Shared Memory - Process communication - c

Question

What I have to do:
-Create a shared memory segment.
-fill an array with a fixed number of integers e.g 100
-pass these created numbers to a child process in blocks of 10 each.
-in the child process: output these numbers
So this is basically a communication between two processes via a shared memory segment.
My question: So far I can pass the first 10 numbers to the child process .. but I don't really know how to pass the next 10 numbers to the very same child process to output it without creating more child processes .. I thought maybe I could simply wrap everything in a while loop but then everytime a new child process is created which is not what I want.
Right now I have the following Code:
#include <stdio.h>
#include <sys/ipc.h>
#include <sys/shm.h>
#include <sys/types.h>
#include <unistd.h>
#include <stdlib.h>
#include <string.h>
#define N_SHARED 10
#define SIZE 100
int main(int argc, char **argv){
int shID;
int *myPtr;
int i;
int counter = 0;
int array[SIZE];
for(i=0;i<SIZE;i++){
array[i] = lrand48();
}
/* Shared Memory Creation */
shID = shmget(223520, N_SHARED, IPC_CREAT | 0666);
if (shID >= 0) {
/* get memory */
myPtr = shmat(shID, 0, 0);
if (myPtr==(int *)-1) {
perror("shmat");
} else {
/* memory is accessible */
for (i=0; i<N_SHARED; i++) {
myPtr[i] = array[counter];
counter += 1;
}
// create Child Process
pid_t child = fork();
if(child == 0){
sleep(5);
shID = shmget(223520, N_SHARED, 0666);
if (shID >= 0) {
myPtr = shmat(shID, 0, 0);
if (myPtr==(int *)-1) {
perror("shmat");
} else {
for (i=0; i<N_SHARED; i++) {
printf("%d\n", myPtr[i]);
}
shmdt(myPtr);
}
}else {
/* shmget went wrong */
perror("shmget");
}
}
/* give up memory */
shmdt(myPtr);
}
} else {
/* shmget went wrong */
perror("shmget");
}
}