This question already has answers here:
Fortran increase dynamic array size in function
(3 answers)
Fortran array automatically growing when adding a value
(1 answer)
How to increase array size on-the-fly in Fortran?
(3 answers)
Closed 5 years ago.
I am trying to allocate an array and want to resize the array ie., grow the array size as and when required in the program.
My sample code looks like this
program main
implicit none
integer, allocatable, dimension(:)::test1
integer i, c1, c2
c1=10
c2=5
allocate(test1(1:c1))
! I basically want to do this
!allocate(test1(c1+1:c2))
end program main
How do I do this?
Related
This question already has answers here:
Print a Fortran 2D array as a matrix
(3 answers)
Printing a Fortran array with an implicit loop
(3 answers)
Closed 6 months ago.
I am trying to print a 2D matrix of real numbers using fortran 90 using format descriptor F, and it keeps being printed as a single column. what should I do?
My code:
do i=1,N
do j=1,M
A(i,j) = 2.4
end do
end do
write(*,'(F6.2)')((A(i,j), j=1,M), i=1,N)
This question already has answers here:
Fortran: Choosing the rank of an allocatable array
(2 answers)
Dynamic array rank
(2 answers)
Set array's rank at runtime
(4 answers)
Closed 3 years ago.
Is there a way I can declare an array which will be able to allocate any number of dimensions (in any shape) later in the code? Something like a the classic deferred shape but bearing in mind I do not know the rank, shape or size during declaration. For example, something similar to
real, allocatable :: a(:)
integer, parameter :: sh = [4,2,2]
allocate(a(sh))
which does not throw an error (of course it does in this case).
This question already has answers here:
Sum of a two dimensional array
(1 answer)
sum only on certain dimension
(1 answer)
Closed 4 years ago.
I am trying to figure how to do simple algebraic operations on a subset of elements in a multidimensional array and assign the result to another array with the same dimensions.
program hello
IMPLICIT NONE
REAL,DIMENSION(10,10,2,1) :: tmp1=2
REAL,DIMENSION(10,10,2,1) :: tmp2=1
INTEGER,DIMENSION(2) :: myind=(/1,2/)
This operations returns only one value
Print *, sum(tmp1(:,:,itree,:))
While this returns the correct results, however I would expect the same result than the second operation, maybe I am thinking in the R way.
Print *, tmp1(:,:,1,:)+tmp1(:,:,2,:)
end program Hello
How do I achieve the result of the second operation and assign it to another multidimensional array? Imagine my index is large so I can't type out each single term in the operation.
This question already has answers here:
How do I determine the size of my array in C?
(24 answers)
Closed 4 years ago.
We have been given a large array of unknown size with elements given , is there any function or something other through which we can find the size of that array in language C
int a[]={4,6,4,26,3,2,5,7,3,7,3,2,5,4,6,3,7,232,6,32,6,3,7,3,6,2,5,7,3,6,3,6,36,3,67,23,6};
The size in bytes you can get by
sizeof(a);
The number of elements in that array you can get by
sizeof(a)/sizeof(a[0]);
This question already has answers here:
Why int array[1000][1000] is memory issue in C program? [duplicate]
(1 answer)
Getting a stack overflow exception when declaring a large array
(8 answers)
Closed 5 years ago.
I'm using a pretty simple 2D array to store values (it's part of a mandelbrot set program).
int toBeWritten[xres][yres]; // xres and yres are calculated based on command line arguments
The 2D array works fine until my numbers get larger.
These, for example, work:
int toBeWritten[1024][1160];
int toBeWritten[2048][2321];
But when the size of the array grows to this:
int toBeWritten[4092][4637]; // the size I start getting seg faults
int toBeWritten[8192][9284]; // the largest size I want to get to
I get a seg fault if I try and access this array at any point after creating it.
Is it simply too big? Am I not allocating memory correctly?
If I can't make a 2D array this large, how could I store the values instead?
Thanks for any help!