file field doesn't gets saved with wagtail inline field - wagtail

I'm trying to user inline panels but for plain Django model in wagtail like it's described here. I got it working with a plain char field.
When I try to use a models.FileField I get an error message after the save action. "No file chosen". It seem it doesn't saves the file
Here is the code I used:
from django.db import models
from modelcluster.models import ClusterableModel
from wagtail.wagtailadmin.edit_handlers import FieldPanel, InlinePanel
from wagtail.wagtailsnippets.models import register_snippet
from modelcluster.fields import ParentalKey
class Slide(models.Model):
file = models.FileField('PDF / Image',null=True, upload_to="slides")
mymodel = ParentalKey('mymodel.mymodel', related_name='slides',
on_delete=models.CASCADE, null=True)
#register_snippet
class MyModel(ClusterableModel):
name = models.CharField(max_length=255)
number = models.IntegerField()
panels = [
FieldPanel('name'),
FieldPanel('number'),
InlinePanel('slides', label="slides"),
]
def __str__(self):
return self.name
How to get the files saved? Should it be possible?

This is a known bug that will be fixed in the next release of Wagtail (due in a couple of weeks): https://github.com/wagtail/wagtail/issues/2251

Related

Wagtail snippets dont migrate

I started to build startup project using Django and Wagtail, but I have one problem, snippets don't migrate.
limbro/
config/
website/
this is a base project structure.
PS D:\Documents\GitHub\limbro.io> python manage.py makemigrations
No changes detected
PS D:\Documents\GitHub\limbro.io>
snippets.py file in website
from django.db import models
from wagtail.snippets.models import register_snippet
from wagtail.admin.edit_handlers import FieldPanel
#register_snippet
class Footer(models.Model):
facebook_page = models.URLField(blank=True)
instagram_page = models.URLField(blank=True)
panels = [
FieldPanel('facebook_page'),
FieldPanel('instagram_page'),
]
def __str__(self):
return "Footer"
class Meta:
verbose_name = "Footer"
verbose_name_plural = "Footer"
The Django migration framework specifically looks for a module called models within your app - if your models are defined in snippets.py, it won't find them. One way to fix this is to add an import line to models.py:
from .snippets import Footer

How to give user option to select a wagtail collection of images in page?

I am looking for a way to show a list of wagtail collection as a field in a page (just like it showing when you upload an image). A user can select a collection and I can programmatically filter the images to the selected collection. I am still new to wagtail and I am not sure how should I implement this in code.
Thank you in advance for your help.
So there's a couple ways you can do this. The first, and probably the least-ideal way is to register Collection as a snippet and use a SnippetChooserPanel.
"""Register Collection snippet."""
from wagtail.snippets.models import register_snippet
from wagtail.core.models import Collection
# Register Collections as Snippets so we can use the SnippetChooserPanel to select a collection
register_snippet(Collection)
And then in your model you can use a SnippetChooserPanel, like so (note, this is all untested code)
from django.db import models
from wagtail.core.models import Page
class CustomPage(Page):
# ...
collection = models.ForeignKey(
'wagtailcore.Collection',
null=True,
blank=True,
on_delete=models.SET_NULL,
related_name='+',
)
content_panels = Page.content_panels + [
# ...
SnippetChooserPanel('collection'),
]
#gasman's comment on the answer has a link to another solution that's much more elegant than mine.
I've managed to do this using wagtail-generic-chooser just following the instructions on the README.md, and using wagtail core Collection model instead of People.
Aug 2022 - Wagtail 2.15.5 - display Wagtail hierarchical collection
from wagtail.admin.templatetags.wagtailadmin_tags import format_collection
class Meeting(models.Model):
COLLECTION_CHOICES = []
for c in Collection.objects.all():
COLLECTION_CHOICES.append((c.id, format_collection(c)))
title = models.CharField(max_length=100)
collection = models.ForeignKey(Collection, on_delete=models.PROTECT, help_text="Choose the 'Collection' folder for the meeting's related documents", choices=COLLECTION_CHOICES)
Edit: If you add a new collection to collections and go back the this Meeting model the new collection will not be in the list. As the COLLECTION_CHOICES is only created once for optimization. If you want a dynamic collection choice you need to make a custom form on top of your model e.g.
from wagtail.admin.forms import WagtailAdminModelForm
class MeetingAdminForm(WagtailAdminModelForm):
# This below field will be automatically added to the Meeting panel fields
meeting_collection = forms.ChoiceField()
def __init__(self, *args, **kwargs):
super(MeetingAdminForm, self).__init__(*args, **kwargs)
self.fields['meeting_collection'] = forms.ChoiceField(
initial=self.instance.collection_id,
choices=[(c.id, format_collection(c)) for c in Collection.objects.all()]
)
def save(self, commit=True):
instance = super().save(commit=False)
instance.collection_id = self.cleaned_data['meeting_collection']
if commit:
instance.save()
return instance
class Meeting(models.Model):
base_form_class = MeetingAdminForm
class Meta:
""" Meta options """
ordering = ['title']
title = models.CharField(max_length=100)
meeting_datetime = models.DateTimeField()
location = models.TextField(null=True)
collection = models.ForeignKey(Collection, on_delete=models.PROTECT, help_text="Choose the 'Collection' folder for the meeting's agenda, minutes and related documents")
committee = models.ForeignKey(Committee, on_delete=models.CASCADE)
panels = [
FieldPanel('title'),
FieldPanel('meeting_datetime'),
FieldPanel('location'),
FieldPanel('meeting_collection'),
FieldPanel('committee'),
]

Django DRF Foreign Key

This question or many like it has been asked multiple times but for some reason I am unable to find the answer.
I do have this working to an extent in the way that if you go on the api pages, it renders, creates and updates without problem. The issue is displaying a field (title) from the nested object instead of just the primary key on the front end.
Some background before getting into the code:
Races is a finite list (e.g. Race1, Race2, Race3) and the front end does not have the ability to add more.
Cards is not finite, but each card must link to an existing Race (this currently does so by Primary Key).
The front end should display the card_text and race title of the linked race.
It also has the ability to add a new card but this works fine.
I have had this working with separate serializers for read and create/update where the read has a 'depth = 1' to pull through the entire object but the create/update doesn't and you then parse the object and send the primary key back (I couldn't find a way of doing this in the serializer, is it possible?).
So basically my question is, are you meant to pass the entire object through and parse it on a POST method, or do you pass the primary key and pull in the linked objects (Races) and use the primary key as an index (e.g. Races[card_race]). Also, why is 'linked_race' not coming through to the front end?
I realise I've almost answered my own question but as I'm new to Django I'm looking for the correct conventions and who knows, it may save someone else time when searching for the same answer.
urls.py
from .api import CardViewSet, RaceViewSet
from rest_framework.routers import DefaultRouter
from django.conf.urls import url, include
from .views import landing
router = DefaultRouter()
router.register(r'cards', CardViewSet)
router.register(r'races', RaceViewSet)
urlpatterns = [
url(r'^$', landing),
url(r'^api/', include(router.urls)),
]
api.py
from rest_framework.viewsets import ModelViewSet
from .serializers import CardSerializer, RaceSerializer
from .models import Card, Race
class CardViewSet(ModelViewSet):
queryset = Card.objects.filter(active=True)
def get_serializer_class(self):
return CardSerializer
def perform_create(self, serializer):
serializer.save(creator=self.request.user)
class RaceViewSet(ModelViewSet):
queryset = Race.objects.filter(active=True)
serializer_class = RaceSerializer
models.py
from django.db import models
from django.conf import settings
User = settings.AUTH_USER_MODEL
class Race(models.Model):
id = models.IntegerField(primary_key=True)
title = models.CharField(max_length=30, blank=False)
active = models.BooleanField(default=True)
def __str__(self):
return "{}".format(self.title)
def __unicode__(self):
return self.title
class Card(models.Model):
card_text = models.CharField(max_length=100, blank=False)
card_description = models.CharField(max_length=100, blank=True)
card_race = models.ForeignKey(Race, related_name='linked_race', on_delete=models.CASCADE)
creator = models.ForeignKey('auth.User', on_delete=models.CASCADE)
created = models.DateTimeField(auto_now_add=True)
active = models.BooleanField(default=True)
def __str__(self):
return self.card_text
class Meta:
ordering = ('created',)
serializers.py
from rest_framework import serializers
from .models import Card, Race
class RaceSerializer(serializers.ModelSerializer):
class Meta:
model = Race
fields = '__all__'
class CardSerializer(serializers.ModelSerializer):
linked_race = RaceSerializer(read_only=True, many=True)
class Meta:
model = Card
fields = 'id', 'card_text', 'card_description', 'card_race', 'linked_race',
Javascript extract (AngularJS)
$http.get('/api/races/').then(function (response) {
$scope.races = response.data;
$scope.selectedOption = $scope.races[0];
});
$scope.cards = [];
$http.get('/api/cards/').then(function (response) {
$scope.cards = orderBy(response.data, 'created', true);
});
html extract (AngularJS)
<div class="races--row" ng-repeat="c in cards | filter : card_filter |
orderBy : sortVal : sortDir" ng-class-odd="'odd'" ng-click="openModal(c)">
<div class="races--cell race">{{ c.card_race.title }}</div>
<div class="races--cell card-text">{{ c.card_text }}</div>
</div>
Your first "problem" is with the Card model (I say problem because I don't think you intended to do this). You're defining related_name='linked_race' for the card_race field. This related_name is the name you use to refer to a card FROM a race.
I would suggest you leave it out and use the default that Django already gives us (i.e. my_race.card_set.all() in this case). So change change that field in the Card model to:
class Card(models.Model):
...
card_race = models.ForeignKey(Race, on_delete=models.CASCADE)
...
And let's change the card serializer to:
class CardSerializer(serializers.ModelSerializer):
# no more linked_race
class Meta:
model = Card
fields = ('id', 'card_text', 'card_description', 'card_race')
Alright, this is a vary basic model serializer and you won't see details of a race yet. So now let's get to your main problem which was that you wanted to:
see the details of the associated race of a card
perform create/get/update/delete operations using the same serializer
For this, let's further change the CardSerializer to include another field called race_detail:
class CardSerializer(serializers.ModelSerializer):
race_detail = RaceSerializer(source='card_race', read_only=True)
class Meta:
model = Card
fields = ('id', 'card_text', 'card_description', 'card_race', 'race_detail')
We have defined two serializer fields for the same model field. Note the source and read_only attributes. This makes this field available when you GET a card (which is what we want), but not when you're performing POSTs or PUTs (which avoids the problem of sending the whole race object and parsing and stuff). You can just send the race id for the card_race field and it should work.

Wagtail Inlinepanel demo erorr

I am relatively new to Django Wagtail and I was following the demo from the docs.wagtail.io website which can be found here on how to add a list of Links to a Page using an InlinePanel with Related links
I seem to have reached an error that I donot fully understand it's meaning.
The error says
AttributeError: type object 'BookPageRelatedLinks' has no attribute 'rel'
The code for the demo is as follows
from wagtail.wagtailcore.models import Orderable, Page
from modelcluster.fields import ParentalKey
from wagtail.wagtailadmin.edit_handlers import FieldPanel,InlinePanel
from django.db import models
class BookPage(Page):
# The abstract model for related links, complete with panels
class RelatedLink(models.Model):
title = models.CharField(max_length=255)
link_external = models.URLField("External link", blank=True)
panels = [
FieldPanel('title'),
FieldPanel('link_external'),
]
class Meta:
abstract = True
# The real model which combines the abstract model, an
# Orderable helper class, and what amounts to a ForeignKey link
# to the model we want to add related links to (BookPage)
class BookPageRelatedLinks(Orderable, RelatedLink):
page = ParentalKey('demo.BookPage', related_name='related_links')
content_panels = Page.content_panels + [
InlinePanel('BookPageRelatedLinks', label="Related Links"),
]
My primary objective was to learn this so I can add image links to a sidebar on a BlogPage app I am developing.
Your InlinePanel declaration isn't quite correct - it needs to be:
InlinePanel('related_links', label="Related Links")
Here's what's going on:
By defining a ParentalKey with related_name='related_links', you set up a one-to-many relation called related_links on BookPage. This allows you to retrieve all of the BookPageRelatedLinks objects associated with a given BookPage instance (for example, if your BookPage instance was called page, you could write page.related_links.all()).
The InlinePanel declaration then tells Wagtail to make the related_links property editable within the admin.
The reason you're getting a misleading error message is that you've defined the RelatedLink and BookPageRelatedLinks classes inside the BookPage - which is a little bit unusual, but still valid. This results in BookPageRelatedLinks being defined as a property of BookPage (i.e. BookPage.BookPageRelatedLinks). Then, when Wagtail tries to set up the InlinePanel, it retrieves that property and fails because it's not the expected type of object (it's a class definition, not a relation).
If you write your models file in the more conventional way, with the related models defined below (or above) BookPage:
class BookPage(Page):
content_panels = Page.content_panels + [
InlinePanel('BookPageRelatedLinks', label="Related Links"),
]
# The abstract model for related links, complete with panels
class RelatedLink(models.Model):
title = models.CharField(max_length=255)
link_external = models.URLField("External link", blank=True)
panels = [
FieldPanel('title'),
FieldPanel('link_external'),
]
class Meta:
abstract = True
# The real model which combines the abstract model, an
# Orderable helper class, and what amounts to a ForeignKey link
# to the model we want to add related links to (BookPage)
class BookPageRelatedLinks(Orderable, RelatedLink):
page = ParentalKey('home.BookPage', related_name='related_links')
...then you would get a more informative error: AttributeError: type object 'BookPage' has no attribute 'BookPageRelatedLinks'.

Django-nonrel in Google App Engine ListField

I am trying to build an example app in Google App Engine using django-nonrel. and am having problems implementing ListField attribute into a model.
I have created an app test_model and have included it as an installed app in my settings. The model.py is:
from django.db import models
from djangotoolbox import *
from dbindexer import *
# Create your models here.
class Example(models.Model):
some_choices = models.ListField('Choice_examples')
notes = models.CharField(max_length='20')
updated_at = models.DateTimeField(auto_now=True)
def __unicode__(self):
return u'%s' % (self.notes)
class Choice_examples(models.Model):
name = models.CharField(max_length='30')
def __unicode__(self):
return u'%s' % (self.name)
The above example gives me:
AttributeError:'module' object has no attribute 'Model'
If I comment out the djangotoolbox import, I get the following :
AttributeError: 'module' object has no attribute 'ListField'
What am I doing wrong here? I can't seem to find any documention as to how to go about using ListField in django-nonrel. Is that because it is supposed to really obvious?
Your imports are smashing each other:
from django.db import models
from djangotoolbox import *
The second import will replace the django.db models with djangotoolbox' empty models module. Using from X import * is a terrible idea in general in Python and produces confusing results like these.
If you're looking to use ListField from djangotoolbox, use:
from djangotoolbox import fields
and refer to the ListField class as fields.ListField.
OK, here is what I did to be able to use ListFields. MyClass the equivalent to your Example class and AnotherClass is the same as your Choice_examples. What I describe will allow you to use ListFields in the admin interface and your self implemented views.
I'll start from the beginning
This is what what my model looks like
class MyClass(models.Model):
field = ListField(models.ForeignKey(AnotherClass))
I wanted to be able to use the admin interface to create/edit instances of this model using a multiple select widget for the list field. Therefore, I created some custom classes as follows
class ModelListField(ListField):
def formfield(self, **kwargs):
return FormListField(**kwargs)
class ListFieldWidget(SelectMultiple):
pass
class FormListField(MultipleChoiceField):
"""
This is a custom form field that can display a ModelListField as a Multiple Select GUI element.
"""
widget = ListFieldWidget
def clean(self, value):
#TODO: clean your data in whatever way is correct in your case and return cleaned data instead of just the value
return value
These classes allow the listfield to be used in the admin. Then I created a form to use in the admin site
class MyClassForm(ModelForm):
def __init__(self, *args, **kwargs):
super(MyClasstForm,self).__init__(*args, **kwargs)
self.fields['field'].widget.choices = [(i.pk, i) for i in AnotherClass.objects.all()]
if self.instance.pk:
self.fields['field'].initial = self.instance.field
class Meta:
model = MyClass
After having done this I created a admin model and registered it with the admin site
class MyClassAdmin(admin.ModelAdmin):
form = MyClassForm
def __init__(self, model, admin_site):
super(MyClassAdmin,self).__init__(model, admin_site)
admin.site.register(MyClass, MyClassAdmin)
This is now working in my code. Keep in mind that this approach might not at all be well suited for google_appengine as I am not very adept at how it works and it might create inefficient queries an such.
I don't know, but try with:
class Choice_examples(models.Model):
name = models.CharField(max_length='30')
def __unicode__(self):
return u'%s' % (self.name)
class Example(models.Model):
some_choices = models.ListField(Choice_examples)
notes = models.CharField(max_length='20')
updated_at = models.DateTimeField(auto_now=True)
def __unicode__(self):
return u'%s' % (self.notes)
Looks like the answer is that you cannot pass an object into fields.ListField.
I have ditched trying to work with ListField as documentation is limited and my coding skills aren't at a level for me to work it out.
Anyone else coming across a similar problem, you should consider create a new model to map the ManyToMany relationships. And if the admin view is important, you should look into the following to display the ManyToMany table inline with any given admin view:
http://docs.djangoproject.com/en/1.2/ref/contrib/admin/#s-working-with-many-to-many-models

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