SQL Server query for next row value where previous row value - sql-server

Question

This query gives me Event values from 1 to 20 within an hour, how to add to that if a consecutive Event value is >=200 as well?
SELECT ID, count(Event) as numberoftimes
FROM table_name
WHERE Event >=1 and Event <=20
GROUP BY ID, DATEPART(HH, AtHour)
HAVING DATEPART(HH, AtHour) <= 1
ORDER BY ID desc
In this dummy 24h table:
+----+-------+--------+
| ID | Event | AtHour |
+----+-------+--------+
| 1 | 1 | 11:00 |
| 1 | 4 | 11:01 |
| 1 | 1 | 11:02 |
| 1 | 20 | 11:03 |
| 1 | 200 | 11:04 |
| 1 | 1 | 13:00 |
| 1 | 1 | 13:05 |
| 1 | 2 | 13:06 |
| 1 | 500 | 13:07 |
| 1 | 39 | 13:10 |
| 1 | 50 | 13:11 |
| 1 | 2 | 13:12 |
+----+-------+--------+
I would like to select IDs with Event with values with range between 1 and 20 followed immediately by value greater than or equal to 200 within an hour.
Expected result should be something like that:
+----+--------+
| ID | AtHour |
+----+--------+
| 1 | 11 |
| 1 | 13 |
| 2 | 11 |
| 2 | 14 |
| 3 | 09 |
| 3 | 12 |
+----+--------+
or just how many times it has happened for unique ID instead of which hour.
Please excuse me I am still rusty with post formatting!

Answer 1

CREATE TABLE data (Id INT, Event INT, AtHour SMALLDATETIME);
INSERT data (Id, Event, AtHour) VALUES
(1,1,'2017-03-16 11:00:00'),
(1,4,'2017-03-16 11:01:00'),
(1,1,'2017-03-16 11:02:00'),
(1,20,'2017-03-16 11:03:00'),
(1,200,'2017-03-16 11:04:00'),
(1,1,'2017-03-16 13:00:00'),
(1,1,'2017-03-16 13:05:00'),
(1,2,'2017-03-16 13:06:00'),
(1,500,'2017-03-16 13:07:00'),
(1,39,'2017-03-16 13:10:00')
;
; WITH temp as (
SELECT rownum = ROW_NUMBER() OVER (PARTITION BY id ORDER BY AtHour)
, *
FROM data
)
SELECT a.id, DATEPART(HOUR, a.AtHour) as AtHour, COUNT(*) AS NumOfPairs
FROM temp a JOIN temp b ON a.rownum = b.rownum-1
WHERE a.Event BETWEEN 1 and 20 AND b.Event >= 200
AND DATEDIFF(MINUTE, a.AtHour, b.AtHour) <= 60
GROUP BY a.id, DATEPART(HOUR, a.AtHour)
;