Gulp minify Angular.js & it's modules - angularjs

Question

I have a gulp script that minifies my javascript:
gulp.task("min:js",
function() {
return gulp.src([paths.js, "!" + paths.minJs])
.pipe(concat(paths.concatJsDest))
.pipe(uglify())
.pipe(gulp.dest("."));
});
When it minifies
<script src="Scripts/Min/modernizr.js"></script>
<script src="Scripts/Min/main.js"></script>
<script src="Scripts/Min/angular.js"></script>
That seems to work, but when I try to minify
<script src="Scripts/Min/modernizr.js"></script>
<script src="Scripts/Min/main.js"></script>
<script src="Scripts/Min/angular.js"></script>
<script src="Scripts/Min/angular-ui-router.js"></script>
I get angular is not defined in my console and the site doesn't come up.
I'm relatively new to gulp and angular, am I missing something here?
Update
Paths:
paths.concatJsDest = "Scripts/site.min.js";
paths.js = "Scripts/Min/**/*.js";

Answer 1

Now that I've narrowed my problem down to file order, I can use gulp-htmlreplace to load angular.min.js first:
<!--build:angular-->
<script src="Scripts/Src/angular.js"></script>
<!-- endbuild -->
<!-- build:js -->
<script src="Scripts/Min/modernizr.js"></script>
<script src="Scripts/Min/main.js"></script>
<script src="Scripts/Min/loading-bar.js"></script>
<script src="Scripts/Min/angular-ui-router.js"></script>/script>
<!-- endbuild -->
And the gulp steps:
gulp.src('Index.html')
.pipe(htmlreplace({
js: paths.concatJsDest,
angular: paths.angularmin
}))
.pipe(gulp.dest('.'));
});
gulp.task("min:js",
function() {
return gulp.src([paths.js, "!" + paths.minJs])
.pipe(concat(paths.concatJsDest))
.pipe(uglify())
.pipe(gulp.dest("."));
});
My consideration is that I'll be adding many more modules to my angular as I build out the site, so a static order isn't ideal.