TSQL Divide set in groups - sql-server

Question

I have a table with 3 fields: wk, cor, id
"wk" is the week, "cor" groups items from same location, "id" is the id of each item to retrieve from warehouse.
Given a certain number of items to retrieve, I must take almost the same quantity of items from each group ("cor" represents groups) for balancing the warehouse performance, respecting the week precedence (before going to the following week, the previous must be ehausted).
If you follow the link the image may be clear:
Data sample
rows are taken in this order:
yellow, orange, green, gray (this last one starts with "cor 2" because "cor 1" was the last used in week 28)
The RES column (done by hand in the sample) represents the right order I should take items; currently this is obtained with a cursor, which is very very slow and I'd like to do something better, if possible; I've tried with windowed functions, cte, recursive cte but was not able to get anything right.
With this script you can have the same table
DECLARE #t TABLE (wk int, cor int, id int)
INSERT INTO #t
(
wk
,cor
,id
)
VALUES
(28,1,4044534),
(28,1,6778322),
(28,1,7921336),
(28,1,4326390),
(28,2,2669622),
(28,2,6580257),
(28,2,1179795),
(28,3,3980111),
(28,3,2549129),
(28,3,6763533),
(29,1,6023538),
(29,1,8219574),
(29,1,3836858),
(29,2,3355314),
(29,2,148847),
(29,2,8083320),
(29,3,1359966),
(29,3,8746308)
The expected result:
All fields are given while the RES field must be calculated and represents the order in which items will be taken out (explained below the table).
+----+-----+---------+-----+
| wk | cor | id | RES |
+----+-----+---------+-----+
| 28 | 1 | 4044534 | 1 |
| 28 | 1 | 6778322 | 4 |
| 28 | 1 | 7921336 | 7 |
| 28 | 1 | 4326390 | 10 |
| 28 | 2 | 2669622 | 2 |
| 28 | 2 | 6580257 | 5 |
| 28 | 2 | 1179795 | 8 |
| 28 | 3 | 3980111 | 3 |
| 28 | 3 | 2549129 | 6 |
| 28 | 3 | 6763533 | 9 |
| 29 | 1 | 6023538 | 11 |
| 29 | 1 | 8219574 | 14 |
| 29 | 1 | 3836858 | 17 |
| 29 | 2 | 3355314 | 12 |
| 29 | 2 | 148847 | 15 |
| 29 | 2 | 8083320 | 18 |
| 29 | 3 | 1359966 | 13 |
| 29 | 3 | 8746308 | 16 |
+----+-----+---------+-----+
The algo is like that:
The older week must be first exausted (in the sample, wk 28 must be finished before taking itmes from wk 29)
Items must be equally reparted in "cor"s, so if 10 items are required they must come out like that: 3 from cor1,3 from cor2, 3 from cor3. The last one may come from whichever cor because 10 is not divisible by 3, obv
If 11 items are required; week 28 only contains 10 items so the last one will be taken from week 29, with the same principle: equally distribute the exit among cors, even if weeks change. If the last article from week 28 was taken from cor 1, the next one in week 29 will be taken from cor 2

Answer 1

Does this answer your problem ?
DROP TABLE IF EXISTS #temp
DROP TABLE IF EXISTS #temp2
CREATE TABLE #temp (idx INT PRIMARY KEY IDENTITY(1,1), wk int, cor int, id int)
INSERT INTO #temp
VALUES
(28,1,4044534),
(28,1,6778322),
(28,1,7921336),
(28,1,4326390),
(28,2,2669622),
(28,2,6580257),
(28,2,1179795),
(28,3,3980111),
(28,3,2549129),
(28,3,6763533),
(29,1,6023538),
(29,1,8219574),
(29,1,3836858),
(29,2,3355314),
(29,2,148847),
(29,2,8083320),
(29,3,1359966),
(29,3,8746308)
SELECT wk, cor, id
, ROW_NUMBER() OVER (ORDER BY wk, RES, idx) as RES
FROM (
SELECT idx
, wk
, cor
, id
, ROW_NUMBER() OVER (PARTITION BY wk, cor ORDER BY cor) AS RES
FROM #temp
) AS t
ORDER BY idx

Answer 2

You don't have the correct information in your test data to support the desired output.
If however, you were to have an identity column that represents the insertion order, you could use something like the following...
WITH cte_RankOrder AS (
SELECT
t.rn, t.wk, t.cor, t.id,
RankOrder = DENSE_RANK() OVER (PARTITION BY t.wk, t.cor ORDER BY t.rn, t.wk)
FROM
#t t
)
SELECT
ro.rn, ro.wk, ro.cor, ro.id,
RES = ROW_NUMBER() OVER (ORDER BY wk, ro.RankOrder, ro.cor)
FROM
cte_RankOrder ro
ORDER BY ro.rn;
results...
rn wk cor id RES
----------- ----------- ----------- ----------- --------------------
1 28 1 4044534 1
2 28 1 6778322 4
3 28 1 7921336 7
4 28 1 4326390 10
5 28 2 2669622 2
6 28 2 6580257 5
7 28 2 1179795 8
8 28 3 3980111 3
9 28 3 2549129 6
10 28 3 6763533 9
11 29 1 6023538 11
12 29 1 8219574 14
13 29 1 3836858 17
14 29 2 3355314 12
15 29 2 148847 15
16 29 2 8083320 18
17 29 3 1359966 13
18 29 3 8746308 16
HTH, Jason