I have created a UserControl in WPF which consists of 2 simple buttons in the first run.
Now, I want to display in a MessageBox the x:Name of the button which is clicked by the user, but I don't want to create a Clicked event for each button separately.
Is it possible to program 1 generic Clicked event in the UserControl and then identify the sender object to get the correct x:Name ?
Is it possible to program 1 generic Clicked event in the UserControl and then identify the sender object to get the correct x:Name ?
Sure:
<Button x:Name="first" Click="generic_Click" />
<Button x:Name="second" Click="generic_Click" />
private void generic_Click(object sender, RoutedEventArgs e)
{
Button clickedButton = sender as Button;
MessageBox.Show(clickedButton.Name);
}
Use an EventSetter for that in a style for a button.
Example in xaml:
<StackPanel
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
x:Class="SDKSample.EventOvw2"
Name="dpanel2"
Initialized="PrimeHandledToo"
>
<StackPanel.Resources>
<Style TargetType="{x:Type Button}">
<EventSetter Event="Click" Handler="b1SetColor"/>
</Style>
</StackPanel.Resources>
<Button>Click me</Button>
<Button Name="ThisButton" Click="HandleThis">
Raise event, handle it, use handled=true handler to get it anyway.
</Button>
</StackPanel>
And then in cs file:
void b1SetColor(object sender, RoutedEventArgs e)
{
Button b = e.Source as Button;
b.Background = new SolidColorBrush(Colors.Azure);
}
void HandleThis(object sender, RoutedEventArgs e)
{
e.Handled=true;
}
Related
Does anybody know how to implement a double-click event handler that opens a new window in a way the new window becomes the front most window? (Just the behavior that is normally expected).
In WPF there is a strange behavior of windows when opening a second window in the double-click event handler. The second window opens but the first window, where the double-click-event was fired, becomes activated again immediately.
Opening a window in a click event handler, works as expected. The second window opens and remains the front window.
For demonstration purposes I created the following application. Two window classes with just a button control. To distinguish between click and double-click on the button control, the click-event works only if the left shift key is pressed.
After double-click
http://blog.mutter.ch/wp-content/uploads/2014/05/wpf_window1.png
After click (this is also the expected behavior for double-click)
http://blog.mutter.ch/wp-content/uploads/2014/05/wpf_window2.png
Main Window
<Window x:Class="WpfWindowSwitching.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="200" Width="600">
<Grid>
<Button Margin="40"
HorizontalAlignment="Center"
VerticalAlignment="Center"
MouseDoubleClick="doubleClick"
Click="click">
<TextBlock FontWeight="Bold"
FontSize="22">
I am the first Window, double click this button...
</TextBlock>
</Button>
</Grid>
</Window>
The code behind:
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void doubleClick(object sender, MouseButtonEventArgs e)
{
openNewWindow();
}
private static void openNewWindow()
{
var window = new SecondWindow();
window.Show();
}
private void click(object sender, RoutedEventArgs e)
{
if (!Keyboard.IsKeyDown(Key.LeftShift)) return;
openNewWindow();
}
}
Second Window
<Window x:Class="WpfWindowSwitching.SecondWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="SecondWindow" Height="200" Width="600">
<Grid>
<Button Margin="40"
HorizontalAlignment="Center"
VerticalAlignment="Center"
Click="click">
<TextBlock FontWeight="Bold"
FontSize="22">
I am the second Window
</TextBlock>
</Button>
</Grid>
</Window>
The code behind:
public partial class SecondWindow : Window
{
public SecondWindow()
{
InitializeComponent();
}
private void click(object sender, RoutedEventArgs e)
{
this.Close();
}
}
After MouseDoubleClick event, MouseUp event is raised which gets handled on MainWindow. Hence secondary window gets activated momentarily and with subsequent event bubbling, main window gets activated.
In case you don't want that, you can explicitly stop event bubbling by setting e.Handled to True after mouse double click event. This way secondary window will remain activated.
private void doubleClick(object sender, MouseButtonEventArgs e)
{
openNewWindow();
e.Handled = true;
}
I have a button name mybutton that is a part of a usercontrol X.
I made another usercontrol Y that holds X (X is part of it).
I want to catch in Y the event of mybutton when clicked.
How can I do it ?
Thanks
Look at the following code. It's the same with UserControl instead of Grid. The Click event is routed up the visual tree, read more here.
<Grid Button.Click="Button_Clicked">
<Grid>
<Button Content="Save" />
</Grid>
</Grid>
private void Button_Clicked(object sender, RoutedEventArgs e)
{
//your code here
}
Now the cursor is focusing in the TextBox. If i click on the the Button (RemoveLostFocus),The TextBox's Lost focus event get fired. But What i need is , Lost Focus event of TextBox should not fire. is there any way to do so ?.
private void Window_Loaded(object sender, RoutedEventArgs e)
{
txtUserName.Focus();
}
private void UserName_LostFocus(object sender, RoutedEventArgs e)
{
if (txtUserName.Text.Length < 1)
{
MessageBox.Show("UserName should not be empty");
}
}
private void btnCancel_Click(object sender, RoutedEventArgs e)
{
this.Close();
anotherWindow.Show();
}
You will want to use the FocusManager attached properties to apply the focus to the TextBox when the Button focus changes
Example:
<StackPanel>
<TextBox Name="txtbx" />
<Button Content="Click Me!" FocusManager.FocusedElement="{Binding ElementName=txtbx}"/>
</StackPanel>
With this solution the The TextBox will always be focused even when the Button is pressed and the TextBox LostFocus event will not be fired
you could Set Focusable="False" on the Button. here is a link of the answer enter link description here
Set Focusable Property
<Button Focusable="False" />
In the Click-Event of you Button you can do something like
this.textBox.Focus();
If your lostfocus-method looks like this:
private void UserName_LostFocus(object sender, RoutedEventArgs e){ ... }
you can prevent the lostfocus with the following code:
this.textBox.LostFocus -= UserName_LostFocus;
I have a ListView in my WPF UserControl using an ItemTemplate to display the items. Within the template is a button. When I select one item and then click on the button of another item, the previously selected item is still selected. I wonder how to automatically select the item the button is in when the button is clicked.
Xaml
<UserControl.Resources>
<DataTemplate x:Key="ItemTemplate">
<Border>
<Grid>
<!-- lots of stuff go here -->
<Button Click="MyButton_Click">Clickme</Button>
</Grid>
</Border>
</DataTemplate>
</UserControl.Resources>
<ListView x:Name="_listView"
ItemTemplate="{StaticResource ItemTemplate}">
</ListView>
C# Code behind
void MyButton_Click(object sender, RoutedEventArgs e)
{
MessageBox.Show( string.Format( "clicked on {0}",
this._listView.SelectedItem.ToString() ) ) ;
}
I would do it by getting the data context of the sender object. Assuming your listview is a list of objects of type MyObject... then something like this would allow you to reference the selected object.
void MyButton_Click(object sender, RoutedEventArgs e)
{
Button b = sender as Button;
if (b == null)
{
return;
}
MyObject o = b.DataContext as MyObject;
if (o != null)
{
// Put stuff for my object here
}
}
When you press the button your click / mouse down event is handled by the button and therefore does not route through to the ListView control.
A possible way to solve this is to manually set the listview.SelectedItem in the button click event.
I have a data template with a textbox and a button with some styles on it. I would like to have the button show the mouse over state when focus is on the textbox beside it. Is this possible?
I figure it would involve something like this. I can get the textbox through use of FindVisualChild and FindName. Then I can set the GotFocus event on the textbox to do something.
_myTextBox.GotFocus += new RoutedEventHandler(TB_GotFocus);
Here in TB_GotFocus I'm stuck. I can get the button I want to show the mouse over state of, but I don't know what event to send to it. MouseEnterEvent isn't allowed.
void TB_GotFocus(object sender, RoutedEventArgs e)
{
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(this.DataTemplateInstance);
DataTemplate template = myContentPresenter.ContentTemplate;
Button _button= template.FindName("TemplateButton", myContentPresenter) as Button;
_button.RaiseEvent(new RoutedEventArgs(Button.MouseEnterEvent));
}
I don't think it's possible to fake the event but you can force the button to render itself as if it had MouseOver.
private void tb_GotFocus(object sender, RoutedEventArgs e)
{
// ButtonChrome is the first child of button
DependencyObject chrome = VisualTreeHelper.GetChild(button, 0);
chrome.SetValue(Microsoft.Windows.Themes.ButtonChrome.RenderMouseOverProperty, true);
}
private void tb_LostFocus(object sender, RoutedEventArgs e)
{
// ButtonChrome is the first child of button
DependencyObject chrome = VisualTreeHelper.GetChild(button, 0);
chrome.ClearValue(Microsoft.Windows.Themes.ButtonChrome.RenderMouseOverProperty);
}
you need to reference PresentationFramework.Aero.dlll for this to work and then it will only work on Vista for the Aero theme.
If you want it to work for other themes you should make a custom controltemplate for each of the theme you want to support.
See http://blogs.msdn.com/llobo/archive/2006/07/12/663653.aspx for tips
As a follow up to jesperll's comment, I think you can get around making a custom template for each theme by dynamically setting the style to the one you want / null.
Here is my window, with the style defined (but not set to anything).
<Window x:Class="WpfApplication.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:local="clr-namespace:WpfApplication"
Title="Window1" Height="300" Width="300">
<Window.Resources>
<Style TargetType="{x:Type Button}" x:Key="MouseOverStyle">
<Setter Property="Background">
<Setter.Value>Green</Setter.Value>
</Setter>
</Style>
</Window.Resources>
<Grid Height="30">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="3*"/>
<ColumnDefinition Width="*"/>
</Grid.ColumnDefinitions>
<TextBox x:Name="MyTextBox" Grid.Column="0" Text="Some Text" Margin="2" GotFocus="TextBox_GotFocus" LostFocus="MyTextBox_LostFocus"/>
<Button x:Name="MyButton" Grid.Column="1" Content="Button" Margin="2" MouseEnter="Button_MouseEnter" MouseLeave="Button_MouseLeave" />
</Grid>
Instead of setting the style via triggers in the template, you can use events in your .cs file like so:
...
public partial class Window1 : Window
{
Style mouseOverStyle;
public Window1()
{
InitializeComponent();
mouseOverStyle = (Style)FindResource("MouseOverStyle");
}
private void TextBox_GotFocus(object sender, RoutedEventArgs e) { MyButton.Style = mouseOverStyle; }
private void MyTextBox_LostFocus(object sender, RoutedEventArgs e) { MyButton.Style = null; }
private void Button_MouseEnter(object sender, MouseEventArgs e) { ((Button)sender).Style = mouseOverStyle; }
private void Button_MouseLeave(object sender, MouseEventArgs e) { ((Button)sender).Style = null; }
}
You get a reference to the style in the constructor and then dynamically set it / unset it. This way, you can define what you want your style to look like in Xaml, and you don't have to rely on any new dependencies.