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Can anyone please provide me the code in c programming language of problem in which we enter "ABCD" as an input in run time and we get "ZYXW" as output and I tried to solve this using ASCII Code
Hope this will help you . Read about ascii code of character . Also you have to gain knowledge of pointer and string .
#include<stdio.h>
int main(){
char ch[20];
scanf("%s",ch);
for(const char *s = ch; *s; ++s)
putchar('Z'-(*s-'A'));
return 0;
}
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I have following C program and I am not understanding some point of this program
#include <stdio.h>
int main()
{
char ara[100];
while(NULL != gets(ara))
{
printf("%s\n", ara);
}
return 0;
}
If I input some string like Hello World, this code return me the output same as input. But, what is NULL and gets?? Are they from C library? Why their colour not changed when I compile them?
Please read description of function gets()!
This function reads string from stdin. It returns NULL if found end of line or end of file before any characters.
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I have the following code:
int (*predicate)(char) = 0;
Can anyone tell me what this code means? What is the meaning of the word predicate in C?
The sentence is a declaration and definition of a pointer to a function taking one argument (char) and returning int. The pointer is initialized to the null pointer value.
The word "predicate" is the programmer's choice for the variable name.
Reference: cdecl
One might use predicate like this:
/* UNTESTED */
int IsLower(char c) { return c >= 'a' && c <= 'z'; }
int main () {
int (*predicate)(char);
predicate = IsLower;
if ( (*predicate)('f') == 1 ) printf("'f' is lower case!\n");
}
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C prog that generates/output 3 numbers (any combination from 1 - 20) when added is equal to 20. Hope you could help me with this one. Thanks in advance.
int main(){
int num1,num2,num3,sum;
do{
printf("%i+%i+%i=%i\n",num1,num2,num3,sum);
} while(sum=20); getch();
}
Try this one. You should be able to modify it according to your needs.
#include<stdio.h>
int main()
{
int i,j,k;
for(i=1;i<=20;i++)
for(j=1;j<=20;j++)
for(k=1;k<=20;k++)
if(i+j+k==20)
printf("%d %d %d\n",i,j,k);
return 0;
}
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I would like to iterate through all the record entries in /etc/passwd using just c api calls.
How can I do this?
Note: I've seen lots of examples of how to do this in other languages, but not found any examples in c.
This small program worked for me:
#include <stdio.h>
#include <pwd.h>
int main(int argc, char **argv) {
struct passwd *pw;
setpwent();
while ( (pw = getpwent()) != NULL )
{
printf("%s\n", pw->pw_name);
}
endpwent();
return 0;
}
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Its C program which is running x86_64 machine ,Wanted to know how output is coming like this way
main()
{
int *mess;
mess=malloc(1);
mess[0]=1;
//mess[1]=2;
printf("%d",mess);
}
Now output here is 6295568
How is it??
You're printing the address where your int is stored. You need
printf("%d",*mess);
to print its value.
You are also allocating too little space for your int, you should do:
int *mess = malloc(sizeof(int));
instead of
int *mess = malloc(1);