I have the following ajax code that makes a POST request for a blob to the server,and prints the returned data.
function upload(blob){
var formData = new FormData();
formData.append('file', blob);
$.ajax({
url: "http://custom-url/record.php",
type: 'POST',
data: formData,
contentType: false,
processData: false,
success: function(data) {
console.log(data);
}
});
}
How can I do the same thing in AngularJS?
Instead of appending the blob to FormData, it is more efficient to send the blob directly as the base64 encoding of the FormData API has an extra 33% overhead.
var config = { headers: { 'Content-Type': undefined } };
$http.post(url, blob, config)
.then(function (response) {
var data = response.data;
var status = response.status;
var statusText = response.statusText;
var headers = response.headers;
var config = response.config;
console.log("Success", status);
return response;
}).catch(function (errorResponse) {
console.log("Error", errorResponse.status);
throw errorResponse;
});
It as important to set the content type header to undefined so that the XHR send method can set the content type header. Otherwise the AngularJS framework will override with content type application/json.
For more information, see AngularJS $http Service API Reference.
Related
unable to send file with angular post call
I am trying to post .mp4 file with some data through ionic 1 with angular 1. While posting through POSTMAN it is fine and working. I am getting Success = false in my application.
in POSTMAN, no headers and data is bellow,
Service url with POST request http://services.example.com/upload.php
body in form data
j_id = 4124, type = text
q_id = 6, type = text
u_id = 159931, type = text
file = demo.mp4, type = file
in my app:
$rootScope.uploadQuestion = function () {
var form = new FormData();
form.append("j_id", "4124");
form.append("q_id", "6");
form.append("u_id", "159931");
form.append("file", $rootScope.videoAns.name); //this returns media object which contain all details of recorded video
return $http({
method: 'POST',
headers: { 'Content-Type': 'multipart/form-data' }, // also tried with application/x-www-form-urlencoded
url: 'http://services.example.com/upload.php',
// url: 'http://services.example.com/upload.php?j_id=4124&q_id=8&u_id=159931&file='+$rootScope.videoAns.fullPath,
// data: "j_id=" + encodeURIComponent(4124) + "&q_id=" + encodeURIComponent(8) + "&u_id=" + encodeURIComponent(159931) +"&file=" + encodeURIComponent($rootScope.videoAns),
data: form,
cache: false,
timeout: 300000
}).success(function (data, status, headers, config) {
if (status == '200') {
if (data.success == "true") {
alert('uploading...');
}
}
}).error(function (data, status, headers, config) {
});
}
RECOMMENDED: POST Binary Files Directly
Posting binary files with multi-part/form-data is inefficient as the base64 encoding adds an extra 33% overhead. If the server API accepts POSTs with binary data, post the file directly:
function upload(url, file) {
if (file.constructor.name != "File") {
throw new Error("Not a file");
}
var config = {
headers: {'Content-Type': undefined},
transformRequest: []
};
return $http.post(url, file, config)
.then(function (response) {
console.log("success!");
return response;
}).catch(function (errorResponse) {
console.error("error!");
throw errorResponse;
});
}
Normally the $http service encodes JavaScript objects as JSON strings. Use transformRequest: [] to override the default transformation.
DEMO of Direct POST
angular.module("app",[])
.directive("selectNgFiles", function() {
return {
require: "ngModel",
link: postLink
};
function postLink(scope, elem, attrs, ngModel) {
elem.on("change", function(event) {
ngModel.$setViewValue(elem[0].files);
});
}
})
.controller("ctrl", function($scope, $http) {
var url = "//httpbin.org/post";
var config = {
headers: { 'Content-type': undefined }
};
$scope.upload = function(files) {
var promise = $http.post(url,files[0],config);
promise.then(function(response){
$scope.result="Success "+response.status;
}).catch(function(errorResponse) {
$scope.result="Error "+errorRespone.status;
});
};
})
<script src="//unpkg.com/angular/angular.js"></script>
<body ng-app="app" ng-controller="ctrl">
<input type="file" select-ng-files ng-model="files">
<br>
<button ng-disabled="!files" ng-click="upload(files)">
Upload file
</button>
<pre>
Name={{files[0].name}}
Type={{files[0].type}}
RESULT={{result}}
</pre>
</body>
Posting with 'Content-Type': 'multipart/form-data'
When posting data using the FormData API, it is important to set the content type to undefined:
function uploadQuestion(file) {
var form = new FormData();
form.append("j_id", "4124");
form.append("q_id", "6");
form.append("u_id", "159931");
form.append("file", file); //this returns media object which contain all details of recorded video
return $http({
method: 'POST',
headers: { 'Content-Type': undefined ̶'̶m̶u̶l̶t̶i̶p̶a̶r̶t̶/̶f̶o̶r̶m̶-̶d̶a̶t̶a̶'̶ }, // also tried with application/x-www-form-urlencoded
url: 'http://services.example.com/upload.php',
data: form,
̶c̶a̶c̶h̶e̶:̶ ̶f̶a̶l̶s̶e̶,̶
timeout: 300000
̶}̶)̶.̶s̶u̶c̶c̶e̶s̶s̶(̶f̶u̶n̶c̶t̶i̶o̶n̶ ̶(̶d̶a̶t̶a̶,̶ ̶s̶t̶a̶t̶u̶s̶,̶ ̶h̶e̶a̶d̶e̶r̶s̶,̶ ̶c̶o̶n̶f̶i̶g̶)̶ ̶{̶
}).then(function(response) {
var data = response.data;
var status = response.status;
if (status == '200') {
console.log("Success");
}
̶}̶)̶.̶e̶r̶r̶o̶r̶(̶f̶u̶n̶c̶t̶i̶o̶n̶ ̶(̶d̶a̶t̶a̶,̶ ̶s̶t̶a̶t̶u̶s̶,̶ ̶h̶e̶a̶d̶e̶r̶s̶,̶ ̶c̶o̶n̶f̶i̶g̶)̶ ̶{̶
}).catch(function(response) {
console.log("ERROR");
//IMPORTANT
throw response;
});
}
When the XHR API send method sends a FormData Object, it automatically sets the content type header with the appropriate boundary. When the $http service overrides the content type, the server will get a content type header without the proper boundary.
I have webApi return me a blob file that I have to display.
how can I know what type is the blob that I got? It could be anything, pdf, doc, jpeg etc.
$http({ method: 'GET', url: (itemsUrl), responseType: 'arraybuffer' }).then(function mySucces(res) {
var byteArray = res.data;
byteArray = new Uint8Array(byteArray);
var file = new Blob([byteArray], { type: '??????' });
var fileURL = URL.createObjectURL(file);
window.open(fileURL);
});
or, how can I open blob in a new window without know the file type?
Use response.headers() to get the content type:
var config = { responseType: 'blob' };
$http.get(itemsUrl, config).then(function onSuccess(response) {
var blob = response.data;
var contentType = response.headers("content-type");
var fileURL = URL.createObjectURL(blob);
window.open(fileURL);
});
Consider using 'blob' as the responseType.
For more information, see MDN XHR responseType.
I have form with textarea and:
<input type="file" name="files" file-input="files" multiple />
How to serialiaze this form and send AJAX with textarea value and files using:
I tried this way:
$scope.send = function(data) {
var path = $filter('sprintf')(paths.comment.send, $scope.issue.project.id, $scope.issue.campaign.id, $scope.issue.id);
var formData = new FormData();
angular.forEach($scope.files, function(value, key) {
formData.append(key, value);
});
formData .append('body', $scope.comment.body);
$http({
method: 'POST',
url: path,
transformRequest: angular.identity,
headers: {
'Content-Type': 'multipart/form-data',
'X-CSRF-Token': $('meta[name=csrf-token]').attr('content')
},
data: formData
})
.then(function(data) {
console.log(data);
},
function(response) {
console.log(response);
});
};
But it does not work
When sending a formData object created by the FormData API, it is important to set the content type header to undefined.
var formData = new FormData();
angular.forEach($scope.files, function(value, key) {
formData.append(key, value);
});
formData .append('body', $scope.comment.body);
$http({
method: 'POST',
url: path,
transformRequest: angular.identity,
headers: {
//'Content-Type': 'multipart/form-data',
//USE content type undefined
'Content-Type': undefined,
'X-CSRF-Token': $('meta[name=csrf-token]').attr('content')
},
data: formData
})
Normally the $http service sets the content type to application/json. When the content type header is undefined, the content type is set by the XHR send method.
In this case the XHR API needs to include the encapsulation boundary with the content type header. It "does not work" with formData objects when the XHR API is forced to use a content type header without an encapsulation boundary.
I tried to use POST to send some bytes using ArrayBuffer, but it seems that the request payload is always empty. Here's some code snippet:
var buffer = new ArrayBuffer(10);
var dataView = new DataView(buffer);
dataView.setInt32(0, 0x1234ABCD);
var request = {
method: 'POST',
url: 'url',
headers: {'Content-Type': 'application/octet-stream'},
data: buffer,
responseType: 'arraybuffer'
};
$http(request)
.success(function(data, status, headers, config) { ... })
.error(function(data, status, headers, config) { ... });
As I commented, to send ArrayBuffer, you need to use XHR2 directly (seems AngularJs doesn't support it). Here's some code of how to do it:
var buffer = new ArrayBuffer(10);
var dataView = new DataView(buffer);
dataView.setInt32(0, 0x1234ABCD);
var xhr = new XMLHttpRequest();
xhr.open('POST', 'url', true);
xhr.onload = function(e) {
console.log('data received');
};
xhr.send(buffer);
More details about XHR2: http://www.html5rocks.com/en/tutorials/file/xhr2/#toc-send-string, hope this could help for someone who's also puzzled :)
I have an API endpoint to which I must send a multipart HTTP request, composed of two parts, file (a file system file) and data (a JSON object).
After some research I found out how to do a multipart request in AngularJS:
$http({
method: 'POST',
url: url,
headers: {
'Content-Type': 'multipart/form-data'
},
data: {
data: model,
file: file
},
transformRequest: customFormDataObject
});
1) The customFormDataObject function initially had this form:
customFormDataObject formDataObject = function (data, headersGetter) {
var fd = new FormData();
angular.forEach(data, function (value, key) {
fd.append(key, value);
});
var headers = headersGetter();
delete headers['Content-Type'];
return fd;
};
The outcome of this implementation is that the individual parts of the request do not have a contentType set to them.
2) After reading some more (https://stackoverflow.com/a/24535293/689216) I tried using a Blob for this, the customFormData object looking like this (a bit of a mess, basically the first part will be of contentType application/json, the second one image/png):
customFormDataObject = function (data, headersGetter) {
var fd = new FormData();
var contentType = 'application/json';
angular.forEach(data, function (value, key) {
fd.append(key, new Blob([JSON.stringify(value)], {
type: contentType
}));
contentType = 'image/png';
});
var headers = headersGetter();
delete headers['Content-Type'];
return fd;
};
This second approach sets the correct contentType for each part of the request, but it does not set any values for the parts.
Basically what happens is with 1) the correct values are set in the multiparts, but the contentType's are not set. With 2) the contentType's are set, but not the values for the multiparts.
Am I missing something? Is this functionality not supposed to work like this?
Thanks!
The easiest way to upload files in Angular:
var fd = new FormData();
fd.append('file', file);
fd.append('data', 'string');
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(){
})
.error(function(){
});
Absolutely essential are the following two properties of the config object:
transformRequest: angular.identity
overrides Angular's default serialization, leaving our data intact.
headers: {'Content-Type': undefined }
lets the browser detect the correct Content-Type as multipart/form-data, and fill in the correct boundary.
Nothing else worked for me! Courtesy of Lady Louthan's wonderful blogpost.
Have you tried something like this:
$httpProvider.defaults.transformRequest = function(data) {
if (data === undefined){
return data;
}
var formData = new FormData();
for (var key in data){
if(typeof data[key] == 'object' && !(data[key] instanceof File)){
formData.append(key, JSON.stringify(data[key]));
}else{
formData.append(key, data[key]);
}
}
return formData;
};
I just solve exactly the same problem.
After some tests, I had this situation that you've described:
Basically what happens is with 1) the correct values are set in the multiparts, but the contentType's are not set. With 2) the contentType's are set, but not the values for the multiparts.
To fix this problem, I had to use Blob and Post Ajax instead of $http Post.
It seems that $http does not work correctly in this case.
Code:
var formData = new FormData();
var blobId = new Blob([100], { 'type':'text/plain' });
formData.append('testId', blobId);
var blobImage = fileService.base64ToBlob(contentToDecode, 'image/jpeg');
formData.append('file', blobImage, 'imagem' + (i + 1) + '.jpg');
Request:
$.ajax({
url: url,
data: formData,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(response) {
deferred.resolve(response);
$rootScope.requestInProgress = false;
},
error: function(error) {
deferred.reject(error);
$rootScope.requestInProgress = false;
}
});
You can use https://github.com/danialfarid/ng-file-upload/.
In this file uploader, there is a provision for sending the file and data (in JSON format) separately as you mentioned in your question above.
For Ex:-
var upload = $upload.upload({
url: url,
file: file,
method: 'POST' or 'PUT', default POST,
headers: {'Content-Type': 'multipart/form-data'}, // only for html5
fileName: 'doc.jpg',
fileFormDataName: 'myFile',
data: {'data': model}
});
In the above code, you can send either a POST or PUT request with 'multipart/form-data', file and data object as JSON separately.
For more information you can visit the above link and look at the ReadMe.md of the plug-in.
I know that my approach is a bit different from the one that you are currently following, but the objective is same.
what i did to solve this was.
var formData = new FormData(document.getElementById('myFormId'));
then in my service
var deferred = $q.defer();
$http.post('myurl', formData, {
cache: false,
contentType: false,
processData: false,
})
.success(function (response) {
deferred.resolve(response);
})
.error(function (reject) {
deferred.reject(reject);
});
return deferred.promise;