C - [Error] invalid conversion from 'char' to 'const char*' [-fpermissive] - c

Question

There's a bunch of threads about C++, but I'm stuck with regular C here and can't find an answer anywhere.
#include <stdio.h>
#include <conio.h>
#include <string.h>
main() {
char word[26], letter, reverse[26], length;
printf("Enter word: ");
scanf("%s", &word);
length=strlen(word);
for (int i=0; i<=length; i++) {
letter = word[length-i];
strcpy(reverse, letter);
printf("%c\n", reverse);
}
getch();
}
I'm getting errors as the title states.
13 25 ~ [Error] invalid conversion from 'char' to 'const char*'
[-fpermissive]
51 18 C:\Program Files (x86)\Dev-Cpp\MinGW64\x86_64-w64-mingw32\include\string.h [Note]
initializing argument 2 of 'char* strcpy(char*, const char*)'
What the code should do is reverse the written word and type it out line by line, by each last letter.
Etc. - Type in "food" and the program should output:
d
od
ood
food
I know I messed up somewhere in the 'letter', but I have no clue how to fix it.
Also I'm trying to avoid using std::, personal prefrence.

Answer 1

Try this:
int main( void ) {
char word[26], reverse[26];
int length, i;
printf("Enter word: ");
scanf("%s", &word);
length=strlen(word);
for (i=0; i<length; i++) {
reverse[i] = word[length - i - 1];
}
/* Put \0 to terminate the string */
reverse[length]='\0';
printf("%s\n", reverse);
}
Note that in the for loop you have to use only < and not <= because you'll get out of bounds of the array (negative index) and you have to put the \0 terminator to terminate your reverse string. You don't need letter and btw strcpy works not with single chars, since a single char is not a string (because of the missing string terminator (\0)).
Edit:
int main( void ) {
char word[26], reverse[26];
int length, i;
printf("Enter word: ");
scanf("%s", &word);
length=strlen(word);
for (i=0; i<length; i++) {
reverse[i] = word[length - i - 1];
/* Put \0 to terminate the string */
reverse[i + 1]='\0';
printf("%s\n", reverse);
}
}

Answer 2

Problems:
You pass the address of an array to scanf, rather than passing the array.
You don't copy the null termination correctly.
strcat must have null terminated strings as parameters, it cannot work with single characters. You don't need to use it here anyway.
Fixed program:
#include <stdio.h>
#include <string.h>
int main (void)
{
char word[26];
char reverse[26];
size_t length;
size_t i;
printf("Enter word: ");
scanf("%s", word);
length=strlen(word);
for (i=0; i<length; i++)
{
reverse[i] = word[length-i-1];
}
reverse[i] = '\0';
printf("Reverse: %s\n", reverse);
return 0;
}
Output:
Enter word: stackoverflow
Reverse: wolfrevokcats

Answer 3

There are a bunch of errors in the code. The one that you are asking about is due to the fact that you are passing a char (i.e. the variable letter) rather than the address (i.e. &letter)
This "fix" would cause the compiler error to disappear, however it would cause another one to appear. This is because we'd now be passing a pointer to a char rather than a pointer to a terminated string.
for (i=0 ; i<26 ; i++)
reverse[i] = word[25-i];

Answer 4

Here i have to pass in strcat(char * s1, const char * s2);
Here reverse is the cha* and &letter is const char*.
Check out this one.
this is the code what you want as output.
int main()
{
char word[26], letter, length;
int n, c, d;
char reverse[26];
char temp[26];
printf("Enter word: ");
scanf("%s", word);
length=strlen(word);
for (int i=0; i<=length; i++)
{
letter = word[length-i];
strcat(reverse, &letter);
n = strlen(reverse);
for (c = n - 1, d = 0; c >= 0; c--, d++)
temp[d] = reverse[c];
temp[d] = '\0';
printf("%s\n", temp);
}
return 0;
}
Output :-