Sending Pointers of Structs to a Function in C - c
I don't love this, but I have a struct with nearly 45 members inside; all are characters or character arrays. That said, I am going to need to optimize the way I initialize each struct. Ordinarily, I would pass the entire object into my init_struct() function, but I feel like that is not the best way to do this.
How would I create and use a pointer to the struct to accomplish this?
Old Method would look something like this:
void init_struct(struct general){
...initialize members...
}
int main(){
struct general[10];
for(int i = 0 ; i < 10 ; ++i){
init_struct(general[i];
}
}
Since this struct is so large, as I said nearly 45 members inside it, I think a point to the struct would go a long way in optimizing this process. How would I accomplish that?
Just in case you need, here is the typedef for my struct
typedef struct
{
//Basically, everything we want to read from HUDL should be here...
int play_num;
char down;
char dist[3];
char ydln[4];
char gnls[3];
char hash[3];
char home[20];
char away[20];
char odk[2];
char qtr[2];
char series[3];
char result[20];
char penalty[20];
char act_cb[20]; //How do they act post-snap
char act_dl[20];
char act_lb[20];
char act_ol[20];
char act_qb[20];
char act_rb[20];
char act_saf[20];
char aln_cb[20]; //How do they align pre-snap
char aln_dl[20];
char aln_lb[20];
char aln_ol[20];
char aln_qb[20];
char aln_rb[20];
char aln_saf[20];
char aln_wr[20];
char blitz[20];
char box_cnt[3];
char saf_count[20];
char coverage[20];
char cvr_basic[20];
char def_front[20];
char mtn_def[20];
char num_rush[3];
char off_form[20];
char form_var[20];
char motion[20];
char off_pro[20];
char off_play[20];
char play_var[20];
char personnel[20];
char play_type[20];
char time[2];
char score_diff[4];
char field_zone[2];
char dd_type[2];
char form_strength[2];
} HUDL; // MAXIMUM of 63 Members
There's a couple of things wrong on your code.
First of, your function definition is wrong because you omit the parameter name. Your function definition should look like this:
void init_struct(struct general mygeneralstruct){}
Alternatively, you could use an alias for your struct using typedef, like so:
typedef struct {
int a;
} general;
In which case, your function declaration could look like this:
void init_struct(general mygeneralstruct){}
You have the same problem when you declare your array of structures. You omit the name of your variable. Instead of
struct general[10];
it should be
struct general mygeneralstruct[10]
or
general mygeneralstruct[10](typedef)
Finally, you can't change your array of structures by passing each structure's value to the function. You need to pass each structure's address instead.
Your function declaration should then be(using typedef):
void init_struct(general* mygeneralstruct){}
and the code in the loop:
init_struct(&mygeneralstruct[i]);
To pass a pointer to your array element, you just prefix the parameter with &, make sure you declare the function correctly:
void init_struct(HUDL* pGeneral){
if ( pGeneral != NULL ) {
//This will ensure the entire structure contains '0'
memset(pGeneral, 0, sizeof(HUDL));
...initialize members...
}
}
int main(){
HUDL general[10];
for( int i=0; i<(sizeof(general) / sizeof(general[0])); i++ ) {
init_struct(&general[i]);
}
}
I'm not sure why you haven't used the typedef 'HUDL' makes life a lost easier and code easier to read.
A slightly cleaner and better approach would be to have a constructor and destructor function to allocate memory dynamically to structure and free it after use.
static void HUDL_destroy(HUDL* ptr)
{
if(ptr)
{
//...any other clean up that needs to be done goes here..
free(ptr);
}
}
static HUDL* HUDL_create()
{
HUDL* ptr = malloc(sizeof(HUDL));
if(!ptr)
return NULL;
//do initialization bits...
init_struct(ptr);
return ptr;
}
int main()
{
//allocate and initialise structure
HUDL *general = HUDL_create();
//do stuff...
//free structure after use
HUDL_destroy(general);
}
You might need an array of pointers in your case. So modify your main() accordingly.
int main()
{
//we need an array of structure pointers
HUDL* general[SIZE];
//allocate and initialize structure
for(int i=0; i<SIZE; i++)
general[i] = HUDL_create();
//do stuff...
//free structure after use
for(i=0; i<SIZE; i++)
HUDL_destroy( general[i] );
}
Related
failing freeing dynamic struct array in c
I'm having some problem with freeing dynamic struct array and I can't understand why. first of all there is this struct: typedef struct { char name[LEN]; char address[MAX]; } Airport; And the constructor I made for this struct isn't using allocation for this struct building. sec of all there is this struct: typedef struct { Airport* airports; int maxAPS; int currentAPS; } AirportManager; //constructor void addAirport(AirportManager* pAirportManager) { if (pAirportManager->maxAPS == pAirportManager->currentAPS) { pAirportManager->maxAPS++; pAirportManager->airports = (Airport*)realloc(pAirportManager->airports, sizeof(Airport)*pAirportManager->maxAPS); //pAirportManager->airports[pAirportManager->currentAPS] = *(Airport*)malloc(sizeof(Airport)); }.... and when I'm ending my program and want to free the AirportManager with the following code: void freeAirportManager(AirportManager* pAirportManager) { for (int i = 0; i < pAirportManager->currentAPS; i++) free(&pAirportManager->airports[i]); free(pAirportManager->airports); } I've debuged this one and all the parameters are just fine but after one run in the loop the program exits, what should I change in the free function ? do I need the marked line in the constructor ? I just added this on thinking it might help, but seems to not work as well... do I need to free only the array itself ?
for (int i = 0; i < pAirportManager->currentAPS; i++) free(&pAirportManager->airports[i]); You need only to free pAirportManager->airports. You do not have pointer to pointer here. So instead of those two lines: free(pAirportManager->airports); I would use flexible array member instead of pointer. typedef struct { char name[LEN]; char address[MAX]; } Airport; typedef struct { size_t maxAPS; size_t currentAPS; Airport airports[]; } AirportManager; For sizes use size_t type instead of int
How do i make this into a struct?
OK so I have erased everything trying to make this into a struct, because i messed it up bad. I need this code of arrays to become a struct. FILE *pFile; int choice = 0; char buf[40]; int id[sizeof(buf)]; char name[sizeof(buf)][20]; char state[sizeof(buf)][5]; char dis_code[sizeof(buf)]; float balance[sizeof(buf)]; char due_date[sizeof(buf)][40]; This is what I got do so far but when i try to use it it goes nuts. I still don't know how to load the file into it. struct fileinfo { int id[10]; char name[20]; char state[5]; char dis_code[5]; float balance[10]; char due_date[40]; } info[sizeof(buf)]; Am i missing something or do i have the right idea. The problem is when i run this the same why i would the regular arrays I run into errors.
I'm not sure if this is your only issue, but you have changed the type of several of the fields. int id[sizeof(buf)]; // id[i] is an int char dis_code[sizeof(buf)]; // dis_code[i] is a char float balance[sizeof(buf)]; // balance[i] is a float struct fileinfo { int id[10]; // info[i].id is an _array of 10 ints_ char dis_code[5]; // info[i].dis_code is an _array of 5 chars_ float balance[10]; // info[i].balance is an _array of 10 floats_ } info[sizeof(buf)]; An array of a type and single instance of that type will behave quite differently. I would suggest making the fields of the struct the same type as your original array elements, i.e.: struct fileinfo { int id; char dis_code; float balance; }
Since you declared char buf[40] ==> sizeof(buf) = 40. You are changing the 2 dimensional array into a single dimensional. The structure should be like struct fileinfo { int id[40]; char name[40][20]; char state[40][5]; char dis_code[40]; float balance[40]; char due_date[40][40]; }
how to write the character value from structure into the serial interface and convert into integer value?
struct MemoryTag1; typedef struct MemoryTag1{ char a[8]= {'+','0','2','6','.','5','EA','\r'}; // setpoint temperature value char b[8]= {'-','0','2','4','.','5','EB','\r'}; char c[6]= {'+','0','2','0','EC','\r'}; }Memory1; // This is a message structure which I want to transfer over the serial interface (RS232) and later convert into integer value. please guide me in this.
Your syntax is a bit off - try this: // declare Memory1 struct type to hold data typedef struct MemoryTag1 { char a[9]; // setpoint temperature value char b[9]; char c[7]; } Memory1; // allocate and initialise a Memory1 struct Memory1 m = { {'+','0','2','6','.','5','E','A','\r'}, {'-','0','2','4','.','5','E','B','\r'}, {'+','0','2','0','E','C','\r'} };
Really, to be honest, I'd prefer more information. But it doesn't really matter. It only affects the method of output. If you were running this on an arduino, for instance, you could output to the serial ports as easily as: Serial.begin(9600); Serial.write('a'); etc, etc As others have mentioned, there are situations in which you'd be better off using null-terminated strings. If however, you had a particular reason to do so, then I suppose you could; #include <stdio.h> typedef struct memoryTag1_t { char a[9]; // setpoint temperature value char b[9]; char c[7]; } *pMemoryTag1_t; typedef struct memoryTag2_t { char a[10]; // setpoint temperature value char b[10]; char c[8]; } *pMemoryTag2_t; void displayField1(char *field, int len) { for (int i=0; i<len; i++) { if (i!=0) printf(","); printf("%c", field[i]); }printf("\n"); } void displayField2(char *field) { bool firstDone = false; while (*field) { if (firstDone) printf(","); else firstDone = true; printf("%c", *field++); } printf("\n"); } int main() { memoryTag1_t myMem1 = { {'+','0','2','6','.','5','E','A','\r'}, {'-','0','2','4','.','5','E','B','\r'}, {'+','0','2','0','E','C','\r'} }; memoryTag2_t myMem2 = { "+026.5EA\r", "-024.5EB\r", "+020EC\r" }; displayField1(myMem1.a, sizeof(myMem1.a)); displayField1(myMem1.b, sizeof(myMem1.b)); displayField1(myMem1.c, sizeof(myMem1.c)); displayField2(myMem2.a); displayField2(myMem2.b); displayField2(myMem2.c); } Output: (Don't forget there's a \r printed 'after' the last comma in each line) +,0,2,6,.,5,E,A, -,0,2,4,.,5,E,B, +,0,2,0,E,C, +,0,2,6,.,5,E,A, -,0,2,4,.,5,E,B, +,0,2,0,E,C,
you can not declare struct in C in this way: it should be typedef struct MemoryTag1{ char a[9]; char b[9]; char c[7]; }Memory1; you can set value in the declaration of an object of this structure: Memory1 test = { {'+','0','2','6','.','5','E','A','\r'}, {'-','0','2','4','.','5','E','B','\r'}, {'+','0','2','0','E','C','\r'} }; If you use this bloc in each initiation of a Memory1 object so you can use macro to make it easier: #define INIT_MEMORYTAG1 {\ {'+','0','2','6','.','5','E','A','\r'},\ {'-','0','2','4','.','5','E','B','\r'},\ {'+','0','2','0','EC','\r'}\ } and then in your declaration of a Memory1 object: Memory1 test = INIT_MEMORYTAG1; BTW: You can not put 'EA', 'EB', 'EC' like a 1 charachter you have to separate them to: 'E','A', 'E','B', 'E','C' and so you have to update your char array sizes in the struct definition
That is really not C syntax. You can't have initializers in declarations of types, that doesn't have any meaning. You need to do it like this, to build the message: typedef struct { char a[10]; char b[10]; char c[8]; } Memory1; int main(void) { Memory1 m1; strcpy(m1.a, "+026.5EA\r"); strcpy(m1.b, "-024.5EB\r"); strcpy(m1.c, "+020EC\r"); return 0; } Note that the above will build proper C strings in the fields of the message, i.e. there will be 0-characters acting as terminators. The sizes were too small, so I changed that. It's trivial to ignore the terminator characters if you need to send this over some format that doesn't allow them; send each field separately. Converting one of the fields back into integers could be done using sscanf(), for instance.
accessing the array inside array of structures
I have a structure as follows struct a { char* ap; char* inputs[10]; int e; }; then I have created an array of this structure like struct a list [100]; now i want to fille the array inputs[10] and for that I am using the syntax to access the first location : ip=0; inp=0; list[ip].inputs[inp] but I am gettin the error "error C2107: illegal index, indirection not allowed" on compiling the code please suggest how to access the array location inside array of structure. regards priya
Here you use array of character pointer in your structure. So Initially you allocate memory for you structure by creation list of 100. I think you didn't create memory for you array of character pointer. You have to create memory for each of character pointer. So I suggest example code. #include <stdio.h> struct a { char* ap; char* inputs[10]; int e; }; int main() { int ip=0; int inp=0; struct a list[100]; list[ip].inputs[inp]= (char*)malloc(25); scanf("%s",list[ip].inputs[inp]);//Or other copy function to fill string printf("output %s",list[ip].inputs[inp]); }
Working fine on my pc.. here is my code.. #include <stdio.h> struct a { char* ap; char* inputs[10]; int e; }; int main() { int ip=0; int inp=0; struct a list[100]; list[ip].inputs[inp] = 'A'; printf("This: %c", list[ip].inputs[ip]); return 0; } OUTPUT= This: A let me know whether it helped or not..
The struct themselves do not have data. You need to create objects of the struct type and set the objects ... struct a { char* ap; char* inputs[10]; int e; }; /* I like to separate the type definition from the object creation */ struct a list [3]; list [0].inputs[0] = "Choclate"; list [0].inputs[1] = "Almond"; list [0].inputs[2] = "Rasberry"; Hope it ll usefull. Also refer this article
struct as unknown argument
I know how to pass an unknown amount of arguments from unknown types to a function. I mean something like this: char* plugins_entry(const char* data, ...); Now I am trying to pass a struct besides a few other arguments to that function. I have the same struct declared (or defined?) in both files (main.c and plugins.c). But when I try to "filter" the irc struct passed from the main.c out and parse the data in the irc struct from the plugins.c, I don't get anything usefull. When I call the function I get a segementation fault. This is the important part from the main.c: struct irc_data { char nick[32]; char user[32]; char host[64]; char chan[32]; char message[512]; int is_ready; }; .... int main(int argc, char** argv) { .... struct irc_data *irc = malloc(sizeof(struct irc_data)); .... (*lib_plugin)("r",irc); // call the function in plugins.c .... } And here the hole plugins.c: #include <stdio.h> #include <stdlib.h> #include <stdarg.h> #include <string.h> struct irc_data{ char nick[32]; char user[32]; char host[64]; char chan[32]; char message[512]; int is_ready; }; char* plugins_entry(const char* data, ...) { int i; struct irc_data *irc = malloc(sizeof(struct irc_data)); va_list args; va_start(args, data); for(i=0; data[i] != '\0'; ++i){ if(data[i] == 'r'){ irc = data[i]; } } va_end(args); printf("\n\n------------------------\n"); printf("What we got here: %s\n",irc->nick); printf("\n------------------------\n\n"); return "done"; } So, I am pretty sure that I am doing something wrong with the pointers. Could you please help me out here? Thank you ~ Tectu
The line irc = data[i] doesn't make any sense. You need to call va_arg: if(data[i] == 'r') { irc = va_arg(args, struct irc *); } Also, the malloc in plugins_entry is useless, it will only leak memory.
You don't extract the pointer to the struct using va_args(). With that, you should be able to directly use your struct: struct irc_data *irc = va_args(args, struct irc *); Note that you don't need to use malloc in this function as long as you don't want to copy explicitly. As your struct is already located on the heap (it's malloc'ed in main.c), you can just use it directly by using the pointer.