Store words in char array C language - c

Question

I have this code:
char *pch;
pch = strtok(texto," ");
while (pch != NULL)
{
pch = strtok (NULL, " ");
}
My "texto" variable have something like "This is my text example".
And i need to store each value comming from pch in while, in an array of characteres, but i really dont know how to do it.
I need something like that, each value in array will have a word, so:
"This is my text example".
Array[0][20] = This;
Array[1][20] = is;
Array[2][20] = my;
Array[3][20] = text;
Array[4][20] = example;
The pch in while having all these words already split, but I don't know how to add into a char array, or how I will declare him too.

Answer 1

Consider the following example:
#include <stdio.h>
#include <string.h>
#define MAXSTRLEN 20
#define MAXWORD 6
int main(void)
{
char arr[MAXWORD][MAXSTRLEN+1] = {0};
char str[] ="This is my text example";
char *pch;
int i = 0;
pch = strtok (str," ");
while (pch != NULL && i < MAXWORD)
{
strncpy(arr[i++], pch, MAXSTRLEN);
pch = strtok (NULL, " ");
}
return 0;
}

Answer 2

This should work. Use strcpy to copy pch to character array.
char str[] ="This is my text example";
char *pch;
int i = 0;
pch = strtok (str," ");
char a[10][20];
while (pch != NULL)
{
strcpy(a[i++], pch);
pch = strtok (NULL, " ");
}
And as #stackptr has suggested dont use strtok and instead use strtok_r . For more info on this.