I have some sample data in snowflake as follows;
created_at
----------
2022-06-10T18::35::57
2022-06-10T18::35::57
The datatype of this column is VARCHAR(16777216), I am trying to filter for the rows with date June 10,2022. Here is my query;
select *
from table
where to_date(created_at) = date('2022-06-10', 'yyyy-mm-dd');
But this gives me following error; Date '2022-06-10T18::35::57' is not recognized. If we replace to_date by try_to_date then we get 0 rows. Unfortunately I can't go to backend and change the properties of the table. Therefore, I need to resort to sql datetime functions.
Can I please get help here, on how to fix above errors? thanx
Using LEFT to get date part:
where to_date(LEFT(created_at, 10), 'YYYY-MM-DD') = date('2022-06-10', 'YYYY-MM-DD');
There are two issues here -
1 - It is not a date but a timestamp
2 - usage of '::' rather then standard ':' in time portion
Below will not work as its not a date -
with date_cte(created_at) as
(select * from values
('2022-06-10T18::35::57'),
('2022-06-10T18::35::57'))
select to_date('2022-06-10T18::35::57') from date_cte;
100040 (22007): Date '2022-06-10T18::35::57' is not recognized
Using timestamp will not work too due to '::' in time portion
with date_cte(created_at) as
(select * from values
('2022-06-10T18::35::57'),
('2022-06-10T18::35::57'))
select to_timestamp('2022-06-10T18::35::57','yyyy-mm-dd"T"hh24:mi:ss') from date_cte;
100096 (22007): Can't parse '2022-06-10T18::35::57' as timestamp with format 'yyyy-mm-dd"T"hh24:mi:ss'
Below takes care of both -
with date_cte(created_at) as
(select * from values
('2022-06-10T18::35::57'),
('2022-06-10T18::35::57'))
select to_timestamp('2022-06-10T18::35::57','YYYY-MM-DD"T"HH24::MI::SS') from date_cte;
TO_TIMESTAMP('2022-06-10T18::35::57','YYYY-MM-DD"T"HH24::MI::SS')
2022-06-10 18:35:57.000
2022-06-10 18:35:57.000
Now to compare - just convert in desired format using to_char -
with date_cte(created_at) as
(select * from values
('2022-06-10T18::35::57'),
('2022-06-10T18::35::57'))
select * from date_cte
where to_char(to_timestamp('2022-06-10T18::35::57','YYYY-MM-DD"T"HH24::MI::SS'),'yyyy-mm-dd')='2022-06-10';
CREATED_AT
2022-06-10T18::35::57
2022-06-10T18::35::57
One possible way is to do this:
SELECT *
FROM table
WHERE CAST(SUBSTRING(created_at, 0, 11) as date) = '2022-06-10'
Table is having the column as ret_period and contains varchar datatype. I'm trying to write the query for converting the datatype of column from varchar to date datatype .but it is throwing an error as Conversion failed when converting date and/or time from character string.
Can any one please let me know how to resolve this issue!
below is the sample data of column.
ret_period
012018
012019
012020
You could transform the string to a format that can be converted/casted to a DATE.
select *
, TRY_CAST(CONCAT(RIGHT(ret_period, 4),'-',LEFT(ret_period, 2),'-01') AS DATE) AS ret_date
from (values
('012018'),
('012019'),
('012020')
) q(ret_period)
Note however, that the yyyyMMDD format should be a safer than yyyy-MM-DD, since it doesn't depend on the language when casting it to a DATETIME.
Or use the DATEFROMPARTS function
select *
, DATEFROMPARTS(RIGHT(ret_period, 4), LEFT(ret_period, 2), 1) AS ret_date
from (values
('012018'),
('012019'),
('012020')
) q(ret_period)
ret_period
ret_date
012018
2018-01-01
012019
2019-01-01
012020
2020-01-01
I have a date time column in sql DB - named check_time. I want to write a select query where this check_time should be equals to today's date (no need to consider what time is. Only need to check current date).
For example check_time in table is inserted as 03/08/2017 12:00:00.000 AM.
I have written like below
SELECT * FROM time_details
WHERE check_time = DATEADD(day, DATEDIFF(day,0,GETDATE()),0)
But it returns nothing.
This is the correct syntax:
SELECT * FROM time_details where (DATEDIFF(d, check_time, GETDATE()) = 0)
Just CAST the today's date to DATE.
Query
select * from time_details
where check_time = cast(getdate() as date);
Try with
SELECT * FROM time_details where DATE(check_time) =CURDATE()
The DATE function is going to extract just the date from you datetime field while the CURDATE is returning the current date.
Check with the sql query
SELECT * FROM time_details where DATE(check_time)=DATE(NOW())
this should work
SELECT * FROM time_details where check_time =convert(varchar, getdate(), 101)
SELECT CONVERT(datetime,'17/05/2015 22:15:00',103)
output:
2015-05-17 22:15:00.000
I want include 2 column is Date+Time
Example: Colunm Date and Time
**Date** **Time**
17/05/2015 22:15:00
but Error Query
SELECT CONVERT(datetime,[Date]+' '+[Time],103) FROM LPTables
Conversion failed when converting date and/or time from character string.
Just add the time portion to the date portion:
SELECT DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
FROM LPTables
This will give you accuracy to the millisecond.
Just enclose your columns with ().
SELECT CONVERT(datetime,([Date]+' '+[Time]),103) FROM LPTables
WHERE ISNULL([Date],'')!='' AND ISNULL([Time],'')!=''
Sample :
in MySQL
select * from record where register_date like '2009-10-10%'
What is the syntax in SQL Server?
You could use the DATEPART() function
SELECT * FROM record
WHERE (DATEPART(yy, register_date) = 2009
AND DATEPART(mm, register_date) = 10
AND DATEPART(dd, register_date) = 10)
I find this way easy to read, as it ignores the time component, and you don't have to use the next day's date to restrict your selection. You can go to greater or lesser granularity by adding extra clauses, using the appropriate DatePart code, e.g.
AND DATEPART(hh, register_date) = 12)
to get records made between 12 and 1.
Consult the MSDN DATEPART docs for the full list of valid arguments.
There's no direct support for LIKE operator against DATETIME variables, but you can always cast the DATETIME to a VARCHAR:
SELECT (list of fields) FROM YourTable
WHERE CONVERT(VARCHAR(25), register_date, 126) LIKE '2009-10-10%'
Check the MSDN docs for a complete list of available "styles" in the CONVERT function.
Marc
If you do that, you are forcing it to do a string conversion. It would be better to build a start/end date range, and use:
declare #start datetime, #end datetime
select #start = '2009-10-10', #end = '2009-11-10'
select * from record where register_date >= #start
and register_date < #end
This will allow it to use the index (if there is one on register_date), rather than a table scan.
You can use CONVERT to get the date in text form. If you convert it to a varchar(10), you can use = instead of like:
select *
from record
where CONVERT(VARCHAR(10),register_date,120) = '2009-10-10'
Or you can use an upper and lower boundary date, with the added advantage that it could make use of an index:
select *
from record
where '2009-10-10' <= register_date
and register_date < '2009-10-11'
Unfortunately, It is not possible to compare datetime towards varchar using 'LIKE'
But the desired output is possible in another way.
select * from record where datediff(dd,[record].[register_date],'2009-10-10')=0
You can also use convert to make the date searchable using LIKE. For example,
select convert(VARCHAR(40),create_date,121) , * from sys.objects where convert(VARCHAR(40),create_date,121) LIKE '%17:34%'
Try this
SELECT top 10 * from record WHERE IsActive = 1
and CONVERT(VARCHAR, register_date, 120) LIKE '2020-01%'
I am a little late to this thread but in fact there is direct support for the like operator in MS SQL server.
As documented in LIKE help if the datatype is not a string it is attempted to convert it to a string. And as documented in cast\convert documentation:
default datetime conversion to string is type 0 (,100) which is mon dd
yyyy hh:miAM (or PM).
If you have a date like this in the DB:
2015-06-01 11:52:59.057
and you do queries like this:
select * from wws_invoice where invdate like 'Jun%'
select * from wws_invoice where invdate like 'Jun 1%'
select * from wws_invoice where invdate like 'Jun 1 %'
select * from wws_invoice where invdate like 'Jun 1 2015:%'
select * from wws_invoice where invdate like 'Jun ? 2015%'
...
select * from wws_invoice where invdate like 'Jun 1 2015 11:52AM'
you get that row.
However, this date format suggests that it is a DateTime2, then documentation says:
21 or 121 -- ODBC canonical (with milliseconds) default for time,
date, datetime2, and datetimeoffset. -- yyyy-mm-dd hh:mi:ss.mmm(24h)
That makes it easier and you can use:
select * from wws_invoice where invdate like '2015-06-01%'
and get the invoice record. Here is a demo code:
DECLARE #myDates TABLE (myDate DATETIME2);
INSERT INTO #myDates (myDate)
VALUES
('2015-06-01 11:52:59.057'),
('2015-06-01 11:52:59.054'),
('2015-06-01 13:52:59.057'),
('2015-06-01 14:52:59.057');
SELECT * FROM #myDates WHERE myDate LIKE '2015-06-01%';
SELECT * FROM #myDates WHERE myDate LIKE '2015-06-01 11%';
SELECT * FROM #myDates WHERE myDate LIKE '2015-06-01 11:52:59%';
SELECT * FROM #myDates WHERE myDate LIKE '2015-06-01 11:52:59.054%';
Doing datetime searches in SQL server without any conversion to string has always been problematic. Getting each date part is an overkill (which unlikely would use an index). Probably a better way when you don't use string conversion would be to use range checks. ie:
select * from record
where register_date >= '20091010' and register_date < '20091011';
The LIKE operator does not work with date parts like month or date but the DATEPART operator does.
Command to find out all accounts whose Open Date was on the 1st:
SELECT *
FROM Account
WHERE DATEPART(DAY, CAST(OpenDt AS DATE)) = 1`
*CASTING OpenDt because it's value is in DATETIME and not just DATE.
There is a very flaky coverage of the LIKE operator for dates in SQL Server. It only works using American date format. As an example you could try:
... WHERE register_date LIKE 'oct 10 2009%'
I've tested this in SQL Server 2005 and it works, but you'll really need to try different combinations. Odd things I have noticed are:
You only seem to get all or nothing for different sub fields within the date, for instance, if you search for 'apr 2%' you only get anything in the 20th's - it omits 2nd's.
Using a single underscore '_' to represent a single (wildcard) character does not wholly work, for instance, WHERE mydate LIKE 'oct _ 2010%' will not return all dates before the 10th - it returns nothing at all, in fact!
The format is rigid American: 'mmm dd yyyy hh:mm'
I have found it difficult to nail down a process for LIKEing seconds, so if anyone wants to take this a bit further, be my guest!
Hope this helps.
I solved my problem that way. Thank you for suggestions for improvements.
Example in C#.
string dd, mm, aa, trc, data;
dd = nData.Text.Substring(0, 2);
mm = nData.Text.Substring(3, 2);
aa = nData.Text.Substring(6, 4);
trc = "-";
data = aa + trc + mm + trc + dd;
"Select * From bdPedidos Where Data Like '%" + data + "%'";
I realise this an old question, but a lot of the answers here don't give a SARGable answer here, nor cover parmetrisation.
First off, you are far better off using >= and < logic. For the date you want, then that would look like this:
SELECT {Your Columns}
FROM dbo.record
WHERE register_date >= '20091010'
AND register_date < '20091011';
This'll include every time value on 2009-10-10, including the stroke of midnight on the day, and a nanosecond prior to 2009-10-11.
Often, however, you'll be parametrising your query, so instead what you can do is use DATEADD to add a day to the second clause:
DECLARE #DateParam date = '20091010';
SELECT {Your Columns}
FROM dbo.record
WHERE register_date >= #DateParam
AND register_date < DATEADD(DAY,1,#DateParam);
This maintains SARGability and means that any indexes on register_date can be used.