Creating a matrix and free() problems - c - c

Question

it seems i have some problems in my code. the first one is that i cant use the free function correctly:"heap corruption detected".
in the second part of my work i wanted to create a matrix:it puts a red mark under the j and then the compiler says that subscript requires array and pointer type.
i only wanted to create a two dimension matrix.
thanks for your help!!!
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include <math.h>
void main()
{
char *word[1000] = { 0 }, letter[1000], *temparr, *originalarr;
int i = 0, j = 0, counter = 0, k = 0, w = 0, anagram = 0, size = 0, *mat;
for (i = 0; letter[i] != '\n'; i++)
{
letter[i] = getchar();
counter++;
if (letter[i] == ' ' || letter[i] == '\n')
{
if (letter[i] == 10)
{
letter[i] = 0;
word[j] = malloc(sizeof(char*)*(counter - 1));
strcpy_s(word[j], (counter - 1) * sizeof(char*), &letter[i - (--counter)]);
break;
}
if (letter[i - 1] == ' ')
continue;
letter[i] = '\0';
word[j] = malloc(sizeof(char*)*counter);
strcpy_s(word[j], (counter - 1) * sizeof(char*), &letter[i - (--counter)]);
letter[i] = ' ';
counter = 0;
j++;
}
}
while (j > 0)
{
printf_s("%s ", word[j--]);
if (j == 0)
printf_s("%s", word[j]);
}
for (j = 0; word[j] != 0; j++)
{
originalarr = (char*)malloc((sizeof(char) * strlen(word[j])));
strcpy_s(originalarr, strlen(word[j]) + 1, word[j]);
for (i = 0; word[i] != 0; i++)
{
temparr = (char*)malloc((sizeof(char) * strlen(word[i])));
strcpy_s(temparr, strlen(word[i]) + 1, word[i]);
counter = 0;
if (strlen(originalarr) != strlen(temparr))
continue;
for (k = 0; originalarr[k] != 0; k++)
{
for (w = 0; w < strlen(temparr); w++)
{
printf_s("temparr - %c ", temparr[w]);
printf_s("original - %c\n", originalarr[k]);
if (originalarr[k] == temparr[w])
{
temparr[w] = '0';//problem, but cant be equal to 0
counter++;
printf_s("counter- %d\n", counter);
}
}
}
if (counter == strlen(originalarr))
anagram++;
free(temparr);//problem
}
}
k = 0;
size = ceil(sqrt(strlen(letter)));
mat = (int*)malloc((sizeof(int) * size));
for (i = 0; i < size; i++)
{
mat[i] = (int)malloc((sizeof(int) * size));
for (j = 0; j < size; j++)
mat[i][j] = '\0';
}
for (i = 0; i < size; i++)
for (j = 0; j < size; j++)
{
mat[i][j] = letter[k];
k++;
}
}

Answer 1

For the second part of your question you need to declare a pointer to a pointermat instead of a simple pointer as you have done. Then allocate as shown.
int ** mat;
mat = malloc((sizeof(int*) * size));
for (i=0; i<size; i++)
mat[i] = malloc( sizeof(int) * size));
You can use this array mat as a 2D array mat[i][j]