SQL: generate schedule table with different frequencies - sql-server

Question

I am working in SQL Server 2012. I have 3 tables. The first is a "schedule" table. Its structure is like:
CREATE TABLE schedule
(
JobID int
,BeginDate date
,EndDate date
)
Some sample data is:
INSERT INTO schedule
SELECT 1, '2017-01-01', '2017-07-31' UNION ALL
SELECT 2, '2017-02-01', '2017-06-30'
The second is a "frequency" table. Its structure is like:
CREATE TABLE frequency
(
JobID int
,RunDay varchar(9)
)
Some sample data is:
INSERT INTO frequency
SELECT 1, 'Sunday' UNION ALL
SELECT 1, 'Monday' UNION ALL
SELECT 1, 'Tuesday' UNION ALL
SELECT 1, 'Wednesday' UNION ALL
SELECT 1, 'Thursday' UNION ALL
SELECT 1, 'Friday' UNION ALL
SELECT 1, 'Saturday' UNION ALL
SELECT 2, 'Wednesday'
The third is a "calendar" table. Its structure is like:
CREATE TABLE calendar
(
CalendarFullDate date
,DayName varchar(9)
)
My goal is to "unpivot" the schedule table so that I create a row for each date spanning the date range in BeginDate and EndDate for each JobID. The rows must match the days in the frequency table per JobID.
Up until now, the frequencies of dates for each job are either daily or weekly. For this, I use the following SQL to generate my desired table:
SELECT
s.JobID
,c.CalendarFullDate
FROM
schedule AS s
INNER JOIN
calendar AS c
ON
c.CalendarFullDate BETWEEN s.BeginDate AND s.EndDate
INNER JOIN
frequency AS f
ON
f.JobID = s.JobID
AND f.RunDay = c.DayName
This doesn't work for frequencies that are higher than weekly (e.g., bi-weekly). To do so, I know that my frequency table would need to change structure. In particular, I would have to add a column that gives the frequency (e.g., daily, weekly, bi-weekly). And, I'm betting that I will need to add a week number column to the calendar table as well.
How can I generate my desired table to accommodate at least bi-weekly frequencies (if not higher frequencies)? For example, if JobID = 3 is a bi-weekly job that runs on Wednesday, and it's bound by BeginDate = '2017-06-01' and EndDate = '2017-07-31', then, for this job, I would expect the following in the result:
JobID Date
3 2017-06-07
3 2017-06-21
3 2017-07-05
3 2017-07-19

Answer 1

I have changed the schedule table instead of the frequency table. I have added a SkipWeeks field that should be set to 1 for bi-weekly, 2 to run the job every third week etc. I have used a table-valued function to return the right dates. I think this is what you wanted.
CREATE TABLE dbo.schedule
(
JobID int
,BeginDate date
,EndDate date
,SkipWeeks tinyint default 0
)
GO
INSERT INTO dbo.schedule
(JobID,BeginDate,EndDate)
SELECT 1, '2017-01-01', '2017-07-31' UNION ALL
SELECT 2, '2017-02-01', '2017-06-30'
GO
CREATE TABLE dbo.frequency
(
JobID int
,RunDay varchar(9),
primary key (
JobID,
RunDay
)
)
GO
INSERT INTO dbo.frequency
SELECT 1, 'Sunday' UNION ALL
SELECT 1, 'Monday' UNION ALL
SELECT 1, 'Tuesday' UNION ALL
SELECT 1, 'Wednesday' UNION ALL
SELECT 1, 'Thursday' UNION ALL
SELECT 1, 'Friday' UNION ALL
SELECT 1, 'Saturday' UNION ALL
SELECT 2, 'Wednesday'
GO
CREATE FUNCTION dbo.DateRangeTable(#pdStartDate date, #pdEndDate date, #piSkipWeeks tinyint)
RETURNS
#dates TABLE
(
[Date] date primary key,
DayName varchar(9)
)
AS
BEGIN
declare #ldDate date = #pdStartDate
declare #skipDecr smallint = #piSkipWeeks
while (#ldDate <= #pdEndDate) Begin
if #skipDecr = 0 Begin
insert into #dates
select #ldDate, format(#ldDate,'dddd')
End
--Start of New week? (% = MOD)
if datediff(d,#pdStartDate,#ldDate) % 7 = 0 Begin
if #skipDecr = 0 Begin
set #skipDecr = #piSkipWeeks
End else Begin
set #skipDecr = #skipDecr - 1
End
End
set #ldDate = dateadd(D,1, #ldDate)
End
RETURN
END
GO
INSERT INTO dbo.schedule
(JobID,BeginDate,EndDate,SkipWeeks)
SELECT 3, '2017-06-01','2017-07-31',1
GO
INSERT INTO dbo.frequency
SELECT 3, 'Wednesday'
GO
SELECT
s.JobID
,c.[Date]
FROM dbo.schedule AS s
cross apply dbo.DateRangeTable(s.BeginDate, s.EndDate, s.SkipWeeks) c
INNER JOIN dbo.frequency AS f
ON f.JobID = s.JobID
AND f.RunDay = c.DayName
GO