Bash script to iterate over directories and create subdirectory - arrays

Question

I have the following code which creates an array and iterate over a directory and create a subdirectory under each of the element of an array.
#!/bin/bash
cd /var/www
dirs=$(find * -maxdepth 0 -type d)
for dir in "${dirs[#]}"; do
echo $dir
mkdir $dir/backups
done
While it echo's all the directories, it creates a directory only on the last element of the array. What can be the issue?

Answer 1

If you are on bash 4.4 particularly , you can use the readarray feature like bellow. Also using -maxdepth 0 seems not a good option - you probably need to use -maxdepth 1.
#!/bin/bash
cd /var/www
readarray -t -d'' dirs < <$(find . -maxdepth 1 -type d -print0)
for dir in "${dirs[#]}"; do
echo $dir
mkdir $dir/backups
done
But in case you can do the whole thing just with find and mkdir -v (verbose):
$ find . -maxdepth 1 -type d -name 'a*'
./appsfiles
$ find . -maxdepth 1 -type d -name 'a*' -exec mkdir -v {}/backup \;
mkdir: created directory './appsfiles/backup'
Using mkdir -v you get verbose messages from mkdir and you can skip the echo.
If you need the echo anyway, you can do it like:
$ find . -maxdepth 1 -type d -name 'a*' -exec bash -c 'echo $0 && mkdir -v $0/backup' {} \;
./appsfiles
mkdir: created directory './appsfiles/backup'

Answer 2

The issue the array initialization - change it to:
dirs=($(find * -maxdepth 0 -type d))
However, the above statement can be problematic if you have directories that have white spaces in them.
You can use a simple glob instead - it handles white spaces too:
cd /var/www
dirs=(*/)
for dir in "${dirs[#]}"; do
: your code
done