function (passing a blank space as delimiter), which returns as rows each word on a string, and then filter it to return just the words having a dot.
SQL Server 2016 already has one https://learn.microsoft.com/en-us/sql/t-sql/functions/string-split-transact-sql and on older SQL Servers you can build your own : Splitting the string in sql server
set #SQLStr varchar(512) = 'abcde sfjhjk.dkjb sajb njdhf';
select value from string_split(#SQLStr, ' ')
where charindex('.', value) > 0

Answer 2

Alright just for fun
declare #str nvarchar(100) = 'abcde sfjhjk.dkjb sajb njdhf',
#pointIndex int
SET #pointIndex = (SELECT CHARINDEX('.',#str) )
SELECT RTRIM(LTRIM(SUBSTRING(#str, #pointIndex - CHARINDEX(' ',REVERSE(LEFT(#str,#pointIndex))) +1,CHARINDEX(' ',REVERSE(LEFT(#str,#pointIndex)))) -- left side
+SUBSTRING(#str,#pointIndex +1, CHARINDEX( ' ', SUBSTRING(#str,#pointIndex,len(#str) - #pointIndex) ) -1 )))
Needless to say i would not recommend this option because it is really hard to maintain. As Marc said your best option here is to split your string for blanks and find the ones with a '.'
Now if you dont have SQLServer 2016 here is a split function for you :
CREATE function [dbo].[Split]
(
#string nvarchar(max),
#delimiter nvarchar(20)
)
returns #table table
(
[Value] nvarchar(max)
)
begin
declare #nextString nvarchar(max)
declare #pos int, #nextPos int
set #nextString = ''
set #string = #string + #delimiter
set #pos = charindex(#delimiter, #string)
set #nextPos = 1
while (#pos <> 0)
begin
set #nextString = substring(#string, 1, #pos - 1)
insert into #table
(
[Value]
)
values
(
#nextString
)
set #string = substring(#string, #pos + len(#delimiter), len(#string))
set #nextPos = #pos
set #pos = charindex(#delimiter, #string)
end
return
end
And use it as such :
SELECT * FROM dbo.Split(REPLACE(#str,' ','/'),'/')
WHERE charindex('.', value) > 0
Note that i replace blanks by another value.