I'm trying to pass two arguments into a script that looks through arrays with a lot of values.
Basically, I have a pretty big JSON file with around 15 arrays (google sheet data). I then want to take the 1st argument, which is one/multiple words and match it in the 1st array. And then I want to take index numbers in the 1st array and only look through those index numbers in the 2nd array for a string that matches the 2nd argument and return the strings and the index number for future use. For example:
sheetData = [ [ "1stArray", "other", "other" ], [ "2ndArray", "stuff", "2stuff", "stuff" "2stuff" ] ]
If I then would type in: node index.js other 2stuff. It is supposed to find the two "other" entries in the 1st array, then look at the "stuff" and the first "2stuff" in the 2nd array and then return both "2stuff" and the index number 2.
So far I've been able to find one of the strings matching the 1st argument in the 1st array, but not the other ones. Nor have I been able to even go through the 2nd array trying to find another string. Here is the code I've written so far for this:
let fs = {
help: config.help.failstack,
func: (client, message, args) => {
// E = Enhance, R = Repair/replace, D = re-enhance (degrade part),
let itemName = args[0];
let enhanceWanted = args[1];
debugger;
var a = sheetData.values[[0]];
var sheetItemName = a.indexOf(itemName);
if (sheetItemName === -1) {
message.reply('Command not formatted correctly.')
.then(msg => console.log())
.catch(console.error);
} else {
var sheetFailstack = a.indexOf(enhanceWanted);
message.reply()
.then(msg => console.log(`${msg}`))
.catch(console.error);
}
}
}
var sheetFailstack = a.indexOf[enhanceWanted];
should be:
var sheetFailstack = a.indexOf(enhanceWanted);
Related
I have a set of data in a Google spreadsheet in two columns. One column is a list of article titles and the other is the ID of a hotel that is in that article. Call it list1.
Example data
I would like returned a new list with article titles in one column, and an array of the hotel IDs in that article in the other column. Call it list2.
Example data
There are thousands of lines that this needs to be done for, and so my hope was to use Google Apps Script to help perform this task. My original thinking was to
Create column 1 of list2 which has the unique article titles (no script here, just the G-sheets =unique() formula.
Iterate through the titles in list2, looking for a match in first column of the list1
If there is a match:
retrieve its corresponding value in column 2
push it to an empty array in column two of list2
move onto next row in list1
if no longer a match, loop back to step 2.
I've written the following code. I am currently getting a type error (TypeError: Cannot read property '0' of undefined (line 13, file "Code")), however, I wanted to ask whether this is even a valid approach to the problem?
function getHotelIds() {
var outputSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('list2');
var lastRow = outputSheet.getLastRow();
var data = outputSheet.getRange(2,1,lastRow,2).getValues();
var workingSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('list1');
var lastActiveRow = workingSheet.getLastRow();
var itemIDS = [];
for (var i=1; i<=data.length; i++) {
var currentArticle = data[i][0];
var lookupArticle = workingSheet[i][0];
if (currentArticle === lookupArticle) {
var tempValue = [workingSheet[i][1]];
itemIDS.push(tempValue);
}
}
}
Use a simple google sheets formula:
You can use a very simple formula to achieve your goal instead of using long and complicated scripts.
Use =unique(list1!A2:A) in cell A2 of list2 sheet to get the unique hotels.
and then use this formula to all the unique hotels by dragging it down in column B.
=JOIN(",",filter(list1!B:B,list1!A:A=A2))
You got the idea right, but the logic needed some tweaking. The "undefined" error is caused by the workingSheet[i][0]. WorkingSheet is a Sheet object, not an array of data. Also, is not necessary to get the data from list2 (output), it is rather the opposite. You have to get the data from the list1 (source) sheet instead, and iterate over it.
I added a new variable, oldHotel, which will be used to compare each line with the current hotel. If it's different, it means we have reached a different Hotel and the data should be written in list2.
function getHotelIds() {
var outputSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('list2');
var outLastRow = outputSheet.getLastRow();
var workingSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('list1');
var lastActiveRow = workingSheet.getLastRow();
var sourceValues = workingSheet.getRange("A2:B" + lastActiveRow).getValues();
var itemIDS = [];
var oldHotel = sourceValues[0][0]; //first hotel of the list
for (var i = 0; i < sourceValues.length; i++) {
if (sourceValues[i][0] == oldHotel) {
itemIDS.push(sourceValues[i][1]);
/*When we reach the end of the list, the oldHotel variable will never be different. So the next if condition is needed. Otherwise it wouldn't write down the last Hotel.
*/
if (i == sourceValues.length - 1) {
outputSheet.getRange(outLastRow + 1, 1, 1, 2).setValues([
[sourceValues[i][0], itemIDS.toString()]
]);
}
} else {
outputSheet.getRange(outLastRow + 1, 1, 1, 2).setValues([
[sourceValues[i - 1][0], itemIDS.toString()]
]);
oldHotel = sourceValues[i][0]; //new Hotel will be compared
outLastRow = outputSheet.getLastRow(); //lastrow has updated
itemIDS = []; //clears the array to include the next codes
}
}
}
I also converted the itemIDS array to a String each time, so it's written down in a single cell without issues.
Make sure each column of the Sheet is set to "Plain text" from Format > Number > Plain Text
References
getRange
setValues
toString()
I'm trying to filter a set of objects based on values in one of their elements based on another array. I've got it working with filter just fine if the search is "OR" - it returns give me all objects for which at least one of the strings in the search array is found.
But I can't figure out how to make it work as an AND search - returning only the objects that match ALL of the strings in the search array.
Example:
struct Schedule {
let title: String
let classTypes: [String]
}
let schedule1 = Schedule(title: "One", classTypes: ["math","english","chemistry","drama"])
let schedule2 = Schedule(title: "Two", classTypes: ["pe","math","biology"])
let schedule3 = Schedule(title: "Three", classTypes: ["english","history","math","art"])
let schedules = [schedule1, schedule2, schedule3]
let searchArray = ["math", "english"]
//works for OR - "math" or "english"
var filteredSchedules = schedules.filter { $0.classTypes.contains(where: { searchArray.contains($0) }) }
I'd like to find a way for it to use the same search array
let searchArray = ["math", "english"]
But only return items 1 & 3 - as they both have BOTH math and english in the list.
There are good examples of AND conditions when the AND is across different search criteria: car type and colour - but I've been unable to find an example where the criteria are dynamically based on items in an array. For context, I could have dozens of schedules with 20+ class types.
You can work with a Set, isSubset will return true if the schedules element contains all elements of the searchSet
let searchSet = Set(searchArray)
var filteredSchedules = schedules.filter { searchSet.isSubset(of: $0.classTypes) }
As suggested by #LeoDabus it might be worth changing the type of classTypes to Set instead of arrays (if order doesn't matter) since they seems to be unique and then the filtering can be done in the opposite way without the need to convert searchArray each time
var filteredSchedules = schedules.filter { $0.classTypes.isSuperset(of: searchArray) }
The problem with the ECMA standard for sort of Object.keys() is known:
Object.keys() handle all keys with integer (example: 168), including integer as strings (example: "168"), as a integer. The result is, both are the same (168 === "168"), and overwrite itself.
var object = {};
object["168"] = 'x';
object[168] = 'y';
Object.keys(object); // Array [ "168" ]
object[Object.keys(object)]; // "y"
Interestingly, all keys (including pure integer keys) are returned as a string.
The ecma262 wrote about this: All keys will be handle as a integer, expect the key is a String but is not an array index.
https://tc39.es/ecma262/#sec-ordinaryownpropertykeys
That should tell us: 168 === "168". A toString() do not solve the problem.
var object = {};
object[[3].toString()] = 'z';
object[[1].toString()] = 'x';
object[[2].toString()] = 'y';
Object.keys(object);
// Array(3) [ "1", "2", "3" ]
Paradoxically, in this case, only integer apply as "enumerable" (it's ignoring array.sort(), that sort also strings with letters.).
My question about this is simple: How can i prevent the sort function in Object.keys()? I have testet the Object.defineProperties(object, 1, {value: "a", enumerable: true/false}), but that mean not realy enumerable in the case of integer or string or integer-like string. It means only should it be counted with or not. It means "counted" like omit (if it false), not "enumerabled" like ascending or descending.
A answere like that is not a good answer: Please use only letters [a-zA-Z] or leastwise a letter at the first position of keyword.
What I want: That the keys are not sorted, but output in the order in which they were entered, whether integer, string or symbol.
Disclaimer: Please solutions only in JavaScript.
Javascript Objects are unordered by their nature. If you need an ordered object-like variable I would suggest using a map.
To achieve what you're looking for with a map instead of object you'd do something like the below:
var map1 = new Map();
map1.set("123", "c");
map1.set(123, "b");
var iterator1 = map1.keys();
var myarray = [];
for (var i = 0; i < map1.size; i++) {
myarray.push(iterator1.next().value);
}
console.log(myarray);
// Array ["123", 123]
Unfortunately it's not compatible with IE and I'm not sure how else you could achieve what you need without it. A quick Google did return something about jQuery maps, though.
If you don't want to use jQuery and still need to support IE some points are below:
Is there anything stopping you using an array rather than JS object to store the data you need? This will retain the order per your requirements unlike objects. You could have an object entry in each iteration which represents the key then use a traditional foreach to obtain them as an array. I.e.
The array:
var test_array = [
{key: 123, value: 'a value here'},
{key: "123", value: 'another value here'}
];
// console.log(test_array);
Getting the keys:
var test_array_keys = [];
test_array.forEach(function(obj) { test_array_keys.push(obj['key']); } );
// console.log(test_array_keys);
Then if you needed to check whether the key exists before adding a new entry (to prevent duplicates) you could do:
function key_exists(key, array)
{
return array.indexOf(key) !== -1;
}
if(key_exists('12345', test_array_keys))
{
// won't get here, this is just for example
console.log('Key 12345 exists in array');
}
else if(key_exists('123', test_array_keys))
{
console.log('Key 123 exists in array');
}
Would that work? If not then the only other suggestion would be keeping a separate array alongside the object which tracks the keys and is updated when an entry is added or removed to/from the object.
Object Keys sorted and store in array
First Creating student Object. then sort by key in object,last keys to store in array
const student={tamil:100, english:55, sci:85,soc:57}
const sortobj =Object.fromEntries(Object.entries(student).sort())
console.log(Object.keys(sortobj))
use map instead of an object.
let map = new Map()
map.set("a", 5)
map.set("d", 6)
map.set("b", 12)
to sort the keys (for example, to update a chart data)
let newMap = new Map([...map.entries()].sort())
let keys = Array.from(newMap.keys()) // ['a','b','d']
let values = Array.from(newMap.values()) // [5,12,6]
If I have the following array and I want to create a string array containing the door prizes by mapping the mysteryDoors array as keys for the dictionary, and get the corresponding values into a new array.
Thus I would get a string array of ["Gift Card", "Car", "Vacation"] how can I do that?
let mysteryDoors = [3,1,2]
let doorPrizes = [
1:"Car", 2: "Vacation", 3: "Gift card"]
You can map() each array element to the corresponding value in
the dictionary. If it is guaranteed that all array elements are
present as keys in the dictionary then you can do:
let mysteryDoors = [3, 1, 2]
let doorPrizes = [ 1:"Car", 2: "Vacation", 3: "Gift card"]
let prizes = mysteryDoors.map { doorPrizes[$0]! }
print(prizes) // ["Gift card", "Car", "Vacation"]
To avoid a runtime crash if a key is not present, use
let prizes = mysteryDoors.flatMap { doorPrizes[$0] }
to ignore unknown keys, or
let prizes = mysteryDoors.map { doorPrizes[$0] ?? "" }
to map unknown keys to a default string.
If you have to use map, then it would look something like the following:
let array = mysteryDoors.map { doorPrizes[$0] }
After re-reading the Apple Doc example code and changing it to what I need. I believe this is it (Almost). Unfortunately it is now in string format with new lines...
let myPrizes = doorPrizes.map { (number) -> String in
var output = ""
output = mysteryDoors[number]!
return output;
}
i have a struct array that i want "break up" into smaller arrays that can be called as needed or at least figure out how i can map the items needed off one text value.
the struct:
struct CollectionStruct {
var name : String
var description : String
var title : String
var image : PFFile
var id: String
}
and the array made from the struct
var collectionArray = [CollectionStruct]()
var i = 0
for item in collectionArray {
print(collectionArray[i].name)
i += 1
}
printing partArray[i].name gives the following result:
pk00_pt01
pk00_pt02
pk00_pt03
pk01_pt01
pk01_pt02
pk01_pt03
pk01_pt04
pk01_pt05
pk01_pt06
pk01_pt07
pk01_pt08
this is just some test values but there could be thousands of entries here so i wanted to filter the entire array just by the first 4 characters of [i].name i can achieve this by looping through as above but is this achievable using something like .map?
I wanted to filter the entire array just by the first 4 characters of
[i].name
You can achieve this by filtering the array based on the substring value of the name, as follows:
let filteredArray = collectionArray.filter {
$0.name.substring(to: $0.name.index($0.name.startIndex, offsetBy: 4)).lowercased() == "pk00"
// or instead of "pk00", add the first 4 characters you want to compare
}
filteredArray will be filled based on what is the compared string.
Hope this helped.
If you want to group all data automatically by their name prefix. You could use a reducer to generate a dictionary of grouped items. Something like this:
let groupedData = array.reduce([String: [String]]()) { (dictionary, myStruct) in
let grouper = myStruct.name.substring(to: myStruct.name.index(myStruct.name.startIndex, offsetBy: 4))
var newDictionart = dictionary
if let collectionStructs = newDictionart[grouper] {
newDictionart[grouper] = collectionStructs + [myStruct.name]
} else {
newDictionart[grouper] = [myStruct.name]
}
return newDictionart
}
This will produce a dictionary like this:
[
"pk00": ["pk00_pt01", "pk00_pt02", "pk00_pt03"],
"pk01": ["pk01_pt01", "pk01_pt02", "pk01_pt03", "pk01_pt04", "pk01_pt05", "pk01_pt06", "pk01_pt07"],
"pk02": ["pk02_pt08"]
]
Not sure if i am understanding you correctly but it sounds like you are looking for this...
To create a new array named partArray from an already existing array named collectionArray (that is of type CollectionStruct) you would do...
var partArray = collectionArray.map{$0.name}