I have a bunch of records in SQL SERVER and i'm having an issue with one of the fields.
The datatype is datetime. The system was only inserting a date with no time in it, so '1/2/2017' - so when it was inserted in SQL SERVER it would show only as 1/2/2017 00:00:00. Now, what I'm trying to do is to display it just as it is saved in the DB.
I query the DB and display it like this...
If Not IsDBNull(dr("ReceivedOn")) Then
txtReceivedOn.Text = Format(dr("ReceivedOn"), "MM/dd/yyyy hh:mm tt")
End If
The mask on my masked textbox is liek this.....
00/00/0000 90:00 aa
When it does get displayd in the masked textbox is shows the date and 12:00 AM
1/2/2017 12:00:00 AM
Is there to get rid of it, and only show 0's instead of a incorrect time? However I'd like to only see a 12 hr time rather than 24.
You need to change the format specifier for hours from hh to HH
If Not IsDBNull(dr("ReceivedOn")) Then
txtReceivedOn.Text = Format(dr("ReceivedOn"), "MM/dd/yyyy HH:mm tt")
End If
On MSDN at the DateTime Custom Date and Time strings you can read
The "HH" custom format specifier (plus any number of additional "H"
specifiers) represents the hour as a number from 00 through 23; that
is, the hour is represented by a zero-based 24-hour clock that counts
the hours since midnight. A single-digit hour is formatted with a
leading zero.
Note that, with this format, the tt is meaningless.
Related
My date is stored in a type date column in dd/mm/yyyy format. I want to print the date in yyyymmdd format.
When i used the following formula
tonumber(totext(db.colname,'YYYYMMDD'))
It gave me a "the string is non numeric" error when previewing the report.
Secondly,
My time is stored in a string column in 12 hour format. I want to display it as hh24miss format.
How do i do that ?
First of all, you should NOT store dates/times as text in your database.
Use the apropriate datatype of your DBMS.
Otherwise you will very likely have further problems because of this.
When you've changed the datatype you could just drag&drop the database-field inside your report and use the formatting options of Crystal Reports to get the desired format.
If for any reason (I doubt there's a good one) you can't change the datatype, use the following formula.
ToText(Date({db.colname}), "yyyyMMdd")
This formula converts the string to a date and then formats the date with yyyyMMdd format.
Notice the uppercase M which is used for the month. Lowercase m is used for minutes.
Below sql showing 57 hours, But,it's 44 hrs. How can i solve.
SELECT DATEDIFF(Hour,'2018-11-20 2:26:38.000','2018-11-22 11:00:29.367')
Use 24 hr format in both dates
SELECT DATEDIFF(Hour,'2018-11-20 14:26:38.000','2018-11-22 11:00:29.367')
Not prefixing the hours to be two digits looks like it could be the issue, making it unambiguously in the afternoon gives your result.
/*------------------------
SELECT DATEDIFF(Hour,'2018-11-20 14:26:38.000','2018-11-22 11:00:29.367')
------------------------*/
45
You're default Date Time format is probably 12 hour, and "2:…" is being treated as pm.
Using two digits for the hour should help.
/*------------------------
SELECT DATEDIFF(Hour,'2018-11-20 02:26:38.000','2018-11-22 11:00:29.367')
------------------------*/
57
(SQL Server has a lot of backward compatibility which may be triggered is the input is not precisely formatted, ISO Date/Time formats always use two digits for hours, minutes, and seconds.)
If you are using a client (rather than fixed code in a Stored Proc/Function/Trigger/…) parameterising your queries avoids this issue: pass data as Date-Time type directly without any need to convert into a string.
I would like to keep my dates as datetime datatype by also be in MM/DD/YYYY format. I know how to do this by converting them to a varchar, but want to keep the datetime format. Can anyone help with this?
Currently I have tried
SELECT CONVERT(datetime, GETDATE(), 101)
which is not working...
There is a basic misunderstanding in your question. Repeat after me: Datetimes don't have a format.
It helps if you think of them as just an array of seven integers (year, month, day, hours, minutes, seconds, milliseconds) with certain constraints. That's not in any way accurate, but it helps to get the notion out of your head that something akin to 12/31/2015 is stored in your database.
Datetimes only get a format when (implicitly or explicitly) being converted to strings. You already know how to set the format when explicitly converting to string, now all that is left to do is to find the implicit conversion that is obviously bothering you and replace it with an explicit one.
Date and datetime Values stored in the database are NOT in any recognizable format. They are stored in binary (1s and 0s) in a proprietary format where one part represents the number of days since a defined reference date (1 jan 1900) in SQL server). and the other part represents the time portion of the value. (in sql server, its the number of 1/300ths of a second since midnight.)
ALL formatting of dates and date times, no matter what format you wish for, is done only after the values have been extracted from the database, before you see them on screen, in whatever application you are using.
You can find all the formats that the SQL Server convert function can use on this MSDN Convert Link
I am using server time for one of my process. For that I am taking date and time using postgresql. The time format I want is 2 digit day,month,hour,minute,second and 4 digit year (eg: 05/01/2015 16:05:30). I am using SELECT to_char(now()::timestamp,'DD/MM/YYYY HH24:MI:SS') I want to make sure that the number of digits for each will be as like I want. Because its very important for my processing. I have refered the following link Link. There it is saying, day of month (01-31) for DD's decription. Is there any possibility to get day as 1 instide of 01
Feel safe.
The table ad your link (http://www.postgresql.org/docs/9.4/static/functions-formatting.html#FUNCTIONS-FORMATTING-DATETIME-TABLE)
is right.
Numbers in date converted with to_char, are 0 padded.
Is there any possibility to get day as 1 instide of 01
You can use regular expression to remove leading 0:
select regexp_replace(to_char(now()::timestamp,'DD/MM/YYYY HH24:MI:SS'), '^0(\d)', '\1', 'g');
How will I convert date in the format Sat Mar 29 00:00:00 EST 1975 to datetime in TSQL?
I get the date in this format from an old table which defined the date of birth column as NVARCHAR and stores the data as Mon Jun dd hh:mm:ss GMT yyyy format. I need to read another table which has the dob in datetime using this value.
So basically I want to convert, say Sat Mar 29 00:00:00 EST 1975 to 1975-03-29 00:00:00.000
Is there a way in T-SQL to do this conversion? I tried the CONVERT function, but I am unable to locate the correct 'style' to use.
Examining the data format, it appears to be a fixed length string.
The first portion is the day of week, which can be discarded as it isn't needed for parsing. Next you have the month and day information, which we need. After that is the time, which can be retained or discarded depending on whether you want a date or datetime as output.
Since you are looking for a date of birth, the time zone information can most likely be safely discarded.
Finally, there is the year.
If we eliminate the day of week and the time zone, sql server will parse the rest of the string with no problem.
I recommend cast(substring(#difficultTime,5,7) + substring(#difficultTime,25,4) as date), where #difficulteTime is the column name you are converting.
If you wanted to retain the time information, the following format will work cast(substring(#difficultTime,5,16) + substring(#difficultTime,25,4) as datetime)
This assumes that your strings will be of a fixed length. The first conversion shown eliminates the day of week, the time, and the time zone from the string, leaving a parseable date.
The second conversion eliminates the day of week and the time zone, leaving a parseable datetime.