Redux-form: Field value from state isn't submitted - reactjs

Question

I have a field (source-file) in redux-form which is being updated by a change in the application state. The state value is being properly delivered to the field but when clicking submit, only the first field (name) is submitted (which I fill in interactively).
What am I doing wrong here?
import React, { Component, PropTypes } from 'react';
import { reduxForm, Field } from 'redux-form';
import { connect } from 'react-redux';
import { Link } from 'react-router';
import * as actions from '../../actions/job_actions';
import UploadPage from './upload_page';
const renderField = field => (
<div>
<label>{field.input.label}</label>
<input {...field.input}/>
{field.touched && field.error && <div className="error">{field.error}</div>}
</div> );
class JobForm extends Component {
handleFormSubmit(formProps) {
this.props.createJob(formProps); }
render() {
const { handleSubmit } = this.props;
return (
<div>
<form onSubmit={handleSubmit(this.handleFormSubmit.bind(this))}>
<label>Title</label>
<Field name="name" component={renderField} type="text" />
<label>Input File</label>
<Field name="source_file" component={() => {
return (
<div class="input-row">
<input type="text" value={this.props.uploadedFile} />
</div>
)
}} />
<button type="submit" className="btn btn-
primary">Submit</button>
</form>
</div>
);
};
}
const form = reduxForm({ form: 'JobForm' });
function mapStateToProps({uploadedFile}) { return { uploadedFile }; }
export default connect(mapStateToProps, actions)(form(JobForm));

Answer 1

If you want redux-form to include your field, then you'll need to render it as an actual field (as you do with your renderField).
If you don't want to treat it as an actual field, then the redux-form author suggests injecting the values from state within your submit handler. Maybe something like this:
handleFormSubmit(formProps) {
this.props.createJob({ ...formProps, source_file: this.props.uploadedFile} );
}