arithmetic average of an array with range -5 to 5 in c - c

Question

I want to generate the arithmetic average from an array, but only with values from a certain range (here from -5 to 5)
Is this code ok?
#include <stdio.h>
int main()
{
int n, i;
float num[100], sum = 0.0, average;
printf("Enter the numbers of elements: ");
scanf("%d", &n);
while (n > 10 || n <= 0)
{
printf("Error! number should in range of (1 to 10).\n");
printf("Enter the number again: ");
scanf("%d", &n);
}
for(i = 0; i < n; ++i)
{
printf("%d. Enter number: ", i+1);
scanf("%f", &num[i]);
if( num[i]< 5 && num[i]>-5){
sum+= num[i];
}
average = sum / n;
printf("Average = %.2f", average);
return 0;
edit : I am sorry I must have missed copying the whole code in th eheat of the moment.
It is a simple question I know bu I cannot seem to get it to work. Maybe the lack of sleep is making me go insane

Answer 1

Your code is wrong.
And it's poorly formatted and that's the reason why you don't see why it's wrong:
Your poorly formatted code:
...
for(i = 0; i < n; ++i)
{
printf("%d. Enter number: ", i+1);
scanf("%f", &num[i]);
if( num[i]< 5 && num[i]>-5){
sum+= num[i];
} // it looks as if the for loop end here, but it doesn't
average = sum / n;
printf("Average = %.2f", average);
return 0;
} // the for loop actually ends here
The same code formatted correctly:
for (i = 0; i < n; ++i)
{
printf("%d. Enter number: ", i + 1);
scanf("%f", &num[i]);
if (num[i]< 5 && num[i]>-5) {
sum += num[i];
}
average = sum / n;
printf("Average = %.2f", average);
return 0;
} // <<< the for loop ends here
Correct code (look at the comments for an explanation):
...
int nbofnumbers = 0; // number of numbers in the interval [-5,5]
for (i = 0; i < n; ++i)
{
printf("%d. Enter number: ", i + 1);
scanf("%f", &num[i]);
if (num[i]< 5 && num[i]>-5) {
nbofnumbers++;
sum += num[i];
}
} // for loop must end here
average = sum / nbofnumbers; // we divide by the number of numbers
// in the interval [-5,5], not by n
printf("Average = %.2f", average);
return 0;
...