Partitioning inputs in scanf - c

Question

I want to accept the string and the float value in between the '#' is present. I have tried some what like this but it's not working; it is taking the whole input as the string.
#include <stdio.h>
#include <stdlib.h>
int main()
{
char str[10000];
float number;
scanf("%s#%f",str,&number); //input BMW#23.5 Expected output BMW 23.5
printf("%s %f\n",str,number); //actual output BMW#23.5 0.000000
}
Can anyone help me to solve this?

Answer 1

Get all as a char[] and parse it:
int main()
{
char str[10000];
float number;
scanf("%s", str);
char *at_pos = strrchr(str, '#');
if (at_pos)
{
number = atof(at_pos + 1);
// manage errors in number
printf("%s %f\n", str, number);
}
else
{
// manage error
}
}

Answer 2

//using the "[^#]" can really save your time.
//But you can do a lot in this approach of mine. Not just in that case.
//Feel free to ignore this but if you want to check and understand the logic there, there's the code that i wrote. Then you can just improve it. Tnx.
#include <stdio.h>
int main(void)
{
char str[10000];
char c;//The idea is, collect the input 1 by 1.
float f;
float power = 10;
int counter = 0;//We need this for the string.
c = getchar();//get the first character
str[counter] = c;//store it in the first element
counter++;
c = getchar();//Since we know that the input is string, we assume that there's a next character of course.
while(c != '#')
{
//But what if the user didn't enter a '#' character?
//Do this!
if(c == 10)
{
printf("I can't find the '#' there. =)\n\n");
return 0;
}
str[counter++] = c; //Test the recently collected character if
c = getchar(); //it's '#' or not. If not, then store it
} //in the string and continue to collect the
//next characters then store each of it in
//the string again and again until it reaches the '#'. From there you stop.
//after collecting all the characters, start collecting the numbers.
c = getchar();//collect
f = c - '0';//convert character to digit. I would bet you know this. Then store it in your float variable.
c = getchar();//collect again
//then test the recently collected again. Just like before
while(c != 10 && c != '.')//10 is the ASCII of the <enter> or new line right?. //We will also stop if we encounter '.' (dot)..
{
//while if it's not 10 or dot, add it your float variable. But don't forget the rules. use the power of 10 to.
f = f * 10 + (c - '0');
c = getchar();//collect again.
}
//do this again
c = getchar();
f += (c - '0') / power;//now divide it with power
c = getchar();
power *= 10;//then increase the power.
//Now collect the decimals
while(c != 10)//just like before
{
f += (c - '0') / power; //just do this over and
power *= 10; //over again until
c = getchar(); //it reaches the ASCII 10.
}
//Test it if you got it. =)
printf("%s # %f", str, f);
return 0;
}
//here's the clean code.
#include <stdio.h>
int main(void)
{
char str[1000];
char c;
float f;
float power = 10;
int counter = 0;
c = getchar();
str[counter] = c;
counter++;
c = getchar();
while(c != '#')
{
//But what if the user didn't enter a '#' character?
//Do this!
if(c == 10)
{
printf("I can't find the '#' there. =)\n\n");
return 0;
}
str[counter++] = c;
c = getchar();
}
c = getchar();
f = c - '0';
c = getchar();
while(c != 10 && c != '.')
{
f = f * 10 + (c - '0');
c = getchar();
}
c = getchar();
f += (c - '0') / power;
c = getchar();
power *= 10;
while(c != 10)
{
f += (c - '0') / power;
power *= 10;
c = getchar();
}
printf("%s # %f", str, f);
return 0;
}