Wager must be less than balance to continue C - c

Question

So I am working on a game of craps, one aspect of the game is that the wager must be less than or equal to balance to continue (so you don't bet more than you have). Right now I have my full game I am working on, but that would be too much code to post, so I wrote out essentially what I am trying to do.
The code I am posting assumes it is a loss, but it does not subtract correctly for some reason. And in my actual game, it ignores the while function completely ie. if my balance is 20 and I bet 22 it gives me -2. I can not figure out how to make this work correctly..
#include<stdio.h>
int main(void)
{
double balance = 0.0, wager = 0.0;
balance = get_balance();
wager = get_wager();
checking_wager(balance, wager);
loss(balance, wager);
return 0;
}
double get_balance(void)
{
double balance = 0.0;
balance = printf("Enter your balance: ");
scanf("%lf", &balance);
return balance;
}
double get_wager(void)
{
double wager = 0.0;
wager = printf("Enter your wager: \n");
scanf("%lf", &wager);
return wager;
}
double checking_wager(double balance, double wager)
{
while (wager > balance)
{
printf("The wager is invalid\n");
wager = get_wager();
}
return 0;
}
double loss(double balance, double wager)
{
balance -= wager;
printf("Balance: %.2f", balance);
return balance;
}
If anyone has any suggestions on how I can make this work, I would really appreciate it. Thanks :)

Answer 1

I reformat you code, now it should work.
int main(void)
{
double balance = 0.0, wager = 0.0;
balance = get_balance();
wager = get_wager();
checking_wager(balance, &wager);
loss(balance, wager);
return 0;
}
double get_balance(void)
{
double balance = 0.0;
balance = printf("Enter your balance: ");
scanf("%lf", &balance);
return balance;
}
double get_wager(void)
{
double wager = 0.0;
wager = printf("Enter your wager: \n");
scanf("%lf", &wager);
return wager;
}
double checking_wager(double balance, double *wager)
{
while (*wager > balance)
{
printf("The wager is invalid\n");
*wager = get_wager();
}
return 0;
}
double loss(double balance, double wager)
{
balance -= wager;
printf("Balance: %.2f", balance);
return balance;
}
The changes I've done, is first replaced the returntypes form
int
to
double
Second and more importent, I've change the second paramter int this function
int checking_wager(double balance, double wager)
to a pointer to double
double checking_wager(double balance, double *wager)
The reason this, to return the new wager from the function.

Answer 2

The problem occurs from the definition of your checking_wager() function.
So from my assumption, you passed two parameters which are balance and wager, and hopefully to reinput value of wager in case it's greater than balance.
However, your code doesn't do like you'd intended, because you defined the wager as a new local variable, which doesn't share the same location as wager from main function.
So, the easiest fix is to change checking_wager()'s wager into a pointer, so that it can refers and changes value from main()'s wager.
int checking_wager(double balance, double *wager)
{
while (*wager > balance)
{
printf("The wager is invalid\n");
*wager = get_wager();
}
return 0;
}
So, to call it from main function, you can basically give main function's wager pointer into the checking_wager() function.
checking_wager(balance, &wager);
Hopefully that will helps.